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maheshmeghwal9
 4 years ago
Plz help:)
maheshmeghwal9
 4 years ago
Plz help:)

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maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1why b>1? Why not b>0?

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1in the attachment.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0holymoly that's one big pic.

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1should I make it small?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0b>1 because the negatitve exponents will take care of values for b between 0 and 1... that make sense?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it is defined for b>1

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1didn't understand ya main concept:(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let's do this then...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1337931693406:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you see why b doesn't have to be defined between 0 and 1?

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1but what is the problem for 0<b<1.Isn't it defined for exponential f(x) too. Since it also gives a value which is defined as "x". in ur exampledw:1337932045573:dw All r defined:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there's no problem... with 0<b<1.. it's just not needed...

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1k! did it have no need due to log?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0notice the base of logs CAN have a base between 0 and 1 also but could be transformed and written with a base bigger than 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is there a reason why this was bumped?

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1Hi @experimentX I couldn't understand the my basic questiom.Plz help:)

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1I don't understand the reason why b should be greater than 1, but b should always be greater than zero ... for that expression to be defined

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1ya I also think this:)

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1\[ \log_b x = \frac{\log_k x}{\log_k b}\] Also between 01 \( \log_k b < 1\)

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1I had this problem while studying Logarithmic Differentiation. I think there is some connection between b>1 & Logarithmic Differentiation.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1\[ \frac{d}{dx} (\log_b x) = \frac{1}{x \ln b}\] At b=1, \( \ln b =0\) is zero ... so it is undefined, so is the above expression, but for (0,1) the expression is defined http://www.wolframalpha.com/input/?i=plot+y+%3D+d%2Fdx+log [0.5%2C+x]+from+0+to+10 http://www.wolframalpha.com/input/?i=plot+y+%3D+log [0.5%2C+x]+from+0+to+10

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1So indirectly do u want to say that b>1 is right there! Please tell:)

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1No ... i think i got it wrong it somewhere check this out http://www.wolframalpha.com/input/?i=plot+y+%3D+log [x%2C+2]+from+0+to+10

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1it seems i was right ... but somewhat not accurate http://www.wolframalpha.com/input/?i=plot+y+%3D+log [x%2C+5]+from+0+to+2

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1K! I understood that.I also think u r right.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1at b=0, \( \log_b x\) is zero ... and \( dy/dx\) is indeterminate

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1ow I have some clues. I will think on that point more. Thanx for clues:)

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=plot+y+%3D+d%2Fdx%28log [b%2C+x]%29+from+b%3D0+to+2 check this out

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1Hmm! I checked that:)

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1b cannot be 1 and less than zero ... that's all

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1k! but can be (0,1)

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1so we again came there; where was our doubt:)

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1this is a very confusing state; isn't it?

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1What should we do now? by the way I have asked this to my sir also online, but they will receive question & give answer after almost a week!!!

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1what was the original question??

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1Pardon me what do u want?; that is a video cutted part. I had this problem while studying video:)

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1Oh ... i thought this is a part of the problem where you got stuck!!

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1so is there anyone in OS who can solve our problem:)

maheshmeghwal9
 4 years ago
Best ResponseYou've already chosen the best response.1k! np:) Thanx for ur cooperation. When my problem is solved, i'll tell u too.
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