## JoãoVitorMC 3 years ago Consider the reaction of aluminum chloride with silver acetate. How ml of 0.250M aluminum chloride are required to react completely with 20ml of 0.500M silver acetate?

1. JoãoVitorMC

AlCl3 + 3(AgC2H3O2) -> Al(C2H3O2)3 + 3(AgCl)

2. Australopithecus

Yes I was about to tell you to post that

3. Australopithecus

First off recognize that Molarity = moles/Liters

4. Australopithecus

You have a volume 20ml of 0.500M acetate

5. Australopithecus

Thus you can say x moles/0.02L = 0.500M of acetate solve for the moles

6. Australopithecus

Look at the ratio you have 3 times the moles of silver acetate for everyone one mole of aluminum chloride

7. Australopithecus

Since the division cancels multiplication you simply divide the number of moles of silver acetate by 3 to solve for the moles of aluminum chloride

8. Australopithecus

This will give you the moles, since you have the concentration of aluminum chloride you can just sub them into the equation to solve for the liters Molarity = moles/liters

9. Australopithecus

remember the conversion Liters * 1000 = mL mL/1000 = Liters

10. Australopithecus

if you have questions about the basic algebra feel free to ask

11. JoãoVitorMC

Thanks a lot! i'll try this now

12. Australopithecus

alright if you have problems show your work and I can help have lecture now though so yeah

13. JoãoVitorMC

i did the this: 1 mole of AlCl3 -> 3 moles of AgC2H3O2 x -> 0.01 so x= 0.0033. 0.5 = 0.003/volume , volume = 0.0066, is it right?

14. Australopithecus

0.500M = x/0.020L x = 0.500M*0.020L x=0.01moles 0.01moles/3 = 0.0033mol of Ag acetate thus 0.250M = 0.0033mol/x 0.0033mol/0.250 = x x = 0.013L

15. Australopithecus

0.013L = 13mL

16. JoãoVitorMC

oh! that it! now i realize that. Thanks !!

17. Australopithecus

I think you made a mistake with your algebra remember Molarity = Moles/Volume thus you have 0.250M = 0.0033mol/x = 0.250M*x = 0.0033mol*x/x = 0.250M*x = 0.0033mol = 0.250M*x/0.250M = 0.0033mol/0.250M = x = 0.0033mol/0.250M

18. Australopithecus

here are all the steps

19. Australopithecus

remember you want to bring the x into the numerator and isolate it

20. Australopithecus

you never want it in the denominator

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