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AEB047

  • 2 years ago

How do you factor x^2-4x+24

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  1. Mertsj
    • 2 years ago
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    It won't factor by the usual methods since there are not 2 numbers whose product is 24 and whose sum is -4

  2. JADA-SHA88
    • 2 years ago
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    can't be factored. use the quadratic formula which is x= -b + or - the square root of b^2 - 4ac all over 2a a= the x^2 which is 1 b=the -4 c=24 hope that helped :)

  3. AEB047
    • 2 years ago
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    I don't know what to do, though.

  4. Mertsj
    • 2 years ago
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    So if you want to factor it, you could use the quadratic formula and find the roots. Then using the roots, you could write the factors.

  5. AEB047
    • 2 years ago
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    I think that helped

  6. Mertsj
    • 2 years ago
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    Are you sure you copied it right?

  7. AEB047
    • 2 years ago
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    Yes

  8. Mertsj
    • 2 years ago
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    \[x=\frac{4\pm \sqrt{16-4(24)}}{2}=\frac{4\pm \sqrt{-80}}{2}=\frac{4\pm4\sqrt{5}i}{2}=2\pm2\sqrt{5}i\]

  9. Mertsj
    • 2 years ago
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    So the factors must by: \[[x-(2+2\sqrt{5}i)][x-(2-2\sqrt{5}i)]\]

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