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Eyad

An Infinite Geometric sequence Such : \[S \infty =81/2 , Sn/Tn=(3^n-1)/2\] ,Find The G.s ???

  • one year ago
  • one year ago

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  1. experimentX
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    Sinf??

    • one year ago
  2. Eyad
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    Sum to infinity :D Its rule is S∞ =a/1-r .

    • one year ago
  3. experimentX
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    you should have written more explicitly

    • one year ago
  4. Eyad
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    what do u mean ?

    • one year ago
  5. experimentX
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    sum up to infinity

    • one year ago
  6. Eyad
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    An infinite geometric series is an infinite series whose successive terms have a common ratio. Such a series converges if and only if the absolute value of the common ratio is less than one ( | r | < 1 ).

    • one year ago
  7. Eyad
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    lol ,thats all what I know xD

    • one year ago
  8. Eyad
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    I think its we can apply the rule only ..

    • one year ago
  9. experimentX
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    put n=2 ...

    • one year ago
  10. experimentX
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    1/r + 1 = 8

    • one year ago
  11. experimentX
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    find the value of a from the left relation

    • one year ago
  12. Eyad
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    u mean 1-r ,but why u put a =1 ?

    • one year ago
  13. experimentX
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    Oh ... sorry ... forgot to divide by 2

    • one year ago
  14. experimentX
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    ignore that post ... i wasn't thinking

    • one year ago
  15. Eyad
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    nvm :)

    • one year ago
  16. Eyad
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    sry for asking many questions :/

    • one year ago
  17. experimentX
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    \[ \frac{S_2}{T_2} = 4 = \frac{a +ar}{ar}\] find the value of r from here get the value of a from other relation

    • one year ago
  18. Eyad
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    aha...

    • one year ago
  19. Eyad
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    @satellite73 : can u help :)

    • one year ago
  20. Eyad
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    @experimentX :from where u got that 4 in Sn/Tn=4=... ?

    • one year ago
  21. experimentX
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    from your second relation ... put n=2

    • one year ago
  22. Eyad
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    oh, OK

    • one year ago
  23. experimentX
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    you will get the value of r from here use your first relation to get the second value

    • one year ago
  24. experimentX
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    *get the value of a

    • one year ago
  25. Eyad
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    oh ,k........TY ^.^_^.^

    • one year ago
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