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anonymous
 4 years ago
displacement time equation of a particle moving along xaxis is x=20+t312t.
a)find velocity of particle at time t=0
b)state whether the motion is uniformly acceleration or nt.
c)find position of the particle when v=0.
anonymous
 4 years ago
displacement time equation of a particle moving along xaxis is x=20+t312t. a)find velocity of particle at time t=0 b)state whether the motion is uniformly acceleration or nt. c)find position of the particle when v=0.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if that^ is the equation of the displacement, how would you get the equation for velocity?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0"Substitute" the value of "t" and find.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hint for part (a): \(v=\frac{dx}{dt}\) Hint for part (b): \(a=\frac{dv}{dt} = \frac{d^2x}{dt^2}\). If this is a function of time, then it is not constant. Hint for part (c): What \(t\) values satisfies this condition?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry. @yakeyglee is absolutely correct. Follow his steps and ur answer is done

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, perfect @Ruchi.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, we getdw:1338103103383:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0More specifically, \(t=\pm 2\).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But, "t" cannot be negative, so t = 2. so, c) 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A) 12m/s correct. sorry for my error.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0On double differentiation, we get, a = 6t (I think I am correct).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, unifrom acceleration

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Ishaan94 , @apoorvk @him1618 please help me and correct me if I am wqrong.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Acceleration is not uniform

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But how? My steps r wrong or rite? Please help me.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No as a=6t, acceleration is dependent on time. So it's not uniform.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\(t\) most certainly can be negative. It simply corresponds to be fore \(t=0\).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Bt that isnt in the domain@ yakeyglee

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So @apoorvk bhai, when can we say that a is uniform? in what relation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And put in the value of 't' when v=0 from the first part, in the equation of displacement, that is put in t=2. That should give you the displacement at the time when v=0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0When the accn is not a function of time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0uniform means constant  it isn't constant is it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In this case accn is a function of time...so its not uniform

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks all, I understood.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But, plz show me what will be the answer of (a), (b) and (c)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@him1618 I don't see any statement of the domain...it's usually assumed \(t\in\mathbb R\), which includes negative values.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, (a) = 12, (c) = 2, (b) = not uniform. Is this the final answer? Please say.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is so my man..bt not here..this is simple/...were not into time domain circuits here :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is (a) and (b) what i gave the answer rite? How is (c) = 4?????????

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0v=0 means 3t^2  12 =0 t=2 Put t=2 in x(t)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Still bhaiya, we get, 20 + 2*3  12*2 = 2. Am I rite????????
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