anonymous
  • anonymous
displacement time equation of a particle moving along x-axis is x=20+t3-12t. a)find velocity of particle at time t=0 b)state whether the motion is uniformly acceleration or nt. c)find position of the particle when v=0.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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apoorvk
  • apoorvk
if that^ is the equation of the displacement, how would you get the equation for velocity?
apoorvk
  • apoorvk
wrt 'time' ofcourse.
anonymous
  • anonymous
"Substitute" the value of "t" and find.

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anonymous
  • anonymous
Hint for part (a): \(v=\frac{dx}{dt}\) Hint for part (b): \(a=\frac{dv}{dt} = \frac{d^2x}{dt^2}\). If this is a function of time, then it is not constant. Hint for part (c): What \(t\) values satisfies this condition?
anonymous
  • anonymous
v=dx/dt
anonymous
  • anonymous
Sorry. @yakeyglee is absolutely correct. Follow his steps and ur answer is done
anonymous
  • anonymous
as v=0,we 0=3t2-12
anonymous
  • anonymous
am i right.
anonymous
  • anonymous
Yeah, perfect @Ruchi.
anonymous
  • anonymous
So, we get|dw:1338103103383:dw|
anonymous
  • anonymous
A) answer is 12
anonymous
  • anonymous
More specifically, \(t=\pm 2\).
anonymous
  • anonymous
a)=-12m/s
anonymous
  • anonymous
But, "t" cannot be negative, so t = 2. so, c) 2
anonymous
  • anonymous
A) -12m/s correct. sorry for my error.
anonymous
  • anonymous
On double differentiation, we get, a = 6t (I think I am correct).
anonymous
  • anonymous
So, unifrom acceleration
anonymous
  • anonymous
@Ishaan94 , @apoorvk @him1618 please help me and correct me if I am wqrong.
anonymous
  • anonymous
Acceleration is not uniform
anonymous
  • anonymous
But how? My steps r wrong or rite? Please help me.
apoorvk
  • apoorvk
No as a=6t, acceleration is dependent on time. So it's not uniform.
anonymous
  • anonymous
\(t\) most certainly can be negative. It simply corresponds to be fore \(t=0\).
anonymous
  • anonymous
Bt that isnt in the domain@ yakeyglee
anonymous
  • anonymous
So @apoorvk bhai, when can we say that a is uniform? in what relation?
apoorvk
  • apoorvk
And put in the value of 't' when v=0 from the first part, in the equation of displacement, that is put in t=2. That should give you the displacement at the time when v=0.
anonymous
  • anonymous
When the accn is not a function of time
apoorvk
  • apoorvk
uniform means constant - it isn't constant is it?
anonymous
  • anonymous
In this case accn is a function of time...so its not uniform
anonymous
  • anonymous
Thanks all, I understood.
anonymous
  • anonymous
But, plz show me what will be the answer of (a), (b) and (c)
anonymous
  • anonymous
velocity is dx/dt
anonymous
  • anonymous
@him1618 I don't see any statement of the domain...it's usually assumed \(t\in\mathbb R\), which includes negative values.
anonymous
  • anonymous
So, (a) = -12, (c) = 2, (b) = not uniform. Is this the final answer? Please say.
anonymous
  • anonymous
it is so my man..bt not here..this is simple/...were not into time domain circuits here :P
anonymous
  • anonymous
c=4
anonymous
  • anonymous
Is (a) and (b) what i gave the answer rite? How is (c) = 4?????????
anonymous
  • anonymous
v=0 means 3t^2 - 12 =0 t=2 Put t=2 in x(t)
anonymous
  • anonymous
Still bhaiya, we get, 20 + 2*3 - 12*2 = 2. Am I rite????????

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