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Ruchi.
Group Title
displacement time equation of a particle moving along xaxis is x=20+t312t.
a)find velocity of particle at time t=0
b)state whether the motion is uniformly acceleration or nt.
c)find position of the particle when v=0.
 2 years ago
 2 years ago
Ruchi. Group Title
displacement time equation of a particle moving along xaxis is x=20+t312t. a)find velocity of particle at time t=0 b)state whether the motion is uniformly acceleration or nt. c)find position of the particle when v=0.
 2 years ago
 2 years ago

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apoorvk Group TitleBest ResponseYou've already chosen the best response.0
if that^ is the equation of the displacement, how would you get the equation for velocity?
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.0
wrt 'time' ofcourse.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
"Substitute" the value of "t" and find.
 2 years ago

yakeyglee Group TitleBest ResponseYou've already chosen the best response.0
Hint for part (a): \(v=\frac{dx}{dt}\) Hint for part (b): \(a=\frac{dv}{dt} = \frac{d^2x}{dt^2}\). If this is a function of time, then it is not constant. Hint for part (c): What \(t\) values satisfies this condition?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
Sorry. @yakeyglee is absolutely correct. Follow his steps and ur answer is done
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.2
as v=0,we 0=3t212
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
Yeah, perfect @Ruchi.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
So, we getdw:1338103103383:dw
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
A) answer is 12
 2 years ago

yakeyglee Group TitleBest ResponseYou've already chosen the best response.0
More specifically, \(t=\pm 2\).
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
But, "t" cannot be negative, so t = 2. so, c) 2
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
A) 12m/s correct. sorry for my error.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
On double differentiation, we get, a = 6t (I think I am correct).
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
So, unifrom acceleration
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
@Ishaan94 , @apoorvk @him1618 please help me and correct me if I am wqrong.
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
Acceleration is not uniform
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
But how? My steps r wrong or rite? Please help me.
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.0
No as a=6t, acceleration is dependent on time. So it's not uniform.
 2 years ago

yakeyglee Group TitleBest ResponseYou've already chosen the best response.0
\(t\) most certainly can be negative. It simply corresponds to be fore \(t=0\).
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
Bt that isnt in the domain@ yakeyglee
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
So @apoorvk bhai, when can we say that a is uniform? in what relation?
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.0
And put in the value of 't' when v=0 from the first part, in the equation of displacement, that is put in t=2. That should give you the displacement at the time when v=0.
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
When the accn is not a function of time
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.0
uniform means constant  it isn't constant is it?
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
In this case accn is a function of time...so its not uniform
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
Thanks all, I understood.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
But, plz show me what will be the answer of (a), (b) and (c)
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
velocity is dx/dt
 2 years ago

yakeyglee Group TitleBest ResponseYou've already chosen the best response.0
@him1618 I don't see any statement of the domain...it's usually assumed \(t\in\mathbb R\), which includes negative values.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
So, (a) = 12, (c) = 2, (b) = not uniform. Is this the final answer? Please say.
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
it is so my man..bt not here..this is simple/...were not into time domain circuits here :P
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
Is (a) and (b) what i gave the answer rite? How is (c) = 4?????????
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
v=0 means 3t^2  12 =0 t=2 Put t=2 in x(t)
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
Still bhaiya, we get, 20 + 2*3  12*2 = 2. Am I rite????????
 2 years ago
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