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Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0i don't know how to start..can someone please help..

lalaly
 2 years ago
Best ResponseYou've already chosen the best response.3i am still trying to do it but something is confusing me whats the x?

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0I don't know; I'm confused as well, where did the x come from? lol

lalaly
 2 years ago
Best ResponseYou've already chosen the best response.3lol i did half of the work but got to an equatoin with x in it ...

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0Well, I don't know how to do it; where the x come from? Can you give me a hint how to start?

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0Hm,okay; I will try from that..

lalaly
 2 years ago
Best ResponseYou've already chosen the best response.3sorry:( .. im sure the other people viewing would have an idea

lalaly
 2 years ago
Best ResponseYou've already chosen the best response.3i can do part b xD do u need help with that?

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0Nope, only the first one.

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.1That's a stupid question.

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.1where the 'x' come from in equation 'a'?

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0i don't know that is why I'm lost; or probably there's a mistake :/

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0lol, please delete that inky..

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.1I understand the problem now.

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.1As to how I figured it out, I began by constructing that perpendicular line segment, and then I assumed the statement was true. I found that sin(thetaphi)=sin(angle b), and a sin(b)= that line segment I constructed. Then, sin(phi)=opp/hyp=contructed line segment/(a+something), or (a+something)sin(phi) =a sin(thetaphi) and the only value for something that makes sense is that segment.

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1337941445676:dw a sin(thetaphi)=constructed line segment > let's call that segment length y Then, (a+x) sin(phi)=opp/hyp >opp is segment y, and hyp would be x+a  the only definition of x that works is in my drawing. Thus, (a+x)sin(phi)=(a+x)*(opp/hyp)=(a+x)(y)/(x+a)=y and a sin(thetaphi) is also y, and so we can substitute (y)(y)=0

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.1@lalaly , do you at least understand my explanation?

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.1Max I can get is \[asin(\theta)(x+a)sin(\phi)=0\] assuming x was there dw:1337941920722:dw

inkyvoyd
 2 years ago
Best ResponseYou've already chosen the best response.1@.Sam. , that's what I meant... I'm sure that that is x

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.0First, where did sine come from? I havent done geometry in a while..

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.1I've ended up with another solution \[rcos(90+\phi\theta)(x+r)sin(\phi)=0\]

lalaly
 2 years ago
Best ResponseYou've already chosen the best response.3angle TBO= 180(180theta+phi)=thetaphi \[\frac{(x+a)}{\sin(\theta\phi)}=\frac{a}{\sin \phi}\]\[(x+a)\sin \phi=asin(\theta\phi)\]

lalaly
 2 years ago
Best ResponseYou've already chosen the best response.3so\[asin(\theta\phi)(x+a)\sin \phi=0\]

lalaly
 2 years ago
Best ResponseYou've already chosen the best response.3i assumed that the part of TC that is outside the circle is x ... and it worked!! :D

lalaly
 2 years ago
Best ResponseYou've already chosen the best response.3and then i used the sin rule after finding TBO O is the center

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.1I was using angle JOB lol
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