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## anonymous 4 years ago I just confused myself trying this : 1/sin^2(x) + Sec^2(x)/Tan^2(x)

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1. anonymous

change everything in terms of sines and cosines $\sec^2 x = \frac{1}{\cos^2 x}$ $\tan^2 x = \frac{\sin^2 x}{\cos^2 x}$

2. anonymous

$\large \frac{\sec^2 x}{\tan ^2 x} = \frac{\frac{1}{\cos^2 x}}{\frac{\sin^2 x}{\cos^2 x}}$ does that help?

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