## open_study1 Group Title 50 ML of 0.001 M phosphoric acid are exactly neutralized by the addition of 0.005 N Naoh the molarity of resulting salt is? 2 years ago 2 years ago

1. open_study1 Group Title

@Callisto help

2. Callisto Group Title

Sorry.. I haven't learnt it :|

3. open_study1 Group Title

ok

4. .Sam. Group Title

$\begin{array}{c} \text{H}_3\text{P}\text{O}_4 \\\end{array}\text{ + }\begin{array}{cc} 3 & \text{Na}\text{O}\text{H} \\\end{array}\text{ \longrightarrow  }\begin{array}{cc} 3 & \text{H}_2\text{O} \\\end{array}\text{ + }\begin{array}{c} \text{Na}_3\text{P}\text{O}_4 \\\end{array}$ ------------------------------------ $M_AV_A=M_BV_B$ $\text{Molarity of base is}~~ M_B$ $\text{Molarity of acid is}~~ M_A$ ------------------------------------ $M_B=\frac{M_AV_A}{V_B}$ Sub in the values

5. Preetha Group Title

Don forget the stoichiometric ratios. for every mole of phosphoric acid, you need 3 moles of NaOH to neutralize it. So you have to include that factor of 3 in the above calculation. It is a 1: 3 not 1:1 relationship. Try it and see.

6. open_study1 Group Title

@Kryten help!

7. Kryten Group Title

as i see it you got all you need you just need to put numbers in.... only way to learn how to solve this kind of things is to do it yourself...

8. open_study1 Group Title

i solve it but not getting lol @Kryten thats why i called u

9. open_study1 Group Title

if u get after solving that then inform me

10. open_study1 Group Title

The answer should be 6.25 * 10^-4 moles

11. open_study1 Group Title

but i am not getting that @Kryten

12. Kryten Group Title

this is really basic chemistry, begin with writing equation, then write down what you have and what you need and do the magic... put the relationships of reactants and products in equations and just crunch the numbers...

13. open_study1 Group Title

@.Sam. not getting the answer by ur way

14. open_study1 Group Title

@Kryten not getting!!!

15. open_study1 Group Title

i wrote the equation

16. .Sam. Group Title

6.25 * 10^-4 moles This is in moles, I thought you want molarity?

17. open_study1 Group Title

@Kryten do u have any idea

18. open_study1 Group Title

i am confused in question it is asked to find molarity but the answer is given in 6.25*10^-4

19. Kryten Group Title

yea i have some idea but i gotta run students arent waiting i need to keep them safe... see you later

20. open_study1 Group Title

@Vincent-Lyon.Fr do u have any idea....

21. Vincent-Lyon.Fr Group Title

I won't answer any of your questions as you are pestering this study site without ever doing any effort on your own.

22. open_study1 Group Title

@Vincent-Lyon.Fr i did but not getting!

23. shivam_bhalla Group Title

@open_study1 , my answer is same as @Vincent-Lyon.Fr 's

24. open_study1 Group Title

@shivam_bhalla i tried ny level best but i am unable,

25. shivam_bhalla Group Title

@.Sam. and @Preetha have given you the valuable hints and tips . Just go ahead and solve it. you have to find the number of moles of H3PO4 initially reacting from given info

26. HairtUB Group Title

What's M and N?

27. open_study1 Group Title

M=molarity N=normality

28. open_study1 Group Title

moles = 5*10^-5 moles

29. shivam_bhalla Group Title

Yes. Now continue and do the rest of the problem.

30. open_study1 Group Title

now wat to do

I'm sorry i don't know this :).

32. open_study1 Group Title

@shivam_bhalla r u there....

33. open_study1 Group Title

Plzzz help anyone plzz!

34. open_study1 Group Title

@Kryten HELP

35. open_study1 Group Title

I FOUNDED THE MOLE THEN WAT TO DO???

36. open_study1 Group Title

@Kryten PLZZ GUIDE ME PLZZ

37. open_study1 Group Title

OH........OH..........PLZZZZ SOME ONE HELP! I AM WAITING FOR 1 DAY PLZZZZ

38. open_study1 Group Title

5*10^-5 moles

39. Kryten Group Title

in your place i would give up on pleading and solve it myself... you have been give instructions by multiple people and you just need to follow them, point is that you want it to be solved so you god forgive wouldnt have to hitch your little grey cells...

40. open_study1 Group Title

I DID IN THE WAY THEY GUIDED BUT NOT GETTING I FOUNDED THE MOLES THEN WAT TO DO PLZZ TELL ME THE STEPS I WILL SOLVE MY OWN @Kryten

41. Kryten Group Title

first send some proof that you did anything (picture of paper of your tries) and then ill help. this is i think your third time you post this question and you just need to read what people have written... look up and read all carefully

42. open_study1 Group Title

0.15=0.005*V V=30ML

43. open_study1 Group Title

0.05 MILLI MOLES OF H3PO4 ON REACTING GIVES 0.05 MILLI MOLES OF NA3PO4 IE 5*10^-5 MOLES OF NA3PO4 ARE FORMED

44. open_study1 Group Title

@Kryten

45. open_study1 Group Title

46. Kryten Group Title

now lets start from the begining write first what data you have, chemical reaction equation and then write what you need from data to be calculated

47. open_study1 Group Title

H3PO4 + 3NaOH ⟶ 3H2O + Na3PO4

48. open_study1 Group Title

WE HAVE TO FIND THE MOLARITY OF NA3PO4

49. Kryten Group Title

write your data properly ex. c(X)= ... V(X)=... c(Y)=.... and then what you need to calculate ex. c(z)=?

50. open_study1 Group Title

WAT IS C(X)

51. Kryten Group Title

that are examples how to write your data properly now lets see you do it

52. open_study1 Group Title

V(PHOSPHORIC ACID)=50ML M(PHOSPHORIC ACID)=0.001M N(NAOH)=0.005N M(NA3PO4)=?

53. open_study1 Group Title

IS THAT CORRECT.........

54. Kryten Group Title

ok now lets see you have written N(NaOH)=0,005N --> that doesnt exist cause N(NaOH) is marking of number of NaOH atoms and it has no units, and furthermore write it one under another not one next to other cause that is vast. now lets see corection...

55. open_study1 Group Title

NORMALITY OF NAOH=0.005N

56. Kryten Group Title

now please explain to me what is normality and then write all data again properly

57. open_study1 Group Title

NO OF EQUIVALENT OF SOLUTE IN ONE LITRE OF SOLUTION

58. Kryten Group Title

ok now explain me the unit N what is its derivative

59. open_study1 Group Title

N= WG OF SOLUTE /(EQUIVALENT WG OF SOLUTE * VOLUME(L))

60. Kryten Group Title

ok now when you explained it all carry on and write all data properly one item under other and under it all chemical equation

61. open_study1 Group Title

@Kryten ANYHOW THANZZZ I HAVE TO GO NOW PLZZ GIVE ALL THE HINTS I WILL LOOK IT AFTER WARDS............

62. Kryten Group Title

no way, you will write all here so i see what you are doing...

63. open_study1 Group Title

hello

64. open_study1 Group Title

@Kryten

65. Kryten Group Title

continue where you stoped, write all on one place...

66. open_study1 Group Title

thats all wat i knw

67. Kryten Group Title

but you still havent written all in one place properly

68. open_study1 Group Title

oh....no wat else u want

69. Kryten Group Title

i would like a cold bear and a steak but what you want is the question

70. open_study1 Group Title

this website was made to help!!!! so plzz

71. Kryten Group Title

i am helping you but you are resisting to it... take a look how i solved your past questions where i photographed my work, it was all in sequence like it should be and that is the only way i will help you if you do it properly and as it should be solved and when you get that routine all this will be easy for you so your choice...

72. open_study1 Group Title

yes u helped me a lot earlier by risiking a lot but i want the reson now why u r not helping that way did any one force u???

73. open_study1 Group Title

such as @vincent fr @aravind etc......

74. Kryten Group Title

no, but i realised that you are taking a path of least resistance which is not good... this site is for learning and not getting all solved with no effort...

75. Kryten Group Title

now lets skip all the debate and tell me if you want to do it with my help properly or with no help at all

76. open_study1 Group Title

i want help

77. Kryten Group Title

so whats the problem then... take a look how i solved your past questions and write it all like that here step by step and with understanding and reason why is it like it is for each step so that you LEARN how to solve problems like this...

78. open_study1 Group Title

ok let me try

79. ujjwal Group Title

Its been two days.. LMAO..

80. open_study1 Group Title

yes no one seems to help me........

81. siddhantsharan Group Title

Is the Answer 3.33 x 10^-4 ?