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maheshmeghwal9
 4 years ago
Inverse Trigonometric Function Question:
Please Help:)
maheshmeghwal9
 4 years ago
Inverse Trigonometric Function Question: Please Help:)

This Question is Closed

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1Why tanx≠−2 ?????

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1Please give reason:)

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1@apoorvk & @Callisto & @shivam_bhalla Plz help:)

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[\tan \frac{1}{2}x=\frac{1\cos x}{\sin x}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[\tan(\frac{1}{2}\cos^{1} \frac{3}{5})=\frac{1\frac{3}{5}}{\frac{4}{5}}=\frac{1}{2}\]

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1but answer is given "2" in the question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\(\frac 12 \) is the correct answer.

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1k! thanx to everyone:)

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1but in the question; is the solution wrong anywhere? Plz tell:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In the componendo dividendo step, the final answer is \(\tan^2 x =\frac 1 4 \)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is how @Mertsj got that and it is right \[\large \tan x/2 = \frac{\sin x/2 }{\cos x/2} = {\sqrt{1cosx \over 2} \over \sqrt{1+cosx \over 2}}\] \[\large \tan x/2 = {\sqrt{1cosx } \over \sqrt{1+cosx}} * \frac{\sqrt{1+cosx}}{\sqrt{1+cosx}}\] \[\large \tan x/2= {sinx \over 1+\cos x }\]

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1k!k! I got that thanx a lot:)

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1I want to know why answer is not 1/2

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1First u see full cmments

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.0It seems that trying to attack it your way, and ending with a \(\tan^2\), there's no real easy way to see that it can't be 1/2. However, doing it mertsj's method, only outputs the single solution.

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1I didn't understand ur 1st line:\

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.0I'm going off of what foolformath said, "In the componendo dividendo step, the final answer is \(\tan^2(x)=\frac{1}{4}\)." I can't see a good reason why you need to exclude the possible answer of 1/2 here. Also, \(\sin(\cos^{1}(3/5))\) should have two solutions. Namely, 4/5 and 4/5. So you should still get both solutions.

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1k! thanx I got it:)
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