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open_study1

  • 2 years ago

50 ML of 0.001 M phosphoric acid are exactly neutralized by the addition of 0.005 N Naoh the molarity of resulting salt is?

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  1. open_study1
    • 2 years ago
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    @Callisto help

  2. Callisto
    • 2 years ago
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    Sorry.. I haven't learnt it :|

  3. open_study1
    • 2 years ago
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    ok

  4. .Sam.
    • 2 years ago
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    \[\begin{array}{c} \text{H}_3\text{P}\text{O}_4 \\\end{array}\text{ + }\begin{array}{cc} 3 & \text{Na}\text{O}\text{H} \\\end{array}\text{ $\longrightarrow $ }\begin{array}{cc} 3 & \text{H}_2\text{O} \\\end{array}\text{ + }\begin{array}{c} \text{Na}_3\text{P}\text{O}_4 \\\end{array}\] ------------------------------------ \[M_AV_A=M_BV_B\] \[\text{Molarity of base is}~~ M_B \] \[\text{Molarity of acid is}~~ M_A\] ------------------------------------ \[M_B=\frac{M_AV_A}{V_B}\] Sub in the values

  5. Preetha
    • 2 years ago
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    Don forget the stoichiometric ratios. for every mole of phosphoric acid, you need 3 moles of NaOH to neutralize it. So you have to include that factor of 3 in the above calculation. It is a 1: 3 not 1:1 relationship. Try it and see.

  6. open_study1
    • 2 years ago
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    @Kryten help!

  7. Kryten
    • 2 years ago
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    as i see it you got all you need you just need to put numbers in.... only way to learn how to solve this kind of things is to do it yourself...

  8. open_study1
    • 2 years ago
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    i solve it but not getting lol @Kryten thats why i called u

  9. open_study1
    • 2 years ago
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    if u get after solving that then inform me

  10. open_study1
    • 2 years ago
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    The answer should be 6.25 * 10^-4 moles

  11. open_study1
    • 2 years ago
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    but i am not getting that @Kryten

  12. Kryten
    • 2 years ago
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    this is really basic chemistry, begin with writing equation, then write down what you have and what you need and do the magic... put the relationships of reactants and products in equations and just crunch the numbers...

  13. open_study1
    • 2 years ago
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    @.Sam. not getting the answer by ur way

  14. open_study1
    • 2 years ago
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    @Kryten not getting!!!

  15. open_study1
    • 2 years ago
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    i wrote the equation

  16. .Sam.
    • 2 years ago
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    6.25 * 10^-4 moles This is in moles, I thought you want molarity?

  17. open_study1
    • 2 years ago
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    @Kryten do u have any idea

  18. open_study1
    • 2 years ago
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    i am confused in question it is asked to find molarity but the answer is given in 6.25*10^-4

  19. Kryten
    • 2 years ago
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    yea i have some idea but i gotta run students arent waiting i need to keep them safe... see you later

  20. open_study1
    • 2 years ago
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    @Vincent-Lyon.Fr do u have any idea....

  21. Vincent-Lyon.Fr
    • 2 years ago
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    I won't answer any of your questions as you are pestering this study site without ever doing any effort on your own.

  22. open_study1
    • 2 years ago
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    @Vincent-Lyon.Fr i did but not getting!

  23. shivam_bhalla
    • 2 years ago
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    @open_study1 , my answer is same as @Vincent-Lyon.Fr 's

  24. open_study1
    • 2 years ago
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    @shivam_bhalla i tried ny level best but i am unable,

  25. shivam_bhalla
    • 2 years ago
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    @.Sam. and @Preetha have given you the valuable hints and tips . Just go ahead and solve it. you have to find the number of moles of H3PO4 initially reacting from given info

  26. HairtUB
    • 2 years ago
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    What's M and N?

  27. open_study1
    • 2 years ago
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    M=molarity N=normality

  28. open_study1
    • 2 years ago
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    moles = 5*10^-5 moles

  29. shivam_bhalla
    • 2 years ago
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    Yes. Now continue and do the rest of the problem.

  30. open_study1
    • 2 years ago
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    now wat to do

  31. TheOlympicnomad
    • 2 years ago
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    I'm sorry i don't know this :).

  32. open_study1
    • 2 years ago
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    @shivam_bhalla r u there....

  33. open_study1
    • 2 years ago
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    Plzzz help anyone plzz!

  34. open_study1
    • 2 years ago
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    @Kryten HELP

  35. open_study1
    • 2 years ago
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    I FOUNDED THE MOLE THEN WAT TO DO???

  36. open_study1
    • 2 years ago
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    @Kryten PLZZ GUIDE ME PLZZ

  37. open_study1
    • 2 years ago
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    OH........OH..........PLZZZZ SOME ONE HELP! I AM WAITING FOR 1 DAY PLZZZZ

  38. open_study1
    • 2 years ago
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    5*10^-5 moles

  39. Kryten
    • 2 years ago
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    in your place i would give up on pleading and solve it myself... you have been give instructions by multiple people and you just need to follow them, point is that you want it to be solved so you god forgive wouldnt have to hitch your little grey cells...

  40. open_study1
    • 2 years ago
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    I DID IN THE WAY THEY GUIDED BUT NOT GETTING I FOUNDED THE MOLES THEN WAT TO DO PLZZ TELL ME THE STEPS I WILL SOLVE MY OWN @Kryten

  41. Kryten
    • 2 years ago
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    first send some proof that you did anything (picture of paper of your tries) and then ill help. this is i think your third time you post this question and you just need to read what people have written... look up and read all carefully

  42. open_study1
    • 2 years ago
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    0.15=0.005*V V=30ML

  43. open_study1
    • 2 years ago
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    0.05 MILLI MOLES OF H3PO4 ON REACTING GIVES 0.05 MILLI MOLES OF NA3PO4 IE 5*10^-5 MOLES OF NA3PO4 ARE FORMED

  44. open_study1
    • 2 years ago
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    @Kryten

  45. open_study1
    • 2 years ago
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    DO U NEED MORE INFO?

  46. Kryten
    • 2 years ago
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    now lets start from the begining write first what data you have, chemical reaction equation and then write what you need from data to be calculated

  47. open_study1
    • 2 years ago
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    H3PO4 + 3NaOH ⟶ 3H2O + Na3PO4

  48. open_study1
    • 2 years ago
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    WE HAVE TO FIND THE MOLARITY OF NA3PO4

  49. Kryten
    • 2 years ago
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    write your data properly ex. c(X)= ... V(X)=... c(Y)=.... and then what you need to calculate ex. c(z)=?

  50. open_study1
    • 2 years ago
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    WAT IS C(X)

  51. Kryten
    • 2 years ago
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    that are examples how to write your data properly now lets see you do it

  52. open_study1
    • 2 years ago
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    V(PHOSPHORIC ACID)=50ML M(PHOSPHORIC ACID)=0.001M N(NAOH)=0.005N M(NA3PO4)=?

  53. open_study1
    • 2 years ago
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    IS THAT CORRECT.........

  54. Kryten
    • 2 years ago
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    ok now lets see you have written N(NaOH)=0,005N --> that doesnt exist cause N(NaOH) is marking of number of NaOH atoms and it has no units, and furthermore write it one under another not one next to other cause that is vast. now lets see corection...

  55. open_study1
    • 2 years ago
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    NORMALITY OF NAOH=0.005N

  56. Kryten
    • 2 years ago
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    now please explain to me what is normality and then write all data again properly

  57. open_study1
    • 2 years ago
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    NO OF EQUIVALENT OF SOLUTE IN ONE LITRE OF SOLUTION

  58. Kryten
    • 2 years ago
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    ok now explain me the unit N what is its derivative

  59. open_study1
    • 2 years ago
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    N= WG OF SOLUTE /(EQUIVALENT WG OF SOLUTE * VOLUME(L))

  60. Kryten
    • 2 years ago
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    ok now when you explained it all carry on and write all data properly one item under other and under it all chemical equation

  61. open_study1
    • 2 years ago
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    @Kryten ANYHOW THANZZZ I HAVE TO GO NOW PLZZ GIVE ALL THE HINTS I WILL LOOK IT AFTER WARDS............

  62. Kryten
    • 2 years ago
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    no way, you will write all here so i see what you are doing...

  63. open_study1
    • 2 years ago
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    hello

  64. open_study1
    • 2 years ago
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    @Kryten

  65. Kryten
    • 2 years ago
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    continue where you stoped, write all on one place...

  66. open_study1
    • 2 years ago
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    thats all wat i knw

  67. Kryten
    • 2 years ago
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    but you still havent written all in one place properly

  68. open_study1
    • 2 years ago
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    oh....no wat else u want

  69. Kryten
    • 2 years ago
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    i would like a cold bear and a steak but what you want is the question

  70. open_study1
    • 2 years ago
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    this website was made to help!!!! so plzz

  71. Kryten
    • 2 years ago
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    i am helping you but you are resisting to it... take a look how i solved your past questions where i photographed my work, it was all in sequence like it should be and that is the only way i will help you if you do it properly and as it should be solved and when you get that routine all this will be easy for you so your choice...

  72. open_study1
    • 2 years ago
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    yes u helped me a lot earlier by risiking a lot but i want the reson now why u r not helping that way did any one force u???

  73. open_study1
    • 2 years ago
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    such as @vincent fr @aravind etc......

  74. Kryten
    • 2 years ago
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    no, but i realised that you are taking a path of least resistance which is not good... this site is for learning and not getting all solved with no effort...

  75. Kryten
    • 2 years ago
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    now lets skip all the debate and tell me if you want to do it with my help properly or with no help at all

  76. open_study1
    • 2 years ago
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    i want help

  77. Kryten
    • 2 years ago
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    so whats the problem then... take a look how i solved your past questions and write it all like that here step by step and with understanding and reason why is it like it is for each step so that you LEARN how to solve problems like this...

  78. open_study1
    • 2 years ago
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    ok let me try

  79. ujjwal
    • 2 years ago
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    Its been two days.. LMAO..

  80. open_study1
    • 2 years ago
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    yes no one seems to help me........

  81. siddhantsharan
    • 2 years ago
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    Is the Answer 3.33 x 10^-4 ?

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