A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3\[\Large \sqrt{x}=x^ \frac{1}{2}\]Do you know this?

abz_tech
 2 years ago
Best ResponseYou've already chosen the best response.0ya .. i know derivite of that is 1/2√x

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3The easier way is to do by this metho\[\Large x \sqrt{x}= x.x^ \frac{1}{2}\]

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3\[\Large x^m \times x^n = x^{m+n}\]

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3\[\Large x \times x^ \frac{1}{2}= ?\]

abz_tech
 2 years ago
Best ResponseYou've already chosen the best response.00_o.. didn;t think of that..but aren't u supposed to use roduct rule?

annas
 2 years ago
Best ResponseYou've already chosen the best response.2no product rule is not applicable here 3/2 x^1/2 answer

abz_tech
 2 years ago
Best ResponseYou've already chosen the best response.0now that makes sense 0_o

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3Yes you can use product rule ,You'll get the same answer

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3\[\frac{d}{dx}x \sqrt{x}=x \frac{d}{dx}\sqrt{x}+\sqrt{x}\frac{d}{dx}x\]\[=x .\frac{1}{2\sqrt{x}}+\sqrt{x}=\frac{x}{2\sqrt{x}}+\sqrt{x} =\frac{\sqrt{x}}{2}+\sqrt{x}\]\[=\frac{\sqrt{x}}{2}+ \frac{\sqrt{x}}{1}=\frac{\sqrt{x}}{2}+\frac{\sqrt{x} \times 2 }{1 \times 2} =\frac{\sqrt{x}}{2}+\frac{2\sqrt{x}}{2}=\frac{3\sqrt{x}}{2}\]

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3Using the Product Rule^^

annas
 2 years ago
Best ResponseYou've already chosen the best response.2wow diya you are really good at maths :)

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3\[\Large \frac{3}{2}x^ \frac{1}{2}= \frac{3}{2}\sqrt{x}= \frac{3\sqrt{x}}{2}\]Same answer! :)

abz_tech
 2 years ago
Best ResponseYou've already chosen the best response.0lol ye.. ur really good

abz_tech
 2 years ago
Best ResponseYou've already chosen the best response.0hmm hey, if u dont mind can u help me with another question =/?

Diyadiya
 2 years ago
Best ResponseYou've already chosen the best response.3Post another question :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.