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Aadarsh

  • 2 years ago

Evaluate.

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  1. Aadarsh
    • 2 years ago
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    |dw:1337842674096:dw|

  2. Aadarsh
    • 2 years ago
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    @Ishaan94 , @apoorvk , @Mani_Jha please help me. Still 3 more questions there.

  3. apoorvk
    • 2 years ago
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    This seems okay - not even indeterminate to me - is it? Should be '0'.

  4. Aadarsh
    • 2 years ago
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    No @apoorvk bhai, answer is 1.

  5. Aadarsh
    • 2 years ago
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    Please explain with all steps.

  6. apoorvk
    • 2 years ago
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    '0' ke neighbourhood ki values pe kya hoga or zero pe kya hoga? waise ye limit less than '0' par defined nahi hogi..

  7. Aadarsh
    • 2 years ago
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    Didn't understand apoorv bhai. Please explain with steps. I think we can differentiate and simplify the expression before substityuting.

  8. apoorvk
    • 2 years ago
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    cos(0) = 1. baaki sab 0.

  9. apoorvk
    • 2 years ago
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    Why would you differentiate this? This is perfectly okay - is this indeterminate in any way?

  10. Aadarsh
    • 2 years ago
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    Then , how is the answer 1? now how to proceed?

  11. apoorvk
    • 2 years ago
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    Answer '1' nahi hai! Why do you go by the answer - it may be a printing error... Apply the limits, what else? sin(0) = 0 cos(0) = 1 and use the rest..

  12. Aadarsh
    • 2 years ago
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    Then u mean answer is 0 only?

  13. apoorvk
    • 2 years ago
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    Waise, x-> 0 pe sirf RHL limit exist haregi, LHL is not defined. Yeah, '0' according to me. @Ishaan94 what say?

  14. Aadarsh
    • 2 years ago
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    @Mani_Jha please say ur opinion also.

  15. apoorvk
    • 2 years ago
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    man, have some confidence on your own knowledge - what should the answer according to your work?

  16. Aadarsh
    • 2 years ago
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    0

  17. apoorvk
    • 2 years ago
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    *answer be^

  18. apoorvk
    • 2 years ago
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    Yeah, so that's it!

  19. Aadarsh
    • 2 years ago
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    But , its a FIITJEE Package question. Some guys r getting answer as 1. I wonder how!!!!!!!!!!!!!

  20. Aadarsh
    • 2 years ago
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    @Mani_Jha bhai may have done this question in his Phase 1 in FIITJEE.

  21. Aadarsh
    • 2 years ago
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    @FoolForMath , @satellite73 , @shivam_bhalla please try.

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