## catsrule332 3 years ago Solve the following equation for x. *Attached file

1. catsrule332

2. mathteacher1729

How far have you gotten before getting stuck?

3. catsrule332

I started by multiplying both sides by the (√4x-3) base. That's about it

4. pfenn1

$2\sqrt{x}-(\sqrt{4x}-3)=\frac{1}{\sqrt{4x}-3}$Note that$\sqrt{4x}=2\sqrt{x}$Therefore we can rewrite the equation$\cancel{2\sqrt{x}}-\cancel{2\sqrt{x}}+3=\frac{1}{2\sqrt{x}-3}$Multiply both sides by the denominator$3(2\sqrt{x}-3)=1$$6\sqrt{x}=10$$\sqrt{x}=\frac{10}{6}=\frac53$$x=\frac{5^2}{3^2}=\frac{25}{9}$

5. hreeg97

x=5232=259