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Mimi_x3Best ResponseYou've already chosen the best response.0
i don't know how to start..can someone please help..
 one year ago

lalalyBest ResponseYou've already chosen the best response.3
i am still trying to do it but something is confusing me whats the x?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
I don't know; I'm confused as well, where did the x come from? lol
 one year ago

lalalyBest ResponseYou've already chosen the best response.3
lol i did half of the work but got to an equatoin with x in it ...
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
Well, I don't know how to do it; where the x come from? Can you give me a hint how to start?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
Hm,okay; I will try from that..
 one year ago

lalalyBest ResponseYou've already chosen the best response.3
sorry:( .. im sure the other people viewing would have an idea
 one year ago

lalalyBest ResponseYou've already chosen the best response.3
i can do part b xD do u need help with that?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
Nope, only the first one.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
That's a stupid question.
 one year ago

.Sam.Best ResponseYou've already chosen the best response.1
where the 'x' come from in equation 'a'?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
i don't know that is why I'm lost; or probably there's a mistake :/
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
dw:1337940741536:dw
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
lol, please delete that inky..
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
dw:1337940823123:dw
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
I understand the problem now.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
dw:1337940877496:dw
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
As to how I figured it out, I began by constructing that perpendicular line segment, and then I assumed the statement was true. I found that sin(thetaphi)=sin(angle b), and a sin(b)= that line segment I constructed. Then, sin(phi)=opp/hyp=contructed line segment/(a+something), or (a+something)sin(phi) =a sin(thetaphi) and the only value for something that makes sense is that segment.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
dw:1337941268446:dw
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
dw:1337941445676:dw a sin(thetaphi)=constructed line segment > let's call that segment length y Then, (a+x) sin(phi)=opp/hyp >opp is segment y, and hyp would be x+a  the only definition of x that works is in my drawing. Thus, (a+x)sin(phi)=(a+x)*(opp/hyp)=(a+x)(y)/(x+a)=y and a sin(thetaphi) is also y, and so we can substitute (y)(y)=0
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
dw:1337941693329:dw
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
@lalaly , do you at least understand my explanation?
 one year ago

.Sam.Best ResponseYou've already chosen the best response.1
Max I can get is \[asin(\theta)(x+a)sin(\phi)=0\] assuming x was there dw:1337941920722:dw
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.1
@.Sam. , that's what I meant... I'm sure that that is x
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.0
First, where did sine come from? I havent done geometry in a while..
 one year ago

.Sam.Best ResponseYou've already chosen the best response.1
I've ended up with another solution \[rcos(90+\phi\theta)(x+r)sin(\phi)=0\]
 one year ago

lalalyBest ResponseYou've already chosen the best response.3
angle TBO= 180(180theta+phi)=thetaphi \[\frac{(x+a)}{\sin(\theta\phi)}=\frac{a}{\sin \phi}\]\[(x+a)\sin \phi=asin(\theta\phi)\]
 one year ago

lalalyBest ResponseYou've already chosen the best response.3
so\[asin(\theta\phi)(x+a)\sin \phi=0\]
 one year ago

lalalyBest ResponseYou've already chosen the best response.3
i assumed that the part of TC that is outside the circle is x ... and it worked!! :D
 one year ago

lalalyBest ResponseYou've already chosen the best response.3
and then i used the sin rule after finding TBO O is the center
 one year ago

.Sam.Best ResponseYou've already chosen the best response.1
I was using angle JOB lol
 one year ago
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