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## zaphod 3 years ago Please i need the question b) only thanks

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1. zaphod
2. zaphod

@ParthKohli @AccessDenied @Aadarsh

3. Aadarsh

easy 1minute I am answering u now

4. Aadarsh

Angle CDX = 56, so, 1/2 angle CDX = angle XDB = 28 dehrees

5. zaphod

okay thanks :)

6. ninhi5

they never say CDX = XDB

7. ninhi5

so you have to prove by complimentary angles

8. zaphod

because it is a parellelogram we can prove right?

9. ninhi5

i used equal angles to prove it

10. zaphod

show me ur method?

11. Aadarsh

Given, CD is parallel to EB, so angle CDX = angle EDX = 56 degrees. So, angle DXB = 180 - 56 = 124 degrees

12. Aadarsh

So, angle XBD = 180 - (124+28) = 28 degrees = angle BDX Hence, traingle BDX is isosceles

13. ninhi5

EB // DC => BDC = EBD EBD = EAD => EA // BD => AEB = ADB => EBD = EBD => BDX isosceles

14. zaphod

thanks once again guyz :D

15. ninhi5

no pb

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