## FeoNeo33 Group Title I need double checking. http://i45.tinypic.com/jqjoep.jpg I got the answer "1"... need someone to make sure if that's right. 2 years ago 2 years ago

1. KingGeorge

I'm getting 0.

2. FeoNeo33

Interesting, gotta figure out what I did wrong.

3. KingGeorge

$\frac{x^2-1}{(x-2)(x+1)}-\frac{(x-1)(x+1)}{(x-2)(x+1)}$$=\frac{x^2-1}{(x-2)(x+1)}-\frac{x^2-1}{(x-2)(x+1)}=\frac{x^2-1-(x^2-1)}{(x-2)(x+1)}$$=\frac{0}{(x-2)(x+1)}=0$

4. FeoNeo33

Thanks, appreciate it.

5. KingGeorge

You're welcome.