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deiboureijane16

  • 3 years ago

The New Line. HELP

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  1. deiboureijane16
    • 3 years ago
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    A line has the same slope as the line represented by 4x - 3y +15 =0 and the same y-intercept as the line represented by 2x + y +6=0

  2. deiboureijane16
    • 3 years ago
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    Determine the equation of this line.

  3. MrYantho
    • 3 years ago
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    1. First determine the slope of your existing line by placing in y=mx+b form and getting m 2. Determine the y-0int of the other line by placing in y=mx+b form and taking the b value

  4. Sera
    • 3 years ago
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    The slope of the first equation: 3y=4x+15 y=(4/3)x+5 slpe is 4/3 Intercept of the second equation: y=-2x-6 intercept is -6 So the final equation is y=(4/3)x-6

  5. deiboureijane16
    • 3 years ago
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    why did it turn from a 15 to a 5?

  6. Sera
    • 3 years ago
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    divide 15 by the coefficient of y, which is 3

  7. deiboureijane16
    • 3 years ago
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    why is the 4x not turned to a -4x but for the 2x it was turned to a -2x?

  8. alexwee123
    • 3 years ago
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    because when you isolate y in 4x - 3y +15 =0 you would subtract 15 and 4x on both sides then divide by -3 -3y=-4x-15 y=4/3x+5

  9. alexwee123
    • 3 years ago
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    same thing for the second equation

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