zaphod
Please i need the question b) only thanks



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zaphod
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@ParthKohli @AccessDenied @Aadarsh

Aadarsh
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easy 1minute I am answering u now

Aadarsh
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Angle CDX = 56, so, 1/2 angle CDX = angle XDB = 28 dehrees

zaphod
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okay thanks :)

ninhi5
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they never say CDX = XDB

ninhi5
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so you have to prove by complimentary angles

zaphod
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because it is a parellelogram we can prove right?

ninhi5
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i used equal angles to prove it

zaphod
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show me ur method?

Aadarsh
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Given, CD is parallel to EB, so angle CDX = angle EDX = 56 degrees. So, angle DXB = 180  56 = 124 degrees

Aadarsh
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So, angle XBD = 180  (124+28) = 28 degrees = angle BDX
Hence, traingle BDX is isosceles

ninhi5
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EB // DC => BDC = EBD
EBD = EAD => EA // BD => AEB = ADB
=> EBD = EBD => BDX isosceles

zaphod
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thanks once again guyz :D

ninhi5
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no pb