Plz help:)

- maheshmeghwal9

Plz help:)

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

hey mahesh

- maheshmeghwal9

##### 1 Attachment

- maheshmeghwal9

why b>1?
Why not b>0?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- maheshmeghwal9

in the attachment.

- anonymous

holymoly that's one big pic.

- maheshmeghwal9

should I make it small?

- anonymous

sawrite....

- maheshmeghwal9

##### 1 Attachment

- anonymous

b>1 because the negatitve exponents will take care of values for b between 0 and 1...
that make sense?

- anonymous

so it is defined for b>1

- maheshmeghwal9

didn't understand ya main concept:(

- anonymous

let's do this then...

- anonymous

|dw:1337931693406:dw|

- anonymous

do you see why b doesn't have to be defined between 0 and 1?

- maheshmeghwal9

but what is the problem for 0

- anonymous

there's no problem... with 0

- maheshmeghwal9

k! did it have no need due to log?

- anonymous

notice the base of logs CAN have a base between 0 and 1 also but could be transformed and written with a base bigger than 1

- anonymous

is there a reason why this was bumped?

- maheshmeghwal9

Hi @experimentX I couldn't understand the my basic questiom.Plz help:)

- experimentX

I don't understand the reason why b should be greater than 1,
but b should always be greater than zero ... for that expression to be defined

- maheshmeghwal9

ya I also think this:)

- experimentX

\[ \log_b x = \frac{\log_k x}{\log_k b}\]
Also between 0-1 \( \log_k b < 1\)

- maheshmeghwal9

ok!

- maheshmeghwal9

I had this problem while studying Logarithmic Differentiation.
I think there is some connection between b>1 & Logarithmic Differentiation.

- experimentX

\[ \frac{d}{dx} (\log_b x) = \frac{1}{x \ln b}\]
At b=1, \( \ln b =0\) is zero ... so it is undefined, so is the above expression, but for (0,1) the expression is defined
http://www.wolframalpha.com/input/?i=plot+y+%3D+d%2Fdx+log[0.5%2C+x]+from+0+to+10
http://www.wolframalpha.com/input/?i=plot+y+%3D+log[0.5%2C+x]+from+0+to+10

- maheshmeghwal9

So indirectly do u want to say that b>1 is right there!
Please tell:)

- experimentX

No ... i think i got it wrong it somewhere
check this out
http://www.wolframalpha.com/input/?i=plot+y+%3D+log[x%2C+2]+from+0+to+10

- maheshmeghwal9

k! thanx alot:)

- experimentX

wait ...

- maheshmeghwal9

k!

- experimentX

it seems i was right ... but somewhat not accurate
http://www.wolframalpha.com/input/?i=plot+y+%3D+log[x%2C+5]+from+0+to+2

- maheshmeghwal9

K! I understood that.I also think u r right.

- experimentX

at b=0, \( \log_b x\) is zero ... and \( dy/dx\) is indeterminate

- maheshmeghwal9

ok! thanx.

- maheshmeghwal9

ow I have some clues.
I will think on that point more.
Thanx for clues:)

- maheshmeghwal9

ow=now

- experimentX

http://www.wolframalpha.com/input/?i=plot+y+%3D+d%2Fdx%28log[b%2C+x]%29+from+b%3D0+to+2
check this out

- maheshmeghwal9

Hmm! I checked that:)

- experimentX

b cannot be 1 and less than zero ... that's all

- maheshmeghwal9

k! but can be (0,1)

- experimentX

i guessed so ...

- maheshmeghwal9

so we again came there; where was our doubt:)

- maheshmeghwal9

this is a very confusing state; isn't it?

- experimentX

well yes!!

- maheshmeghwal9

What should we do now?
by the way I have asked this to my sir also online, but they will receive question & give answer after almost a week!!!

- experimentX

what was the original question??

- maheshmeghwal9

Pardon me what do u want?;
that is a video cutted part.
I had this problem while studying video:)

- experimentX

Oh ... i thought this is a part of the problem where you got stuck!!

- maheshmeghwal9

so is there anyone in OS who can solve our problem:)

- experimentX

I don't know ...

- maheshmeghwal9

k! np:)
Thanx for ur co-operation.
When my problem is solved, i'll tell u too.

- experimentX

k

Looking for something else?

Not the answer you are looking for? Search for more explanations.