anonymous
  • anonymous
Please i need the question b) only thanks
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
http://screencast.com/t/CciNQSaVQjmD
anonymous
  • anonymous
anonymous
  • anonymous
easy 1minute I am answering u now

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anonymous
  • anonymous
Angle CDX = 56, so, 1/2 angle CDX = angle XDB = 28 dehrees
anonymous
  • anonymous
okay thanks :)
anonymous
  • anonymous
they never say CDX = XDB
anonymous
  • anonymous
so you have to prove by complimentary angles
anonymous
  • anonymous
because it is a parellelogram we can prove right?
anonymous
  • anonymous
i used equal angles to prove it
anonymous
  • anonymous
show me ur method?
anonymous
  • anonymous
Given, CD is parallel to EB, so angle CDX = angle EDX = 56 degrees. So, angle DXB = 180 - 56 = 124 degrees
anonymous
  • anonymous
So, angle XBD = 180 - (124+28) = 28 degrees = angle BDX Hence, traingle BDX is isosceles
anonymous
  • anonymous
EB // DC => BDC = EBD EBD = EAD => EA // BD => AEB = ADB => EBD = EBD => BDX isosceles
anonymous
  • anonymous
thanks once again guyz :D
anonymous
  • anonymous
no pb

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