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deiboureijane16

The New Line. HELP

  • one year ago
  • one year ago

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  1. deiboureijane16
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    A line has the same slope as the line represented by 4x - 3y +15 =0 and the same y-intercept as the line represented by 2x + y +6=0

    • one year ago
  2. deiboureijane16
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    Determine the equation of this line.

    • one year ago
  3. MrYantho
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    1. First determine the slope of your existing line by placing in y=mx+b form and getting m 2. Determine the y-0int of the other line by placing in y=mx+b form and taking the b value

    • one year ago
  4. Sera
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    The slope of the first equation: 3y=4x+15 y=(4/3)x+5 slpe is 4/3 Intercept of the second equation: y=-2x-6 intercept is -6 So the final equation is y=(4/3)x-6

    • one year ago
  5. deiboureijane16
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    why did it turn from a 15 to a 5?

    • one year ago
  6. Sera
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    divide 15 by the coefficient of y, which is 3

    • one year ago
  7. deiboureijane16
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    why is the 4x not turned to a -4x but for the 2x it was turned to a -2x?

    • one year ago
  8. alexwee123
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    because when you isolate y in 4x - 3y +15 =0 you would subtract 15 and 4x on both sides then divide by -3 -3y=-4x-15 y=4/3x+5

    • one year ago
  9. alexwee123
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    same thing for the second equation

    • one year ago
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