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zaphod Group Title

Please i need the question b) only thanks

  • 2 years ago
  • 2 years ago

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  1. zaphod Group Title
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    http://screencast.com/t/CciNQSaVQjmD

    • 2 years ago
  2. zaphod Group Title
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    @ParthKohli @AccessDenied @Aadarsh

    • 2 years ago
  3. Aadarsh Group Title
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    easy 1minute I am answering u now

    • 2 years ago
  4. Aadarsh Group Title
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    Angle CDX = 56, so, 1/2 angle CDX = angle XDB = 28 dehrees

    • 2 years ago
  5. zaphod Group Title
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    okay thanks :)

    • 2 years ago
  6. ninhi5 Group Title
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    they never say CDX = XDB

    • 2 years ago
  7. ninhi5 Group Title
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    so you have to prove by complimentary angles

    • 2 years ago
  8. zaphod Group Title
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    because it is a parellelogram we can prove right?

    • 2 years ago
  9. ninhi5 Group Title
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    i used equal angles to prove it

    • 2 years ago
  10. zaphod Group Title
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    show me ur method?

    • 2 years ago
  11. Aadarsh Group Title
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    Given, CD is parallel to EB, so angle CDX = angle EDX = 56 degrees. So, angle DXB = 180 - 56 = 124 degrees

    • 2 years ago
  12. Aadarsh Group Title
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    So, angle XBD = 180 - (124+28) = 28 degrees = angle BDX Hence, traingle BDX is isosceles

    • 2 years ago
  13. ninhi5 Group Title
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    EB // DC => BDC = EBD EBD = EAD => EA // BD => AEB = ADB => EBD = EBD => BDX isosceles

    • 2 years ago
  14. zaphod Group Title
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    thanks once again guyz :D

    • 2 years ago
  15. ninhi5 Group Title
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    no pb

    • 2 years ago
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