Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Mimi_x3

  • 2 years ago

Geometry Question.

  • This Question is Closed
  1. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i don't know how to start..can someone please help..

  3. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    i am still trying to do it but something is confusing me whats the x?

  4. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know; I'm confused as well, where did the x come from? lol

  5. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    lol i did half of the work but got to an equatoin with x in it ...

  6. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well, I don't know how to do it; where the x come from? Can you give me a hint how to start?

  7. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    since*

  8. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hm,okay; I will try from that..

  9. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks anyway

  10. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    sorry:( .. im sure the other people viewing would have an idea

  11. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    i can do part b xD do u need help with that?

  12. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Nope, only the first one.

  13. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    ok:)

  14. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    That's a stupid question.

  15. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    * problem

  16. razor99
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    may i come here

  17. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    where the 'x' come from in equation 'a'?

  18. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i don't know that is why I'm lost; or probably there's a mistake :/

  19. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1337940741536:dw|

  20. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol, please delete that inky..

  21. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1337940823123:dw|

  22. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    That's x.

  23. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I understand the problem now.

  24. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1337940877496:dw|

  25. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    As to how I figured it out, I began by constructing that perpendicular line segment, and then I assumed the statement was true. I found that sin(theta-phi)=sin(angle b), and a sin(b)= that line segment I constructed. Then, sin(phi)=opp/hyp=contructed line segment/(a+something), or (a+something)sin(phi) =a sin(theta-phi) and the only value for something that makes sense is that segment.

  26. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @Mimi_x3

  27. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1337941268446:dw|

  28. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1337941445676:dw| a sin(theta-phi)=constructed line segment -> let's call that segment length y Then, (a+x) sin(phi)=opp/hyp ->opp is segment y, and hyp would be x+a - the only definition of x that works is in my drawing. Thus, (a+x)sin(phi)=(a+x)*(opp/hyp)=(a+x)(y)/(x+a)=y and a sin(theta-phi) is also y, and so we can substitute (y)-(y)=0

  29. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1337941693329:dw|

  30. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @lalaly , do you at least understand my explanation?

  31. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Max I can get is \[asin(\theta)-(x+a)sin(\phi)=0\] assuming x was there |dw:1337941920722:dw|

  32. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @.Sam. , that's what I meant... I'm sure that that is x

  33. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    First, where did sine come from? I havent done geometry in a while..

  34. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I've ended up with another solution \[rcos(90+\phi-\theta)-(x+r)sin(\phi)=0\]

  35. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    http://www.twiddla.com/847714

  36. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm lost..

  37. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    angle TBO= 180-(180-theta+phi)=theta-phi \[\frac{(x+a)}{\sin(\theta-\phi)}=\frac{a}{\sin \phi}\]\[(x+a)\sin \phi=asin(\theta-\phi)\]

  38. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    so\[asin(\theta-\phi)-(x+a)\sin \phi=0\]

  39. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    i assumed that the part of TC that is outside the circle is x ... and it worked!! :D

  40. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    and then i used the sin rule after finding TBO O is the center

  41. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    and TO=x+a

  42. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    did u get it @Mimi_x3

  43. Mimi_x3
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah; thank you!

  44. lalaly
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 3

    :D

  45. inkyvoyd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @Mimi_x3 , rage

  46. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I was using angle JOB lol

  47. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.