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zaphod
 3 years ago
Please i need the question b) only thanks
zaphod
 3 years ago
Please i need the question b) only thanks

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zaphod
 3 years ago
Best ResponseYou've already chosen the best response.1@ParthKohli @AccessDenied @Aadarsh

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1easy 1minute I am answering u now

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Angle CDX = 56, so, 1/2 angle CDX = angle XDB = 28 dehrees

ninhi5
 3 years ago
Best ResponseYou've already chosen the best response.0they never say CDX = XDB

ninhi5
 3 years ago
Best ResponseYou've already chosen the best response.0so you have to prove by complimentary angles

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.1because it is a parellelogram we can prove right?

ninhi5
 3 years ago
Best ResponseYou've already chosen the best response.0i used equal angles to prove it

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Given, CD is parallel to EB, so angle CDX = angle EDX = 56 degrees. So, angle DXB = 180  56 = 124 degrees

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1So, angle XBD = 180  (124+28) = 28 degrees = angle BDX Hence, traingle BDX is isosceles

ninhi5
 3 years ago
Best ResponseYou've already chosen the best response.0EB // DC => BDC = EBD EBD = EAD => EA // BD => AEB = ADB => EBD = EBD => BDX isosceles

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.1thanks once again guyz :D
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