## FoolForMath Fool's problem of the day, A not so easy geometry problem, A triangle is divided into four parts by straight lines from two of the corners. The area of three triangular parts are 8,5 and 10 sq units. What is the area of the remaining part? Good luck! one year ago one year ago

1. FoolForMath

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2. FoolForMath

The diagram is not to scale.

3. ninhi5

does any of the line equal?

4. ninhi5

i'd take it as a no

5. shivamsinha

6. FoolForMath

Explain~

7. shivamsinha

1 sec

8. FoolForMath

9. shivamsinha

oo thanks.... i am seeing this now!! wat u trying to prove ??

10. FoolForMath

I am interested to see your solution :)

11. shivamsinha

i m drwing it

12. FoolForMath

That is a short version of the above solution: Join the third vertex to the intersection of the two lines. Let x and y be the areas of the two triangles formed, with y near 8 and x near 5 $x = \frac 1 2 (y+8)\\ y= \frac 8 {10} (x+5)$ Solve, you get x=10, y= 12 and x+y =22