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ugh vectors :/
well i fail at almost anything related w/ 3d so can't help u here :(
it's k. thanxx anyway.
dear can u attach graph of this ?
I dnt hav it. I hav only the question. Am sorry. :(
ok let's try to solve it step by step together .
I drew this part. Bt where do v place k?
i just think about it .
do the alpha beta has special meaning or they are just coefficient ?
they are just coefficients.
ok we suppose that its in the shape like this
can u plzz show me the next step if u dnt mind.
dear i'm thinking .
dear for writing the plane we need a point and a line which cross the plane am i right ?
u mean for writing the eqn of the plane? bt v can write it if v knw the position vectors of thr three points isnt it?
yes so u know out and in multiple .
if u multiple out and b and like this for others plane u have the line and u have the point .
sorry I didnt get u?
take a look at it : http://en.wikipedia.org/wiki/Cross_product
@Callisto dear i need help here
I hav studied cross product. I dnt get where u apply it here. Am so sorry for disturbing u. Can u plzz explain it a bit more.
i'm not sure i ask a friend for help but what i said is this :
in our question we have a b c vectors , for each plane if u cross product both of them u get the line ortoghonal to the plane and u have the point i mean a1 b1 and the other
i tried bt nt getting t. can u plzz help me dear?
u know , i'm not sure about the solution .
oh k. Am sorry.
i's so sri because i can't help u . but think about my idea . what if we suppose our space with 3 vector a b c instead i j k ? could we find out the answer ?
let me try and see.
dear is it a special tetrahedron ? i mean symmetric or ortoghonal ?
if it has any special feature we can use them .
It is nt given. :(
i'm not good at english but is it like this ? http://en.wikipedia.org/wiki/File:Tetrahedron_flat.svg
i'm so sri .
No problem. Bigg thanxxx for trying to help me.
I wrote the equations of planes as follows. |dw:1337970519951:dw||dw:1337970602748:dw|
I wrote it so cos the equation of a plane through three points is |dw:1337970955268:dw| were r is p.v of any point R on the required plane, a,b and c are p.v of the given points A,B, and C.
Am I right @timo86m
seems right use it to prove those things it says.
bt that's the place I am stuck.
I got the answer for the first part.:0
for 1 you can just take vector D to D1 Use vector addition and it will equal RHS
this is a tough one :) lol
I did it in this way. Let the position vector of D1 with respect to D be d1. Since D1 lies in the plane AB|dw:1337972129746:dw| and since DD1//DK|dw:1337972217587:dw||dw:1337972258266:dw||dw:1337972326958:dw||dw:1337972383792:dw| Such a lengthy method.
@timo86m if u dnt mind can u help me to solve the third and fourth part.
oh Sorry I dont think i can
it's k. I got an answer. If I make an adjustment to that I am getting it right. Bt am nt sure if I am right. Anyways thanxxx a lot for coming to the rescue.
LOL I did nothing :P It was all you smartypants
you did it all :) really
thanxxx for the medal.:)
I am proud of you :)
Bring on another q :D Make it easier this time please :P