Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

displacement time equation of a particle moving along x-axis is x=20+t3-12t. a)find velocity of particle at time t=0 b)state whether the motion is uniformly acceleration or nt. c)find position of the particle when v=0.

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

if that^ is the equation of the displacement, how would you get the equation for velocity?
wrt 'time' ofcourse.
"Substitute" the value of "t" and find.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Hint for part (a): \(v=\frac{dx}{dt}\) Hint for part (b): \(a=\frac{dv}{dt} = \frac{d^2x}{dt^2}\). If this is a function of time, then it is not constant. Hint for part (c): What \(t\) values satisfies this condition?
v=dx/dt
Sorry. @yakeyglee is absolutely correct. Follow his steps and ur answer is done
as v=0,we 0=3t2-12
am i right.
Yeah, perfect @Ruchi.
So, we get|dw:1338103103383:dw|
A) answer is 12
More specifically, \(t=\pm 2\).
a)=-12m/s
But, "t" cannot be negative, so t = 2. so, c) 2
A) -12m/s correct. sorry for my error.
On double differentiation, we get, a = 6t (I think I am correct).
So, unifrom acceleration
@Ishaan94 , @apoorvk @him1618 please help me and correct me if I am wqrong.
Acceleration is not uniform
But how? My steps r wrong or rite? Please help me.
No as a=6t, acceleration is dependent on time. So it's not uniform.
\(t\) most certainly can be negative. It simply corresponds to be fore \(t=0\).
Bt that isnt in the domain@ yakeyglee
So @apoorvk bhai, when can we say that a is uniform? in what relation?
And put in the value of 't' when v=0 from the first part, in the equation of displacement, that is put in t=2. That should give you the displacement at the time when v=0.
When the accn is not a function of time
uniform means constant - it isn't constant is it?
In this case accn is a function of time...so its not uniform
Thanks all, I understood.
But, plz show me what will be the answer of (a), (b) and (c)
velocity is dx/dt
@him1618 I don't see any statement of the domain...it's usually assumed \(t\in\mathbb R\), which includes negative values.
So, (a) = -12, (c) = 2, (b) = not uniform. Is this the final answer? Please say.
it is so my man..bt not here..this is simple/...were not into time domain circuits here :P
c=4
Is (a) and (b) what i gave the answer rite? How is (c) = 4?????????
v=0 means 3t^2 - 12 =0 t=2 Put t=2 in x(t)
Still bhaiya, we get, 20 + 2*3 - 12*2 = 2. Am I rite????????

Not the answer you are looking for?

Search for more explanations.

Ask your own question