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open_study1

50 ML of 0.001 M phosphoric acid are exactly neutralized by the addition of 0.005 N Naoh the molarity of resulting salt is?

  • one year ago
  • one year ago

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  1. open_study1
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    @Callisto help

    • one year ago
  2. Callisto
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    Sorry.. I haven't learnt it :|

    • one year ago
  3. open_study1
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    ok

    • one year ago
  4. .Sam.
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    \[\begin{array}{c} \text{H}_3\text{P}\text{O}_4 \\\end{array}\text{ + }\begin{array}{cc} 3 & \text{Na}\text{O}\text{H} \\\end{array}\text{ $\longrightarrow $ }\begin{array}{cc} 3 & \text{H}_2\text{O} \\\end{array}\text{ + }\begin{array}{c} \text{Na}_3\text{P}\text{O}_4 \\\end{array}\] ------------------------------------ \[M_AV_A=M_BV_B\] \[\text{Molarity of base is}~~ M_B \] \[\text{Molarity of acid is}~~ M_A\] ------------------------------------ \[M_B=\frac{M_AV_A}{V_B}\] Sub in the values

    • one year ago
  5. Preetha
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    Don forget the stoichiometric ratios. for every mole of phosphoric acid, you need 3 moles of NaOH to neutralize it. So you have to include that factor of 3 in the above calculation. It is a 1: 3 not 1:1 relationship. Try it and see.

    • one year ago
  6. open_study1
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    @Kryten help!

    • one year ago
  7. Kryten
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    as i see it you got all you need you just need to put numbers in.... only way to learn how to solve this kind of things is to do it yourself...

    • one year ago
  8. open_study1
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    i solve it but not getting lol @Kryten thats why i called u

    • one year ago
  9. open_study1
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    if u get after solving that then inform me

    • one year ago
  10. open_study1
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    The answer should be 6.25 * 10^-4 moles

    • one year ago
  11. open_study1
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    but i am not getting that @Kryten

    • one year ago
  12. Kryten
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    this is really basic chemistry, begin with writing equation, then write down what you have and what you need and do the magic... put the relationships of reactants and products in equations and just crunch the numbers...

    • one year ago
  13. open_study1
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    @.Sam. not getting the answer by ur way

    • one year ago
  14. open_study1
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    @Kryten not getting!!!

    • one year ago
  15. open_study1
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    i wrote the equation

    • one year ago
  16. .Sam.
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    6.25 * 10^-4 moles This is in moles, I thought you want molarity?

    • one year ago
  17. open_study1
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    @Kryten do u have any idea

    • one year ago
  18. open_study1
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    i am confused in question it is asked to find molarity but the answer is given in 6.25*10^-4

    • one year ago
  19. Kryten
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    yea i have some idea but i gotta run students arent waiting i need to keep them safe... see you later

    • one year ago
  20. open_study1
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    @Vincent-Lyon.Fr do u have any idea....

    • one year ago
  21. Vincent-Lyon.Fr
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    I won't answer any of your questions as you are pestering this study site without ever doing any effort on your own.

    • one year ago
  22. open_study1
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    @Vincent-Lyon.Fr i did but not getting!

    • one year ago
  23. shivam_bhalla
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    @open_study1 , my answer is same as @Vincent-Lyon.Fr 's

    • one year ago
  24. open_study1
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    @shivam_bhalla i tried ny level best but i am unable,

    • one year ago
  25. shivam_bhalla
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    @.Sam. and @Preetha have given you the valuable hints and tips . Just go ahead and solve it. you have to find the number of moles of H3PO4 initially reacting from given info

    • one year ago
  26. HairtUB
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    What's M and N?

    • one year ago
  27. open_study1
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    M=molarity N=normality

    • one year ago
  28. open_study1
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    moles = 5*10^-5 moles

    • one year ago
  29. shivam_bhalla
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    Yes. Now continue and do the rest of the problem.

    • one year ago
  30. open_study1
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    now wat to do

    • one year ago
  31. TheOlympicnomad
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    I'm sorry i don't know this :).

    • one year ago
  32. open_study1
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    @shivam_bhalla r u there....

    • one year ago
  33. open_study1
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    Plzzz help anyone plzz!

    • one year ago
  34. open_study1
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    @Kryten HELP

    • one year ago
  35. open_study1
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    I FOUNDED THE MOLE THEN WAT TO DO???

    • one year ago
  36. open_study1
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    @Kryten PLZZ GUIDE ME PLZZ

    • one year ago
  37. open_study1
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    OH........OH..........PLZZZZ SOME ONE HELP! I AM WAITING FOR 1 DAY PLZZZZ

    • one year ago
  38. open_study1
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    5*10^-5 moles

    • one year ago
  39. Kryten
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    in your place i would give up on pleading and solve it myself... you have been give instructions by multiple people and you just need to follow them, point is that you want it to be solved so you god forgive wouldnt have to hitch your little grey cells...

    • one year ago
  40. open_study1
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    I DID IN THE WAY THEY GUIDED BUT NOT GETTING I FOUNDED THE MOLES THEN WAT TO DO PLZZ TELL ME THE STEPS I WILL SOLVE MY OWN @Kryten

    • one year ago
  41. Kryten
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    first send some proof that you did anything (picture of paper of your tries) and then ill help. this is i think your third time you post this question and you just need to read what people have written... look up and read all carefully

    • one year ago
  42. open_study1
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    0.15=0.005*V V=30ML

    • one year ago
  43. open_study1
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    0.05 MILLI MOLES OF H3PO4 ON REACTING GIVES 0.05 MILLI MOLES OF NA3PO4 IE 5*10^-5 MOLES OF NA3PO4 ARE FORMED

    • one year ago
  44. open_study1
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    @Kryten

    • one year ago
  45. open_study1
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    DO U NEED MORE INFO?

    • one year ago
  46. Kryten
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    now lets start from the begining write first what data you have, chemical reaction equation and then write what you need from data to be calculated

    • one year ago
  47. open_study1
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    H3PO4 + 3NaOH ⟶ 3H2O + Na3PO4

    • one year ago
  48. open_study1
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    WE HAVE TO FIND THE MOLARITY OF NA3PO4

    • one year ago
  49. Kryten
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    write your data properly ex. c(X)= ... V(X)=... c(Y)=.... and then what you need to calculate ex. c(z)=?

    • one year ago
  50. open_study1
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    WAT IS C(X)

    • one year ago
  51. Kryten
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    that are examples how to write your data properly now lets see you do it

    • one year ago
  52. open_study1
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    V(PHOSPHORIC ACID)=50ML M(PHOSPHORIC ACID)=0.001M N(NAOH)=0.005N M(NA3PO4)=?

    • one year ago
  53. open_study1
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    IS THAT CORRECT.........

    • one year ago
  54. Kryten
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    ok now lets see you have written N(NaOH)=0,005N --> that doesnt exist cause N(NaOH) is marking of number of NaOH atoms and it has no units, and furthermore write it one under another not one next to other cause that is vast. now lets see corection...

    • one year ago
  55. open_study1
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    NORMALITY OF NAOH=0.005N

    • one year ago
  56. Kryten
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    now please explain to me what is normality and then write all data again properly

    • one year ago
  57. open_study1
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    NO OF EQUIVALENT OF SOLUTE IN ONE LITRE OF SOLUTION

    • one year ago
  58. Kryten
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    ok now explain me the unit N what is its derivative

    • one year ago
  59. open_study1
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    N= WG OF SOLUTE /(EQUIVALENT WG OF SOLUTE * VOLUME(L))

    • one year ago
  60. Kryten
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    ok now when you explained it all carry on and write all data properly one item under other and under it all chemical equation

    • one year ago
  61. open_study1
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    @Kryten ANYHOW THANZZZ I HAVE TO GO NOW PLZZ GIVE ALL THE HINTS I WILL LOOK IT AFTER WARDS............

    • one year ago
  62. Kryten
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    no way, you will write all here so i see what you are doing...

    • one year ago
  63. open_study1
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    hello

    • one year ago
  64. open_study1
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    @Kryten

    • one year ago
  65. Kryten
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    continue where you stoped, write all on one place...

    • one year ago
  66. open_study1
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    thats all wat i knw

    • one year ago
  67. Kryten
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    but you still havent written all in one place properly

    • one year ago
  68. open_study1
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    oh....no wat else u want

    • one year ago
  69. Kryten
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    i would like a cold bear and a steak but what you want is the question

    • one year ago
  70. open_study1
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    this website was made to help!!!! so plzz

    • one year ago
  71. Kryten
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    i am helping you but you are resisting to it... take a look how i solved your past questions where i photographed my work, it was all in sequence like it should be and that is the only way i will help you if you do it properly and as it should be solved and when you get that routine all this will be easy for you so your choice...

    • one year ago
  72. open_study1
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    yes u helped me a lot earlier by risiking a lot but i want the reson now why u r not helping that way did any one force u???

    • one year ago
  73. open_study1
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    such as @vincent fr @aravind etc......

    • one year ago
  74. Kryten
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    no, but i realised that you are taking a path of least resistance which is not good... this site is for learning and not getting all solved with no effort...

    • one year ago
  75. Kryten
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    now lets skip all the debate and tell me if you want to do it with my help properly or with no help at all

    • one year ago
  76. open_study1
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    i want help

    • one year ago
  77. Kryten
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    so whats the problem then... take a look how i solved your past questions and write it all like that here step by step and with understanding and reason why is it like it is for each step so that you LEARN how to solve problems like this...

    • one year ago
  78. open_study1
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    ok let me try

    • one year ago
  79. ujjwal
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    Its been two days.. LMAO..

    • one year ago
  80. open_study1
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    yes no one seems to help me........

    • one year ago
  81. siddhantsharan
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    Is the Answer 3.33 x 10^-4 ?

    • one year ago
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