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 2 years ago
Look at the figure.
Under what conditions will the triangle formed by the three squares be a right triangle?
Answer
Area of Square 2 is equal to the sum of the area of Square 1 and area of Square 3.
Area of Square 3 is equal to the sum of the area of Square 1 and area of Square 2.
Perimeter of Square 2 is equal to the sum of the perimeter of Square 1 and Square 3.
Perimeter of Square 3 is equal to the sum of the perimeter of Square 1 and Square 2.
 2 years ago
Look at the figure. Under what conditions will the triangle formed by the three squares be a right triangle? Answer Area of Square 2 is equal to the sum of the area of Square 1 and area of Square 3. Area of Square 3 is equal to the sum of the area of Square 1 and area of Square 2. Perimeter of Square 2 is equal to the sum of the perimeter of Square 1 and Square 3. Perimeter of Square 3 is equal to the sum of the perimeter of Square 1 and Square 2.

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glgan1
 2 years ago
Best ResponseYou've already chosen the best response.3Lets assume that the sides of square 1 be a, sides of square 2 be b and sides of square 3 be c. Based on the figure given, we need to prove that:\[c^2=a^2 + b^2\] to show that the triangle formed is right triangle(Pythagoras' theorem). So definitely we can see that the answer would be Area of square3 = Area of square1 + area of square2.

cbrusoe
 2 years ago
Best ResponseYou've already chosen the best response.0got it sorry took me a lil while i had to draw what you were saying out lol but thankyou! =)

phi
 2 years ago
Best ResponseYou've already chosen the best response.0"i had to draw.." That is a good way to figure things out. Very Good!

glgan1
 2 years ago
Best ResponseYou've already chosen the best response.3haha it's okay.:) sometimes you will need to draw things out to make things clearer, especially questions involving trigonometry and also mechanics(projectile motion, circular motion etc.)

cbrusoe
 2 years ago
Best ResponseYou've already chosen the best response.0thankyou haha im a visual learner so i kinda have to and yeah =) aha
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