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ajprincess
 2 years ago
prove\[(\neg p\wedge(\neg q\wedge r))\vee(q\wedge r)\vee(p\wedge q)=r\]
ajprincess
 2 years ago
prove\[(\neg p\wedge(\neg q\wedge r))\vee(q\wedge r)\vee(p\wedge q)=r\]

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ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1338094648240:dw prove this using laws of algebra of propositions.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0@amistre64, @jamesJ, @turingtest

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1338095286775:dw Except this other all are right.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0ya sure. thanx. :) can u help me to prove it if u dnt mind.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.0not used to this kind of thing,; I'm not sure what the technically right approach would be start making assumptions I guess...

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0ha k. thanx. @jamesJ if u dnt can u plzzz help me with this question?

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3How have you proved these sorts of things in the past? The most straightforward way to show this would be write out a truth table with eight rows, one row for each of the truth value combinations of p, q and r

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0i am ok with proving it using truth table. this is one of my past paper question. they hav askd to prove t using laws of algebra of propositions. bt I am nt ued to it.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0@asnaseer can u plzz help me vth this if u dnt mind.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0@JamesJ u too. can u help me plzzz

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3So you want to prove this now using propositions?

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0I tried bt was unable to get t.

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3I just constructed the truth table and the question as written here looks wrong. Could you please triple check it.

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3I think it might be this, but you check it! \[ (\neg p\wedge(\neg q\wedge r))\vee(q\wedge r)\vee(p\wedge r)=r \]

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0ya that's it. sooo sorrry for the mistake.

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3ok, well you factor out ^ r from each of these terms and you have ( ~p^~q) v q v p ) ^ r

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3and ( ~p^~q) v q v p is always true. Hence the entire expression is equivalent to TRUE ^ r = r

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0bt hw do v knw that ( ~p^~q) v q v p is always true?

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3because ~p^~q = ~(p v q) and hence (~p^~q) v q v p = ~(p v q) v (p v q)

JamesJ
 2 years ago
Best ResponseYou've already chosen the best response.3...and X v ~X is always true.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.0I get t nw. thanxxxxxxxx a lot.
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