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hmm?

\[\Large \sqrt{x}=x^ \frac{1}{2}\]Do you know this?

ya
.. i know derivite of that is 1/2√x

The easier way is to do by this metho\[\Large x \sqrt{x}= x.x^ \frac{1}{2}\]

ok.. then?

\[\Large x^m \times x^n = x^{m+n}\]

\[\Large x \times x^ \frac{1}{2}= ?\]

x^3/2

0_o.. didn;t think of that..but aren't u supposed to use roduct rule?

product rule

no product rule is not applicable here
3/2 x^1/2 answer

now that makes sense 0_o

Yes you can use product rule ,You'll get the same answer

why not tough?

:o ok

thx

\[3/2x^{1/2}\]

Using the Product Rule^^

wow diya you are really good at maths :)

\[\Large \frac{3}{2}x^ \frac{1}{2}= \frac{3}{2}\sqrt{x}= \frac{3\sqrt{x}}{2}\]Same answer! :)

Lol Thanks Annas!

welcome !

lol ye.. ur really good

hmm hey, if u dont mind can u help me with another question =/?

Post another question :)

ok