## Aadarsh 3 years ago Evaluate.

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3. apoorvk

This seems okay - not even indeterminate to me - is it? Should be '0'.

No @apoorvk bhai, answer is 1.

6. apoorvk

'0' ke neighbourhood ki values pe kya hoga or zero pe kya hoga? waise ye limit less than '0' par defined nahi hogi..

Didn't understand apoorv bhai. Please explain with steps. I think we can differentiate and simplify the expression before substityuting.

8. apoorvk

cos(0) = 1. baaki sab 0.

9. apoorvk

Why would you differentiate this? This is perfectly okay - is this indeterminate in any way?

Then , how is the answer 1? now how to proceed?

11. apoorvk

Answer '1' nahi hai! Why do you go by the answer - it may be a printing error... Apply the limits, what else? sin(0) = 0 cos(0) = 1 and use the rest..

Then u mean answer is 0 only?

13. apoorvk

Waise, x-> 0 pe sirf RHL limit exist haregi, LHL is not defined. Yeah, '0' according to me. @Ishaan94 what say?

@Mani_Jha please say ur opinion also.

15. apoorvk

man, have some confidence on your own knowledge - what should the answer according to your work?

0

17. apoorvk

18. apoorvk

Yeah, so that's it!

But , its a FIITJEE Package question. Some guys r getting answer as 1. I wonder how!!!!!!!!!!!!!

@Mani_Jha bhai may have done this question in his Phase 1 in FIITJEE.

@FoolForMath , @satellite73 , @shivam_bhalla please try.

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