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helpmewithmathclass!

  • 3 years ago

Solve. 3^x-5 = 9 also how do i find what is x?

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  1. ParthKohli
    • 3 years ago
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    Equate the bases please. \(\Large \color{MidnightBlue}{\Rightarrow 3^{x - 5} = 3^2 }\) Equate the exponents. \(\Large \color{MidnightBlue}{\Rightarrow x - 5 = 2 }\) \(\Large \color{MidnightBlue}{\Rightarrow x = 7 }\)

  2. helpmewithmathclass!
    • 3 years ago
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    why 2?

  3. ParthKohli
    • 3 years ago
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    I have made an equation of the exponents.

  4. helpmewithmathclass!
    • 3 years ago
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    ohh

  5. ParthKohli
    • 3 years ago
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    \(\Large \color{MidnightBlue}{\Rightarrow a^m = a^n \Rightarrow m = n }\)

  6. helpmewithmathclass!
    • 3 years ago
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    7^x - 5 = 74^x + 7 so what about that one?

  7. Thatsmeh
    • 3 years ago
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    Wait 9+5=14 so wouldn't whatever x be have to end up at 14?

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