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Mertsj Group TitleBest ResponseYou've already chosen the best response.0
It won't factor by the usual methods since there are not 2 numbers whose product is 24 and whose sum is 4
 2 years ago

JADASHA88 Group TitleBest ResponseYou've already chosen the best response.0
can't be factored. use the quadratic formula which is x= b + or  the square root of b^2  4ac all over 2a a= the x^2 which is 1 b=the 4 c=24 hope that helped :)
 2 years ago

AEB047 Group TitleBest ResponseYou've already chosen the best response.0
I don't know what to do, though.
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
So if you want to factor it, you could use the quadratic formula and find the roots. Then using the roots, you could write the factors.
 2 years ago

AEB047 Group TitleBest ResponseYou've already chosen the best response.0
I think that helped
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Are you sure you copied it right?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
\[x=\frac{4\pm \sqrt{164(24)}}{2}=\frac{4\pm \sqrt{80}}{2}=\frac{4\pm4\sqrt{5}i}{2}=2\pm2\sqrt{5}i\]
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
So the factors must by: \[[x(2+2\sqrt{5}i)][x(22\sqrt{5}i)]\]
 2 years ago
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