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DiyadiyaBest ResponseYou've already chosen the best response.2
\[\sqrt{x}(2x+4) \ \ or \ \ \sqrt{x(2x+4)}\]
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.2
First can you try it out by yourself?
 one year ago

abz_techBest ResponseYou've already chosen the best response.2
hmm i got : \[2√x + 1/2√x(2x+4)\]
 one year ago

abz_techBest ResponseYou've already chosen the best response.2
dunno how to go from there =/
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.2
Yes thats Right!!! :) Hope you understood :)
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.2
You can simplify it , 1second ..
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.2
\[2\sqrt{x}+ \frac{(2x+4)}{\sqrt{2x}}=\frac{2\sqrt{x}}{1}+ \frac{(2x+4)}{2\sqrt{x}}\]\[\frac{2\sqrt{x}\times 2\sqrt{x}}{1\times 2\sqrt{x}}+ \frac{(2x+4)}{2\sqrt{x}}=\frac{4x}{2\sqrt{x}}+ \frac{(2x+4)}{2\sqrt{x}}\]\[ \frac{(4x+2x+4)}{2\sqrt{x}}= \frac{(6x+4)}{2\sqrt{x}}\]Now factor out 2 from 6x+4 6x+4 =2(3x+2)\[ \frac{2(3x+2)}{2\sqrt{x}}= \frac{(3x+2)}{\sqrt{x}}\]
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.2
If you want you can rationalise \[ \frac{(3x+2) \times \sqrt{x}}{\sqrt{x} \times \sqrt{x}} = \frac{\sqrt{x}(3x+2)}{x}\]\[\frac{\sqrt{x}3x}{x}+\frac{2\sqrt{x}}{x}= 3\sqrt{x}+ \frac{ 2}{\sqrt{x}}\]
 one year ago

abz_techBest ResponseYou've already chosen the best response.2
thx diya.. omg that was kinda easy ... can't belive didn't get that .
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.2
lol Take your time :) Is there any step which you didn't follow ?
 one year ago

DiyadiyaBest ResponseYou've already chosen the best response.2
No problem ,You're Welcome :)
 one year ago

abz_techBest ResponseYou've already chosen the best response.2
poke u later when im stuck.. kinda ok for now :p
 one year ago
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