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catsrule332

  • 3 years ago

Simplify: (q/(q^2-r^2))/r/(r^2-q^2)

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  1. Luis_Rivera
    • 3 years ago
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    \[\frac{q }{(q-r)(q+r) }*\frac{ r^2-q^2}{r }\\ \frac{q }{ (q-r)(q+r) }*\frac{( r-q)(r+q )}{r }\\\\ \frac{q }{ (q-r)(q+r) }*\frac{-1( q-r)(q+r )}{r }\\\\ \frac{q }{ (\cancel{q-r)(q+r)} }*\frac{-1\cancel{( q-r)(q+r )}}{r }\\\\ =\frac{-q }{ r } \]

  2. catsrule332
    • 3 years ago
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    What if it was addition instead of multiplication?

  3. jhonyy9
    • 3 years ago
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    when you need divide two fractions just multiplie first by second inversed

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