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Ok how does angle C equal 20 and PS is 5?
Unkle it's not that hard come on...

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there are 360° in a complete revolution, angle C is 1 eighteenth of the wayround \[\angle C=360°/18\]
wait what so how its it 20 on there?
did you simplify \(\angle C =\frac{360°}{18}=\dots\)
ohhh
\[36=2\times18\] \[360=2 \times 18\times10\]
How would you find the area?
well the shape can be see as 18 of those little right angled triangle joined together, find the area of one then multiply by 18
|dw:1338432746562:dw|
ok wait
I have a diferent problem on my notes.. Same shape but it says each side = 4
What is the area.
|dw:1338433164896:dw|
like that
you can find length CS = a using a trigonometric function of the angle 20°
Lets say the question only give you the length of one side is 4
How would you go about finding the area?
|dw:1338432905847:dw|
|dw:1338433361442:dw|
Thats all it gives you. Find the area. I know it has something to do with finding the apothem and finding the perimeter and using the TAN function.
Half of one side is 2.
\[\tan(20°)=\frac{\text{opposite}}{\text{adjacent}}=\frac5a\] \[a=\frac 5{\tan(20°)}\neq4\]
or is the 4 coming from a different problem/
the diagram posed at the top of the page does not have any side- length equal to 4
4 from a different problem
OK, what is the new problem exactly/
What I drew that's all it gives me
A decagon with a side lengths of 4. Find the Area.
well the first one was a nonagon so the picture is wrong
RAWRRRRRRRRR I HATE MATH SO MUCH OMFG
|dw:1338433609250:dw|
I DONT HAVE TIME FOR THISSSS I WANNA SLEEP
Yes now find the area. Just with that information.
well should i sing you a lullaby instead ?
LOL
ok so you might want to find the angle in triangle first, remember there are 360° in a revolution and i count 10 angles, so the angle in is \[360°/10\]
next find the length of the perpendicular , using the angle you just found and the tangent function
|dw:1338433908040:dw|, find the area of the triangle and lastly multiply this area by the number of those triangles in the decagon
360/10 =36? When I apply the TAN to 36 it's weird...
true, what did you determine as an approximation of length b
2 significant figures is probably fine
huh? I didnt get that far becuase I thought you need to know the TAN of 36
yeah \[\tan(36°)\approx0.727\]
ok.. Let me see
\[\tan(36°)=\frac{\text{opp}}{\text{adj}}=\frac 2 b\] \[b=\frac {2}{\tan36°}\approx\cdots\]
why is it b= 2/tan36?
Ohh I got it
so its 2.75
we are trying to find \(b\) so we can work out the are of the triangle \[\tan(36°)=\frac{\text{opp}}{\text{adj}}=\frac 2 b\] multiply both sides by \(b\) then divide both sides by \(\tan36°\)
yes \(b\approx 2.75\)
so then after we find the area which is 2.752 we take the perimeter which is 40, and do 1/2* 2.752* 40
find the area of this triangle |dw:1338435087210:dw|
\[A_{\triangle}=\frac{ab}2=\frac {2b}2=\cdots\]
you dont need the perimeter
My notes has it O.o
Maybe hes teaching it like that?
THe formula for Area is. 1/2 * Apothem * perimeter
whatever, my method is better ~ so the area of the small right angled triangle is 2.752 and there are 20 of these in the decagon the the total area is simply \(A_{decagon}=2.752\times20=\cdots\)
Yeah lol same thing I got.
Well, thanks for taking like 30 minutes of your time to help me lol.
I'm so dumb.

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