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displacement time equation of a particle moving along xaxis is x=20+t312t.
a)find velocity of particle at time t=0
b)state whether the motion is uniformly acceleration or nt.
c)find position of the particle when v=0.
 one year ago
 one year ago
displacement time equation of a particle moving along xaxis is x=20+t312t. a)find velocity of particle at time t=0 b)state whether the motion is uniformly acceleration or nt. c)find position of the particle when v=0.
 one year ago
 one year ago

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apoorvkBest ResponseYou've already chosen the best response.0
if that^ is the equation of the displacement, how would you get the equation for velocity?
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
"Substitute" the value of "t" and find.
 one year ago

yakeygleeBest ResponseYou've already chosen the best response.0
Hint for part (a): \(v=\frac{dx}{dt}\) Hint for part (b): \(a=\frac{dv}{dt} = \frac{d^2x}{dt^2}\). If this is a function of time, then it is not constant. Hint for part (c): What \(t\) values satisfies this condition?
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
Sorry. @yakeyglee is absolutely correct. Follow his steps and ur answer is done
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
So, we getdw:1338103103383:dw
 one year ago

yakeygleeBest ResponseYou've already chosen the best response.0
More specifically, \(t=\pm 2\).
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
But, "t" cannot be negative, so t = 2. so, c) 2
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
A) 12m/s correct. sorry for my error.
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
On double differentiation, we get, a = 6t (I think I am correct).
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
So, unifrom acceleration
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
@Ishaan94 , @apoorvk @him1618 please help me and correct me if I am wqrong.
 one year ago

him1618Best ResponseYou've already chosen the best response.0
Acceleration is not uniform
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
But how? My steps r wrong or rite? Please help me.
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
No as a=6t, acceleration is dependent on time. So it's not uniform.
 one year ago

yakeygleeBest ResponseYou've already chosen the best response.0
\(t\) most certainly can be negative. It simply corresponds to be fore \(t=0\).
 one year ago

him1618Best ResponseYou've already chosen the best response.0
Bt that isnt in the domain@ yakeyglee
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
So @apoorvk bhai, when can we say that a is uniform? in what relation?
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
And put in the value of 't' when v=0 from the first part, in the equation of displacement, that is put in t=2. That should give you the displacement at the time when v=0.
 one year ago

him1618Best ResponseYou've already chosen the best response.0
When the accn is not a function of time
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
uniform means constant  it isn't constant is it?
 one year ago

him1618Best ResponseYou've already chosen the best response.0
In this case accn is a function of time...so its not uniform
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
Thanks all, I understood.
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
But, plz show me what will be the answer of (a), (b) and (c)
 one year ago

yakeygleeBest ResponseYou've already chosen the best response.0
@him1618 I don't see any statement of the domain...it's usually assumed \(t\in\mathbb R\), which includes negative values.
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
So, (a) = 12, (c) = 2, (b) = not uniform. Is this the final answer? Please say.
 one year ago

him1618Best ResponseYou've already chosen the best response.0
it is so my man..bt not here..this is simple/...were not into time domain circuits here :P
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
Is (a) and (b) what i gave the answer rite? How is (c) = 4?????????
 one year ago

him1618Best ResponseYou've already chosen the best response.0
v=0 means 3t^2  12 =0 t=2 Put t=2 in x(t)
 one year ago

AadarshBest ResponseYou've already chosen the best response.1
Still bhaiya, we get, 20 + 2*3  12*2 = 2. Am I rite????????
 one year ago
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