Here's the question you clicked on:
AEB047
How do you factor x^2-4x+24
It won't factor by the usual methods since there are not 2 numbers whose product is 24 and whose sum is -4
can't be factored. use the quadratic formula which is x= -b + or - the square root of b^2 - 4ac all over 2a a= the x^2 which is 1 b=the -4 c=24 hope that helped :)
I don't know what to do, though.
So if you want to factor it, you could use the quadratic formula and find the roots. Then using the roots, you could write the factors.
Are you sure you copied it right?
\[x=\frac{4\pm \sqrt{16-4(24)}}{2}=\frac{4\pm \sqrt{-80}}{2}=\frac{4\pm4\sqrt{5}i}{2}=2\pm2\sqrt{5}i\]
So the factors must by: \[[x-(2+2\sqrt{5}i)][x-(2-2\sqrt{5}i)]\]