A community for students.
Here's the question you clicked on:
 0 viewing
Mimi_x3
 4 years ago
Geometry Question.
Mimi_x3
 4 years ago
Geometry Question.

This Question is Closed

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0i don't know how to start..can someone please help..

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.3i am still trying to do it but something is confusing me whats the x?

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0I don't know; I'm confused as well, where did the x come from? lol

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.3lol i did half of the work but got to an equatoin with x in it ...

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0Well, I don't know how to do it; where the x come from? Can you give me a hint how to start?

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0Hm,okay; I will try from that..

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.3sorry:( .. im sure the other people viewing would have an idea

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.3i can do part b xD do u need help with that?

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0Nope, only the first one.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.1That's a stupid question.

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.1where the 'x' come from in equation 'a'?

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0i don't know that is why I'm lost; or probably there's a mistake :/

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0lol, please delete that inky..

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.1I understand the problem now.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.1As to how I figured it out, I began by constructing that perpendicular line segment, and then I assumed the statement was true. I found that sin(thetaphi)=sin(angle b), and a sin(b)= that line segment I constructed. Then, sin(phi)=opp/hyp=contructed line segment/(a+something), or (a+something)sin(phi) =a sin(thetaphi) and the only value for something that makes sense is that segment.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1337941445676:dw a sin(thetaphi)=constructed line segment > let's call that segment length y Then, (a+x) sin(phi)=opp/hyp >opp is segment y, and hyp would be x+a  the only definition of x that works is in my drawing. Thus, (a+x)sin(phi)=(a+x)*(opp/hyp)=(a+x)(y)/(x+a)=y and a sin(thetaphi) is also y, and so we can substitute (y)(y)=0

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.1@lalaly , do you at least understand my explanation?

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.1Max I can get is \[asin(\theta)(x+a)sin(\phi)=0\] assuming x was there dw:1337941920722:dw

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.1@.Sam. , that's what I meant... I'm sure that that is x

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.0First, where did sine come from? I havent done geometry in a while..

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.1I've ended up with another solution \[rcos(90+\phi\theta)(x+r)sin(\phi)=0\]

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.3angle TBO= 180(180theta+phi)=thetaphi \[\frac{(x+a)}{\sin(\theta\phi)}=\frac{a}{\sin \phi}\]\[(x+a)\sin \phi=asin(\theta\phi)\]

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.3so\[asin(\theta\phi)(x+a)\sin \phi=0\]

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.3i assumed that the part of TC that is outside the circle is x ... and it worked!! :D

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.3and then i used the sin rule after finding TBO O is the center

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.1I was using angle JOB lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.