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AcidRa1n

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  • one year ago
  • one year ago

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  1. AcidRa1n
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    • one year ago
  2. AcidRa1n
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    Ok how does angle C equal 20 and PS is 5?

    • one year ago
  3. AcidRa1n
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    Unkle it's not that hard come on...

    • one year ago
  4. UnkleRhaukus
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    there are 360° in a complete revolution, angle C is 1 eighteenth of the wayround \[\angle C=360°/18\]

    • one year ago
  5. AcidRa1n
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    wait what so how its it 20 on there?

    • one year ago
  6. UnkleRhaukus
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    did you simplify \(\angle C =\frac{360°}{18}=\dots\)

    • one year ago
  7. AcidRa1n
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    ohhh

    • one year ago
  8. UnkleRhaukus
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    \[36=2\times18\] \[360=2 \times 18\times10\]

    • one year ago
  9. AcidRa1n
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    How would you find the area?

    • one year ago
  10. UnkleRhaukus
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    well the shape can be see as 18 of those little right angled triangle joined together, find the area of one then multiply by 18

    • one year ago
  11. UnkleRhaukus
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    |dw:1338432746562:dw|

    • one year ago
  12. AcidRa1n
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    ok wait

    • one year ago
  13. AcidRa1n
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    I have a diferent problem on my notes.. Same shape but it says each side = 4

    • one year ago
  14. AcidRa1n
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    What is the area.

    • one year ago
  15. AcidRa1n
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    |dw:1338433164896:dw|

    • one year ago
  16. AcidRa1n
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    like that

    • one year ago
  17. UnkleRhaukus
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    you can find length CS = a using a trigonometric function of the angle 20°

    • one year ago
  18. AcidRa1n
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    Lets say the question only give you the length of one side is 4

    • one year ago
  19. AcidRa1n
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    How would you go about finding the area?

    • one year ago
  20. UnkleRhaukus
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    |dw:1338432905847:dw|

    • one year ago
  21. AcidRa1n
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    |dw:1338433361442:dw|

    • one year ago
  22. AcidRa1n
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    Thats all it gives you. Find the area. I know it has something to do with finding the apothem and finding the perimeter and using the TAN function.

    • one year ago
  23. AcidRa1n
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    Half of one side is 2.

    • one year ago
  24. UnkleRhaukus
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    \[\tan(20°)=\frac{\text{opposite}}{\text{adjacent}}=\frac5a\] \[a=\frac 5{\tan(20°)}\neq4\]

    • one year ago
  25. UnkleRhaukus
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    or is the 4 coming from a different problem/

    • one year ago
  26. UnkleRhaukus
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    the diagram posed at the top of the page does not have any side- length equal to 4

    • one year ago
  27. AcidRa1n
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    4 from a different problem

    • one year ago
  28. UnkleRhaukus
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    OK, what is the new problem exactly/

    • one year ago
  29. AcidRa1n
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    What I drew that's all it gives me

    • one year ago
  30. AcidRa1n
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    A decagon with a side lengths of 4. Find the Area.

    • one year ago
  31. UnkleRhaukus
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    well the first one was a nonagon so the picture is wrong

    • one year ago
  32. AcidRa1n
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    RAWRRRRRRRRR I HATE MATH SO MUCH OMFG

    • one year ago
  33. UnkleRhaukus
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    |dw:1338433609250:dw|

    • one year ago
  34. AcidRa1n
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    I DONT HAVE TIME FOR THISSSS I WANNA SLEEP

    • one year ago
  35. AcidRa1n
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    Yes now find the area. Just with that information.

    • one year ago
  36. UnkleRhaukus
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    well should i sing you a lullaby instead ?

    • one year ago
  37. AcidRa1n
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    LOL

    • one year ago
  38. UnkleRhaukus
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    ok so you might want to find the angle in triangle first, remember there are 360° in a revolution and i count 10 angles, so the angle in is \[360°/10\]

    • one year ago
  39. UnkleRhaukus
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    next find the length of the perpendicular , using the angle you just found and the tangent function

    • one year ago
  40. UnkleRhaukus
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    |dw:1338433908040:dw|, find the area of the triangle and lastly multiply this area by the number of those triangles in the decagon

    • one year ago
  41. AcidRa1n
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    360/10 =36? When I apply the TAN to 36 it's weird...

    • one year ago
  42. AcidRa1n
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    @UnkleRhaukus

    • one year ago
  43. UnkleRhaukus
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    true, what did you determine as an approximation of length b

    • one year ago
  44. UnkleRhaukus
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    2 significant figures is probably fine

    • one year ago
  45. AcidRa1n
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    huh? I didnt get that far becuase I thought you need to know the TAN of 36

    • one year ago
  46. AcidRa1n
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    @satellite73

    • one year ago
  47. UnkleRhaukus
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    yeah \[\tan(36°)\approx0.727\]

    • one year ago
  48. AcidRa1n
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    ok.. Let me see

    • one year ago
  49. UnkleRhaukus
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    \[\tan(36°)=\frac{\text{opp}}{\text{adj}}=\frac 2 b\] \[b=\frac {2}{\tan36°}\approx\cdots\]

    • one year ago
  50. AcidRa1n
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    why is it b= 2/tan36?

    • one year ago
  51. AcidRa1n
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    Ohh I got it

    • one year ago
  52. AcidRa1n
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    so its 2.75

    • one year ago
  53. UnkleRhaukus
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    we are trying to find \(b\) so we can work out the are of the triangle \[\tan(36°)=\frac{\text{opp}}{\text{adj}}=\frac 2 b\] multiply both sides by \(b\) then divide both sides by \(\tan36°\)

    • one year ago
  54. UnkleRhaukus
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    yes \(b\approx 2.75\)

    • one year ago
  55. AcidRa1n
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    so then after we find the area which is 2.752 we take the perimeter which is 40, and do 1/2* 2.752* 40

    • one year ago
  56. UnkleRhaukus
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    find the area of this triangle |dw:1338435087210:dw|

    • one year ago
  57. UnkleRhaukus
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    \[A_{\triangle}=\frac{ab}2=\frac {2b}2=\cdots\]

    • one year ago
  58. UnkleRhaukus
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    you dont need the perimeter

    • one year ago
  59. AcidRa1n
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    My notes has it O.o

    • one year ago
  60. AcidRa1n
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    Maybe hes teaching it like that?

    • one year ago
  61. AcidRa1n
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    THe formula for Area is. 1/2 * Apothem * perimeter

    • one year ago
  62. UnkleRhaukus
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    whatever, my method is better ~ so the area of the small right angled triangle is 2.752 and there are 20 of these in the decagon the the total area is simply \(A_{decagon}=2.752\times20=\cdots\)

    • one year ago
  63. AcidRa1n
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    Yeah lol same thing I got.

    • one year ago
  64. AcidRa1n
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    Well, thanks for taking like 30 minutes of your time to help me lol.

    • one year ago
  65. AcidRa1n
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    I'm so dumb.

    • one year ago
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