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Why tanx≠−2
?????

Please give reason:)

\[\tan \frac{1}{2}x=\frac{1-\cos x}{\sin x}\]

What is this?

\[\tan(\frac{1}{2}\cos^{-1} \frac{3}{5})=\frac{1-\frac{3}{5}}{\frac{4}{5}}=\frac{1}{2}\]

but answer is given "2" in the question.

\(\frac 12 \) is the correct answer.

k! thanx to everyone:)

but in the question; is the solution wrong anywhere?
Plz tell:)

In the componendo dividendo step, the final answer is \(\tan^2 x =\frac 1 4 \)

k!k! I got that thanx a lot:)

I want to know why answer is not -1/2

First u see full cmments

I didn't understand ur 1st line:\

Plz help:)

k! thanx I got it:)