## FoolForMath Group Title Fool's problem of the day, A not so easy geometry problem, A triangle is divided into four parts by straight lines from two of the corners. The area of three triangular parts are 8,5 and 10 sq units. What is the area of the remaining part? Good luck! 2 years ago 2 years ago

1. FoolForMath Group Title

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2. FoolForMath Group Title

The diagram is not to scale.

3. ninhi5 Group Title

does any of the line equal?

4. ninhi5 Group Title

i'd take it as a no

5. shivamsinha Group Title

6. FoolForMath Group Title

Explain~

7. shivamsinha Group Title

1 sec

8. FoolForMath Group Title

9. shivamsinha Group Title

oo thanks.... i am seeing this now!! wat u trying to prove ??

10. FoolForMath Group Title

I am interested to see your solution :)

11. shivamsinha Group Title

i m drwing it

12. FoolForMath Group Title

That is a short version of the above solution: Join the third vertex to the intersection of the two lines. Let x and y be the areas of the two triangles formed, with y near 8 and x near 5 $x = \frac 1 2 (y+8)\\ y= \frac 8 {10} (x+5)$ Solve, you get x=10, y= 12 and x+y =22