anonymous
  • anonymous
Is there an easy way to mentally calculate 2^n (where n can be any natural no.)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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experimentX
  • experimentX
memory 1 2 4 8 16 32 64 128 256 512 1024 ...
anonymous
  • anonymous
1?
experimentX
  • experimentX
2^0

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anonymous
  • anonymous
0 is not a natural no
experimentX
  • experimentX
some include 0 as natural number while some do not http://en.wikipedia.org/wiki/Natural_number
anonymous
  • anonymous
what about 54,55,56,... you can't just memories them all !
experimentX
  • experimentX
lol http://en.wikipedia.org/wiki/Pi#Memorizing_digits
experimentX
  • experimentX
the best way is to memorize up to 2^10 ... or 2^something ... then multiply it by two until your you get your result.
radar
  • radar
Use the calculator \[x ^{y}\] button.
anonymous
  • anonymous
why would you ever need 2^54 or something that large?
experimentX
  • experimentX
haha ... agree with radar!!
radar
  • radar
I realize that is not really a "mentally" way, but when you get above 2^7 that would be the way I would do it mentally.
radar
  • radar
use the tools.
anonymous
  • anonymous
@experimentX , 0 can not be an element of N.
experimentX
  • experimentX
I looked into wikipedia .... it said that 0 is still debated as it is an element of N or not
experimentX
  • experimentX
besides ... the question hardly focuses on 0 is a natural number or not ... and i'm in no position to argue that
anonymous
  • anonymous
any natural number at all? seems doubtful since this grows very large very fact. but i count on my fingers, doubling each time two four eight sixteen thirty two sixty four one twenty eight two fifty six five twelve ten twenty four it helps to be old an remember when a computer actually came with one twenty eight two fifty six or five twelve megs, so those numbers are familiar.

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