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Anyone? :)

Which ones are perfect square trinomials?

a is do you know how i figured that out?

No, I don't.

have you learned foil?

No A is not the right answer!

Diya, there is more than one I can choose for the right answer. How come A isn't one of them?

|dw:1338062447129:dw| that is y it is

I'm so confused...

thats not how you do that

@megan1124 (7x-4)(7x-4) = 49x^2-56x+16

noo it equals a

are you in algebra 1?

Yep

for the 3rd time.

O.o what? So is one of the answers A or is one B?

So C and D aren't?

Diya, A isn't right? So the only right answer is B?

A isn't Right! i just showed you why..
B is right
But you have to check the others too

you can have more than one right answer right? if so its a and b

@megan1124 A is not the right answer
Can you tell me what is (7x-4)(7x-4) ??

its a

Nope, try to solve it and see

There is multiple answers that can be right.

Can you find the discriminant of C & D ?
\( D= b^2-4ac \)

I don't know what the disciminant is.

Just plug in the values of a ,b & c in the equation \(b^2 - 4ac \)
can you ?

@careless850 Pls tell me if you're stuck somewhere

is it equal to zero or some other number ?

I'm still confused..

where are you stuck ? did you find b^2 -4ac?

No.

Find it :) & check if its equal to zero

How do I find it?

......

25b^2 − 5b + 10
Given :
a =25
b=-5
c=10
b^2 - 4ac

(-5)^2 - 4* 25 * 10
is it equal to zero?

no

a is 16

yes
b & c?

-8 is b and 1 is c.

Right!!!!!!!
Now Find the discriminant
How do you find it?

So I would do this.. -> -8^2 -4*16*1.

Yessss good work :)

how to solve that, I don't know, but that's the problem.. lol

\( (8)^2 - 4 \times 16 \times 1 \)
What is \( 8^2 \) ?

64

64-64 = 0

So it's a PST

Yess!! so its a perfect square trinomial :)
You can verify by factoring ^_^

I see. Pretty easy now I guess. So the only ones that are perfect square trinomials are B and D?

Can you help me with another?

Yes, If you factorise 16x^2 − 8x + 1 you'll get (1-4x)(1-4x) = (1-4x)^2
Post it as a new question :)

Yes its B & D

Thank you. :))

Np :)