anonymous
  • anonymous
Evaluate.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1337842674096:dw|
anonymous
  • anonymous
@Ishaan94 , @apoorvk , @Mani_Jha please help me. Still 3 more questions there.
apoorvk
  • apoorvk
This seems okay - not even indeterminate to me - is it? Should be '0'.

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More answers

anonymous
  • anonymous
No @apoorvk bhai, answer is 1.
anonymous
  • anonymous
Please explain with all steps.
apoorvk
  • apoorvk
'0' ke neighbourhood ki values pe kya hoga or zero pe kya hoga? waise ye limit less than '0' par defined nahi hogi..
anonymous
  • anonymous
Didn't understand apoorv bhai. Please explain with steps. I think we can differentiate and simplify the expression before substityuting.
apoorvk
  • apoorvk
cos(0) = 1. baaki sab 0.
apoorvk
  • apoorvk
Why would you differentiate this? This is perfectly okay - is this indeterminate in any way?
anonymous
  • anonymous
Then , how is the answer 1? now how to proceed?
apoorvk
  • apoorvk
Answer '1' nahi hai! Why do you go by the answer - it may be a printing error... Apply the limits, what else? sin(0) = 0 cos(0) = 1 and use the rest..
anonymous
  • anonymous
Then u mean answer is 0 only?
apoorvk
  • apoorvk
Waise, x-> 0 pe sirf RHL limit exist haregi, LHL is not defined. Yeah, '0' according to me. @Ishaan94 what say?
anonymous
  • anonymous
@Mani_Jha please say ur opinion also.
apoorvk
  • apoorvk
man, have some confidence on your own knowledge - what should the answer according to your work?
anonymous
  • anonymous
0
apoorvk
  • apoorvk
*answer be^
apoorvk
  • apoorvk
Yeah, so that's it!
anonymous
  • anonymous
But , its a FIITJEE Package question. Some guys r getting answer as 1. I wonder how!!!!!!!!!!!!!
anonymous
  • anonymous
@Mani_Jha bhai may have done this question in his Phase 1 in FIITJEE.
anonymous
  • anonymous
@FoolForMath , @satellite73 , @shivam_bhalla please try.

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