Plz help:)

- maheshmeghwal9

Plz help:)

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- anonymous

hey mahesh

- maheshmeghwal9

##### 1 Attachment

- maheshmeghwal9

why b>1?
Why not b>0?

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## More answers

- maheshmeghwal9

in the attachment.

- anonymous

holymoly that's one big pic.

- maheshmeghwal9

should I make it small?

- anonymous

sawrite....

- maheshmeghwal9

##### 1 Attachment

- anonymous

b>1 because the negatitve exponents will take care of values for b between 0 and 1...
that make sense?

- anonymous

so it is defined for b>1

- maheshmeghwal9

didn't understand ya main concept:(

- anonymous

let's do this then...

- anonymous

|dw:1337931693406:dw|

- anonymous

do you see why b doesn't have to be defined between 0 and 1?

- maheshmeghwal9

but what is the problem for 0

- anonymous

there's no problem... with 0

- maheshmeghwal9

k! did it have no need due to log?

- anonymous

notice the base of logs CAN have a base between 0 and 1 also but could be transformed and written with a base bigger than 1

- anonymous

is there a reason why this was bumped?

- maheshmeghwal9

Hi @experimentX I couldn't understand the my basic questiom.Plz help:)

- experimentX

I don't understand the reason why b should be greater than 1,
but b should always be greater than zero ... for that expression to be defined

- maheshmeghwal9

ya I also think this:)

- experimentX

\[ \log_b x = \frac{\log_k x}{\log_k b}\]
Also between 0-1 \( \log_k b < 1\)

- maheshmeghwal9

ok!

- maheshmeghwal9

I had this problem while studying Logarithmic Differentiation.
I think there is some connection between b>1 & Logarithmic Differentiation.

- experimentX

\[ \frac{d}{dx} (\log_b x) = \frac{1}{x \ln b}\]
At b=1, \( \ln b =0\) is zero ... so it is undefined, so is the above expression, but for (0,1) the expression is defined
http://www.wolframalpha.com/input/?i=plot+y+%3D+d%2Fdx+log[0.5%2C+x]+from+0+to+10
http://www.wolframalpha.com/input/?i=plot+y+%3D+log[0.5%2C+x]+from+0+to+10

- maheshmeghwal9

So indirectly do u want to say that b>1 is right there!
Please tell:)

- experimentX

No ... i think i got it wrong it somewhere
check this out
http://www.wolframalpha.com/input/?i=plot+y+%3D+log[x%2C+2]+from+0+to+10

- maheshmeghwal9

k! thanx alot:)

- experimentX

wait ...

- maheshmeghwal9

k!

- experimentX

it seems i was right ... but somewhat not accurate
http://www.wolframalpha.com/input/?i=plot+y+%3D+log[x%2C+5]+from+0+to+2

- maheshmeghwal9

K! I understood that.I also think u r right.

- experimentX

at b=0, \( \log_b x\) is zero ... and \( dy/dx\) is indeterminate

- maheshmeghwal9

ok! thanx.

- maheshmeghwal9

ow I have some clues.
I will think on that point more.
Thanx for clues:)

- maheshmeghwal9

ow=now

- experimentX

http://www.wolframalpha.com/input/?i=plot+y+%3D+d%2Fdx%28log[b%2C+x]%29+from+b%3D0+to+2
check this out

- maheshmeghwal9

Hmm! I checked that:)

- experimentX

b cannot be 1 and less than zero ... that's all

- maheshmeghwal9

k! but can be (0,1)

- experimentX

i guessed so ...

- maheshmeghwal9

so we again came there; where was our doubt:)

- maheshmeghwal9

this is a very confusing state; isn't it?

- experimentX

well yes!!

- maheshmeghwal9

What should we do now?
by the way I have asked this to my sir also online, but they will receive question & give answer after almost a week!!!

- experimentX

what was the original question??

- maheshmeghwal9

Pardon me what do u want?;
that is a video cutted part.
I had this problem while studying video:)

- experimentX

Oh ... i thought this is a part of the problem where you got stuck!!

- maheshmeghwal9

so is there anyone in OS who can solve our problem:)

- experimentX

I don't know ...

- maheshmeghwal9

k! np:)
Thanx for ur co-operation.
When my problem is solved, i'll tell u too.

- experimentX

k

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