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lindseyharrison

  • 3 years ago

What is the range of the graph of y = (x - 4)^2 + 3

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  1. jim_thompson5910
    • 3 years ago
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    Hint: In general, the range of y = a(x-h)^2+k is [k, infinity) if a > 0

  2. lindseyharrison
    • 3 years ago
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    Y ≤ 3??

  3. jim_thompson5910
    • 3 years ago
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    close, it should be \[\Large y \ge 3\]

  4. lindseyharrison
    • 3 years ago
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    What about this.... 4x^2 + 13x = -3

  5. jim_thompson5910
    • 3 years ago
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    You need to complete the square. Do you know how do to that?

  6. lindseyharrison
    • 3 years ago
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    no

  7. lindseyharrison
    • 3 years ago
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    So the answer would be x = -1/4 and x = -3

  8. jim_thompson5910
    • 3 years ago
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    you're looking for the range correct?

  9. lindseyharrison
    • 3 years ago
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    No just solving the equation

  10. jim_thompson5910
    • 3 years ago
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    oh sry, I thought you were finding the range

  11. jim_thompson5910
    • 3 years ago
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    4x^2 + 13x = -3 4x^2 + 13x + 3 = 0 Now use the quadratic formula to solve for x x = (-b+-sqrt(b^2-4ac))/(2a) x = (-(13)+-sqrt((13)^2-4(4)(3)))/(2(4)) x = (-13+-sqrt(169-(48)))/(8) x = (-13+-sqrt(121))/8 x = (-13+sqrt(121))/8 or x = (-13-sqrt(121))/8 x = (-13+11)/8 or x = (-13-11)/8 x = -2/8 or x = -24/8 x = -1/4 or x = -3 So you are correct, nice job

  12. lindseyharrison
    • 3 years ago
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    Thank you thank you! :)

  13. jim_thompson5910
    • 3 years ago
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    sure thing

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