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anonymous
 4 years ago
Find the volume generated by revolving the area bounded by y^2=x^3 , x=4
about x=1
I can't understand how the area will revolve about a line lying on the area Many thanks in advance
anonymous
 4 years ago
Find the volume generated by revolving the area bounded by y^2=x^3 , x=4 about x=1 I can't understand how the area will revolve about a line lying on the area Many thanks in advance

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lemme refer you to a problem a professor did yesterday.. very similar to this...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1338364929318:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here's the link. Dr. Saab did this with qawarrior and later warrior said hid professor marked it incorrect... http://openstudy.com/users/qrawarrior#/updates/4fc43380e4b0964abc86cdda

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i dunno what to tell u...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but we studied it ?? am so confused :S Thank you for helping me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0normally, if the axis of rotation is on the boundary or outside the boundary i'd be happy to help out.. but idk what to do in this case because the axis lies inside the region to be rotated...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the axis of rotation part of the boundary?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1338365578147:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no it is not a boundary

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1338365720645:dw which area I have to choose

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@dpaInc I did tow problems for him. I believe both of my solutions are correct.
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