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open_study1 Group Title

50 ML of 0.001 M phosphoric acid are exactly neutralized by the addition of 0.005 N Naoh the molarity of resulting salt is?

  • 2 years ago
  • 2 years ago

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  1. open_study1 Group Title
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    @Callisto help

    • 2 years ago
  2. Callisto Group Title
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    Sorry.. I haven't learnt it :|

    • 2 years ago
  3. open_study1 Group Title
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    ok

    • 2 years ago
  4. .Sam. Group Title
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    \[\begin{array}{c} \text{H}_3\text{P}\text{O}_4 \\\end{array}\text{ + }\begin{array}{cc} 3 & \text{Na}\text{O}\text{H} \\\end{array}\text{ $\longrightarrow $ }\begin{array}{cc} 3 & \text{H}_2\text{O} \\\end{array}\text{ + }\begin{array}{c} \text{Na}_3\text{P}\text{O}_4 \\\end{array}\] ------------------------------------ \[M_AV_A=M_BV_B\] \[\text{Molarity of base is}~~ M_B \] \[\text{Molarity of acid is}~~ M_A\] ------------------------------------ \[M_B=\frac{M_AV_A}{V_B}\] Sub in the values

    • 2 years ago
  5. Preetha Group Title
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    Don forget the stoichiometric ratios. for every mole of phosphoric acid, you need 3 moles of NaOH to neutralize it. So you have to include that factor of 3 in the above calculation. It is a 1: 3 not 1:1 relationship. Try it and see.

    • 2 years ago
  6. open_study1 Group Title
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    @Kryten help!

    • 2 years ago
  7. Kryten Group Title
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    as i see it you got all you need you just need to put numbers in.... only way to learn how to solve this kind of things is to do it yourself...

    • 2 years ago
  8. open_study1 Group Title
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    i solve it but not getting lol @Kryten thats why i called u

    • 2 years ago
  9. open_study1 Group Title
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    if u get after solving that then inform me

    • 2 years ago
  10. open_study1 Group Title
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    The answer should be 6.25 * 10^-4 moles

    • 2 years ago
  11. open_study1 Group Title
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    but i am not getting that @Kryten

    • 2 years ago
  12. Kryten Group Title
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    this is really basic chemistry, begin with writing equation, then write down what you have and what you need and do the magic... put the relationships of reactants and products in equations and just crunch the numbers...

    • 2 years ago
  13. open_study1 Group Title
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    @.Sam. not getting the answer by ur way

    • 2 years ago
  14. open_study1 Group Title
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    @Kryten not getting!!!

    • 2 years ago
  15. open_study1 Group Title
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    i wrote the equation

    • 2 years ago
  16. .Sam. Group Title
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    6.25 * 10^-4 moles This is in moles, I thought you want molarity?

    • 2 years ago
  17. open_study1 Group Title
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    @Kryten do u have any idea

    • 2 years ago
  18. open_study1 Group Title
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    i am confused in question it is asked to find molarity but the answer is given in 6.25*10^-4

    • 2 years ago
  19. Kryten Group Title
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    yea i have some idea but i gotta run students arent waiting i need to keep them safe... see you later

    • 2 years ago
  20. open_study1 Group Title
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    @Vincent-Lyon.Fr do u have any idea....

    • 2 years ago
  21. Vincent-Lyon.Fr Group Title
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    I won't answer any of your questions as you are pestering this study site without ever doing any effort on your own.

    • 2 years ago
  22. open_study1 Group Title
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    @Vincent-Lyon.Fr i did but not getting!

    • 2 years ago
  23. shivam_bhalla Group Title
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    @open_study1 , my answer is same as @Vincent-Lyon.Fr 's

    • 2 years ago
  24. open_study1 Group Title
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    @shivam_bhalla i tried ny level best but i am unable,

    • 2 years ago
  25. shivam_bhalla Group Title
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    @.Sam. and @Preetha have given you the valuable hints and tips . Just go ahead and solve it. you have to find the number of moles of H3PO4 initially reacting from given info

    • 2 years ago
  26. HairtUB Group Title
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    What's M and N?

    • 2 years ago
  27. open_study1 Group Title
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    M=molarity N=normality

    • 2 years ago
  28. open_study1 Group Title
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    moles = 5*10^-5 moles

    • 2 years ago
  29. shivam_bhalla Group Title
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    Yes. Now continue and do the rest of the problem.

    • 2 years ago
  30. open_study1 Group Title
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    now wat to do

    • 2 years ago
  31. TheOlympicnomad Group Title
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    I'm sorry i don't know this :).

    • 2 years ago
  32. open_study1 Group Title
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    @shivam_bhalla r u there....

    • 2 years ago
  33. open_study1 Group Title
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    Plzzz help anyone plzz!

    • 2 years ago
  34. open_study1 Group Title
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    @Kryten HELP

    • 2 years ago
  35. open_study1 Group Title
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    I FOUNDED THE MOLE THEN WAT TO DO???

    • 2 years ago
  36. open_study1 Group Title
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    @Kryten PLZZ GUIDE ME PLZZ

    • 2 years ago
  37. open_study1 Group Title
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    OH........OH..........PLZZZZ SOME ONE HELP! I AM WAITING FOR 1 DAY PLZZZZ

    • 2 years ago
  38. open_study1 Group Title
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    5*10^-5 moles

    • 2 years ago
  39. Kryten Group Title
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    in your place i would give up on pleading and solve it myself... you have been give instructions by multiple people and you just need to follow them, point is that you want it to be solved so you god forgive wouldnt have to hitch your little grey cells...

    • 2 years ago
  40. open_study1 Group Title
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    I DID IN THE WAY THEY GUIDED BUT NOT GETTING I FOUNDED THE MOLES THEN WAT TO DO PLZZ TELL ME THE STEPS I WILL SOLVE MY OWN @Kryten

    • 2 years ago
  41. Kryten Group Title
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    first send some proof that you did anything (picture of paper of your tries) and then ill help. this is i think your third time you post this question and you just need to read what people have written... look up and read all carefully

    • 2 years ago
  42. open_study1 Group Title
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    0.15=0.005*V V=30ML

    • 2 years ago
  43. open_study1 Group Title
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    0.05 MILLI MOLES OF H3PO4 ON REACTING GIVES 0.05 MILLI MOLES OF NA3PO4 IE 5*10^-5 MOLES OF NA3PO4 ARE FORMED

    • 2 years ago
  44. open_study1 Group Title
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    @Kryten

    • 2 years ago
  45. open_study1 Group Title
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    DO U NEED MORE INFO?

    • 2 years ago
  46. Kryten Group Title
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    now lets start from the begining write first what data you have, chemical reaction equation and then write what you need from data to be calculated

    • 2 years ago
  47. open_study1 Group Title
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    H3PO4 + 3NaOH ⟶ 3H2O + Na3PO4

    • 2 years ago
  48. open_study1 Group Title
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    WE HAVE TO FIND THE MOLARITY OF NA3PO4

    • 2 years ago
  49. Kryten Group Title
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    write your data properly ex. c(X)= ... V(X)=... c(Y)=.... and then what you need to calculate ex. c(z)=?

    • 2 years ago
  50. open_study1 Group Title
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    WAT IS C(X)

    • 2 years ago
  51. Kryten Group Title
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    that are examples how to write your data properly now lets see you do it

    • 2 years ago
  52. open_study1 Group Title
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    V(PHOSPHORIC ACID)=50ML M(PHOSPHORIC ACID)=0.001M N(NAOH)=0.005N M(NA3PO4)=?

    • 2 years ago
  53. open_study1 Group Title
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    IS THAT CORRECT.........

    • 2 years ago
  54. Kryten Group Title
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    ok now lets see you have written N(NaOH)=0,005N --> that doesnt exist cause N(NaOH) is marking of number of NaOH atoms and it has no units, and furthermore write it one under another not one next to other cause that is vast. now lets see corection...

    • 2 years ago
  55. open_study1 Group Title
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    NORMALITY OF NAOH=0.005N

    • 2 years ago
  56. Kryten Group Title
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    now please explain to me what is normality and then write all data again properly

    • 2 years ago
  57. open_study1 Group Title
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    NO OF EQUIVALENT OF SOLUTE IN ONE LITRE OF SOLUTION

    • 2 years ago
  58. Kryten Group Title
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    ok now explain me the unit N what is its derivative

    • 2 years ago
  59. open_study1 Group Title
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    N= WG OF SOLUTE /(EQUIVALENT WG OF SOLUTE * VOLUME(L))

    • 2 years ago
  60. Kryten Group Title
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    ok now when you explained it all carry on and write all data properly one item under other and under it all chemical equation

    • 2 years ago
  61. open_study1 Group Title
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    @Kryten ANYHOW THANZZZ I HAVE TO GO NOW PLZZ GIVE ALL THE HINTS I WILL LOOK IT AFTER WARDS............

    • 2 years ago
  62. Kryten Group Title
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    no way, you will write all here so i see what you are doing...

    • 2 years ago
  63. open_study1 Group Title
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    hello

    • 2 years ago
  64. open_study1 Group Title
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    @Kryten

    • 2 years ago
  65. Kryten Group Title
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    continue where you stoped, write all on one place...

    • 2 years ago
  66. open_study1 Group Title
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    thats all wat i knw

    • 2 years ago
  67. Kryten Group Title
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    but you still havent written all in one place properly

    • 2 years ago
  68. open_study1 Group Title
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    oh....no wat else u want

    • 2 years ago
  69. Kryten Group Title
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    i would like a cold bear and a steak but what you want is the question

    • 2 years ago
  70. open_study1 Group Title
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    this website was made to help!!!! so plzz

    • 2 years ago
  71. Kryten Group Title
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    i am helping you but you are resisting to it... take a look how i solved your past questions where i photographed my work, it was all in sequence like it should be and that is the only way i will help you if you do it properly and as it should be solved and when you get that routine all this will be easy for you so your choice...

    • 2 years ago
  72. open_study1 Group Title
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    yes u helped me a lot earlier by risiking a lot but i want the reson now why u r not helping that way did any one force u???

    • 2 years ago
  73. open_study1 Group Title
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    such as @vincent fr @aravind etc......

    • 2 years ago
  74. Kryten Group Title
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    no, but i realised that you are taking a path of least resistance which is not good... this site is for learning and not getting all solved with no effort...

    • 2 years ago
  75. Kryten Group Title
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    now lets skip all the debate and tell me if you want to do it with my help properly or with no help at all

    • 2 years ago
  76. open_study1 Group Title
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    i want help

    • 2 years ago
  77. Kryten Group Title
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    so whats the problem then... take a look how i solved your past questions and write it all like that here step by step and with understanding and reason why is it like it is for each step so that you LEARN how to solve problems like this...

    • 2 years ago
  78. open_study1 Group Title
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    ok let me try

    • 2 years ago
  79. ujjwal Group Title
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    Its been two days.. LMAO..

    • 2 years ago
  80. open_study1 Group Title
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    yes no one seems to help me........

    • 2 years ago
  81. siddhantsharan Group Title
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    Is the Answer 3.33 x 10^-4 ?

    • 2 years ago
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