Assume that 25 ml of 0.440M NaCl are added to 25 ml of 0.320M AgNO3.
How many moles of AgCl precipitate is?
NaCl + AgNO3 -> NaNO3 + AgCl
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this is matter of limiting reagent, so you need to calculate amount of each reactant which i assume you know how to. then you need to see ratio in which reactant react to give products and in this case it is 1:1 so now you only take a look which of the reactant is less in 25 ml he will be limiting reagent and that amount of your product will be created. i calculated and your answer is 0,008 moles. if you get stuck or are unsure about any part just say and me or somebody else will clear it up...
hope it helps.