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Qwerty90
What is the length of Segment AB to the nearest tenth of a meter?
\[AB=AD+DB\] \[\cos(60°)=\sin(30°)=\frac{AD}{14}\] \[\sin(60°)=\cos{(30°)}=\frac{DC}{14}\]
Do I then need to use the sin and cosine formula to figure the rest out?
i still cannot see myself how to get DB
what do the first two equal?
actually you can work out angle DCB with a trig identity, because be know two of the sides, and then use another trig identity to find DB
the first two what? @Qwerty90
when you gave those first few ratios.. the AD/14 and DC/14 what do those equal
you dont know the values of sin 30=cos60? you must remember theses if you dont remember you can use a calculator
\[\sin60°=\cos30°\] is a little bit tricker on a calculator, because the value given is irrational but you can square the output 0.86602540... 0.86602540...^2=0.75=3/4 so \[\sin60°=\cos30°= \sqrt{\frac{3}{4}}=\frac{\sqrt3}2\]