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Bailey.Nae

  • 3 years ago

@FoolForMath Can you help me? Suppose that a and b vary inversely and that b=5/6 when a=3 Write a function that models the inverse variation and find b when a = 8

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  1. imagreencat
    • 3 years ago
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    Well, b=k/a. So 5/6=k/3. That makes k=(5)(3)/(6). Simplify this. This k will then be your proportionality constant. Therefore, we can look for b when a=8 since the only unknown would just be b and not k also. b=k/8. Just substitute and evaluate, and you have your answer.

  2. MichaelCJ
    • 3 years ago
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    The basic form of inverse proportion is \[a=k/b\] First you need to find what the proportionality constant k is. Just insert the value of a and b given in the problem. \[3=k/(5/6) = 6k/5\] \[15=6k\] \[k=2.5\] Once you find k, then the relationship between a and b is known. Just substitute a with 8 to get your final answer :) \[8=k/b\] \[b=2.5/8\] \[b=5/16\]

  3. Bailey.Nae
    • 3 years ago
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    i got 5/6a;5/16 i'm right?

  4. Bailey.Nae
    • 3 years ago
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    or is it 5/2a;5/16...?

  5. MichaelCJ
    • 3 years ago
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    a=5/2b or b=5/2a yes 5/16 is the correct answer

  6. Bailey.Nae
    • 3 years ago
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    okay, thank you guys SO much. I really appreciate you guys!

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