Geometry Question.

- Mimi_x3

Geometry Question.

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- Mimi_x3

##### 1 Attachment

- Mimi_x3

i don't know how to start..can someone please help..

- lalaly

i am still trying to do it but something is confusing me whats the x?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- Mimi_x3

I don't know; I'm confused as well, where did the x come from? lol

- lalaly

lol i did half of the work but got to an equatoin with x in it ...

- Mimi_x3

Well, I don't know how to do it; where the x come from? Can you give me a hint how to start?

- lalaly

since*

- Mimi_x3

Hm,okay; I will try from that..

- Mimi_x3

thanks anyway

- lalaly

sorry:( .. im sure the other people viewing would have an idea

- lalaly

i can do part b xD do u need help with that?

- Mimi_x3

Nope, only the first one.

- lalaly

ok:)

- inkyvoyd

That's a stupid question.

- inkyvoyd

* problem

- razor99

may i come here

- .Sam.

where the 'x' come from in equation 'a'?

- Mimi_x3

i don't know that is why I'm lost; or probably there's a mistake :/

- inkyvoyd

|dw:1337940741536:dw|

- Mimi_x3

lol, please delete that inky..

- inkyvoyd

|dw:1337940823123:dw|

- inkyvoyd

That's x.

- inkyvoyd

I understand the problem now.

- inkyvoyd

|dw:1337940877496:dw|

- inkyvoyd

As to how I figured it out, I began by constructing that perpendicular line segment, and then I assumed the statement was true. I found that sin(theta-phi)=sin(angle b), and a sin(b)= that line segment I constructed. Then, sin(phi)=opp/hyp=contructed line segment/(a+something), or (a+something)sin(phi) =a sin(theta-phi) and the only value for something that makes sense is that segment.

- inkyvoyd

@Mimi_x3

- inkyvoyd

|dw:1337941268446:dw|

- inkyvoyd

|dw:1337941445676:dw| a sin(theta-phi)=constructed line segment -> let's call that segment length y Then, (a+x) sin(phi)=opp/hyp ->opp is segment y, and hyp would be x+a - the only definition of x that works is in my drawing. Thus, (a+x)sin(phi)=(a+x)*(opp/hyp)=(a+x)(y)/(x+a)=y and a sin(theta-phi) is also y, and so we can substitute (y)-(y)=0

- inkyvoyd

|dw:1337941693329:dw|

- inkyvoyd

@lalaly , do you at least understand my explanation?

- .Sam.

Max I can get is \[asin(\theta)-(x+a)sin(\phi)=0\] assuming x was there |dw:1337941920722:dw|

- inkyvoyd

@.Sam. , that's what I meant... I'm sure that that is x

- Mimi_x3

First, where did sine come from? I havent done geometry in a while..

- .Sam.

I've ended up with another solution \[rcos(90+\phi-\theta)-(x+r)sin(\phi)=0\]

- inkyvoyd

http://www.twiddla.com/847714

- Mimi_x3

I'm lost..

- lalaly

angle TBO= 180-(180-theta+phi)=theta-phi \[\frac{(x+a)}{\sin(\theta-\phi)}=\frac{a}{\sin \phi}\]\[(x+a)\sin \phi=asin(\theta-\phi)\]

- lalaly

so\[asin(\theta-\phi)-(x+a)\sin \phi=0\]

- lalaly

i assumed that the part of TC that is outside the circle is x ... and it worked!! :D

- lalaly

and then i used the sin rule after finding TBO O is the center

- lalaly

and TO=x+a

- lalaly

did u get it @Mimi_x3

- Mimi_x3

yeah; thank you!

- lalaly

:D

- inkyvoyd

@Mimi_x3 , rage

- .Sam.

I was using angle JOB lol

Looking for something else?

Not the answer you are looking for? Search for more explanations.