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Qwerty90

  • 3 years ago

What is the length of Segment AB to the nearest tenth of a meter?

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  1. Qwerty90
    • 3 years ago
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  2. UnkleRhaukus
    • 3 years ago
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    \[AB=AD+DB\] \[\cos(60°)=\sin(30°)=\frac{AD}{14}\] \[\sin(60°)=\cos{(30°)}=\frac{DC}{14}\]

  3. Qwerty90
    • 3 years ago
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    Do I then need to use the sin and cosine formula to figure the rest out?

  4. UnkleRhaukus
    • 3 years ago
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    i still cannot see myself how to get DB

  5. Qwerty90
    • 3 years ago
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    lets assume its 30

  6. UnkleRhaukus
    • 3 years ago
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    very rough DB~7

  7. Qwerty90
    • 3 years ago
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    what do the first two equal?

  8. UnkleRhaukus
    • 3 years ago
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    actually you can work out angle DCB with a trig identity, because be know two of the sides, and then use another trig identity to find DB

  9. UnkleRhaukus
    • 3 years ago
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    the first two what? @Qwerty90

  10. Qwerty90
    • 3 years ago
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    when you gave those first few ratios.. the AD/14 and DC/14 what do those equal

  11. UnkleRhaukus
    • 3 years ago
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    you dont know the values of sin 30=cos60? you must remember theses if you dont remember you can use a calculator

  12. Qwerty90
    • 3 years ago
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    yes i know those..

  13. UnkleRhaukus
    • 3 years ago
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    \[\sin60°=\cos30°\] is a little bit tricker on a calculator, because the value given is irrational but you can square the output 0.86602540... 0.86602540...^2=0.75=3/4 so \[\sin60°=\cos30°= \sqrt{\frac{3}{4}}=\frac{\sqrt3}2\]

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