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maheshmeghwal9Best ResponseYou've already chosen the best response.1
Why tanx≠−2 ?????
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
Please give reason:)
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
@apoorvk & @Callisto & @shivam_bhalla Plz help:)
 one year ago

MertsjBest ResponseYou've already chosen the best response.2
\[\tan \frac{1}{2}x=\frac{1\cos x}{\sin x}\]
 one year ago

MertsjBest ResponseYou've already chosen the best response.2
\[\tan(\frac{1}{2}\cos^{1} \frac{3}{5})=\frac{1\frac{3}{5}}{\frac{4}{5}}=\frac{1}{2}\]
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
but answer is given "2" in the question.
 one year ago

FoolForMathBest ResponseYou've already chosen the best response.2
\(\frac 12 \) is the correct answer.
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
k! thanx to everyone:)
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
but in the question; is the solution wrong anywhere? Plz tell:)
 one year ago

FoolForMathBest ResponseYou've already chosen the best response.2
In the componendo dividendo step, the final answer is \(\tan^2 x =\frac 1 4 \)
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
This is how @Mertsj got that and it is right \[\large \tan x/2 = \frac{\sin x/2 }{\cos x/2} = {\sqrt{1cosx \over 2} \over \sqrt{1+cosx \over 2}}\] \[\large \tan x/2 = {\sqrt{1cosx } \over \sqrt{1+cosx}} * \frac{\sqrt{1+cosx}}{\sqrt{1+cosx}}\] \[\large \tan x/2= {sinx \over 1+\cos x }\]
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
k!k! I got that thanx a lot:)
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
I want to know why answer is not 1/2
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
First u see full cmments
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.0
It seems that trying to attack it your way, and ending with a \(\tan^2\), there's no real easy way to see that it can't be 1/2. However, doing it mertsj's method, only outputs the single solution.
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
I didn't understand ur 1st line:\
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.0
I'm going off of what foolformath said, "In the componendo dividendo step, the final answer is \(\tan^2(x)=\frac{1}{4}\)." I can't see a good reason why you need to exclude the possible answer of 1/2 here. Also, \(\sin(\cos^{1}(3/5))\) should have two solutions. Namely, 4/5 and 4/5. So you should still get both solutions.
 one year ago

maheshmeghwal9Best ResponseYou've already chosen the best response.1
k! thanx I got it:)
 one year ago
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