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Aadarsh
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dw:1337842674096:dw

Aadarsh
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@Ishaan94 , @apoorvk , @Mani_Jha please help me. Still 3 more questions there.

apoorvk
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This seems okay  not even indeterminate to me  is it? Should be '0'.

Aadarsh
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No @apoorvk bhai, answer is 1.

Aadarsh
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Please explain with all steps.

apoorvk
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'0' ke neighbourhood ki values pe kya hoga or zero pe kya hoga?
waise ye limit less than '0' par defined nahi hogi..

Aadarsh
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Didn't understand apoorv bhai. Please explain with steps. I think we can differentiate and simplify the expression before substityuting.

apoorvk
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cos(0) = 1.
baaki sab 0.

apoorvk
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Why would you differentiate this? This is perfectly okay  is this indeterminate in any way?

Aadarsh
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Then , how is the answer 1? now how to proceed?

apoorvk
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Answer '1' nahi hai! Why do you go by the answer  it may be a printing error...
Apply the limits, what else?
sin(0) = 0
cos(0) = 1
and use the rest..

Aadarsh
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Then u mean answer is 0 only?

apoorvk
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Waise, x> 0 pe sirf RHL limit exist haregi, LHL is not defined.
Yeah, '0' according to me.
@Ishaan94 what say?

Aadarsh
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@Mani_Jha please say ur opinion also.

apoorvk
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man, have some confidence on your own knowledge  what should the answer according to your work?

Aadarsh
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0

apoorvk
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*answer be^

apoorvk
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Yeah, so that's it!

Aadarsh
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But , its a FIITJEE Package question. Some guys r getting answer as 1. I wonder how!!!!!!!!!!!!!

Aadarsh
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@Mani_Jha bhai may have done this question in his Phase 1 in FIITJEE.

Aadarsh
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@FoolForMath , @satellite73 , @shivam_bhalla please try.