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zaphod

  • 2 years ago

Please i need the question b) only thanks

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  1. zaphod
    • 2 years ago
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    http://screencast.com/t/CciNQSaVQjmD

  2. zaphod
    • 2 years ago
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    @ParthKohli @AccessDenied @Aadarsh

  3. Aadarsh
    • 2 years ago
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    easy 1minute I am answering u now

  4. Aadarsh
    • 2 years ago
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    Angle CDX = 56, so, 1/2 angle CDX = angle XDB = 28 dehrees

  5. zaphod
    • 2 years ago
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    okay thanks :)

  6. ninhi5
    • 2 years ago
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    they never say CDX = XDB

  7. ninhi5
    • 2 years ago
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    so you have to prove by complimentary angles

  8. zaphod
    • 2 years ago
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    because it is a parellelogram we can prove right?

  9. ninhi5
    • 2 years ago
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    i used equal angles to prove it

  10. zaphod
    • 2 years ago
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    show me ur method?

  11. Aadarsh
    • 2 years ago
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    Given, CD is parallel to EB, so angle CDX = angle EDX = 56 degrees. So, angle DXB = 180 - 56 = 124 degrees

  12. Aadarsh
    • 2 years ago
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    So, angle XBD = 180 - (124+28) = 28 degrees = angle BDX Hence, traingle BDX is isosceles

  13. ninhi5
    • 2 years ago
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    EB // DC => BDC = EBD EBD = EAD => EA // BD => AEB = ADB => EBD = EBD => BDX isosceles

  14. zaphod
    • 2 years ago
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    thanks once again guyz :D

  15. ninhi5
    • 2 years ago
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    no pb

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