anonymous
  • anonymous
a block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. if a force F is applied at one end of the rope, what is the force which the rope exerts on the block?
MIT 8.01 Physics I Classical Mechanics, Fall 1999
schrodinger
  • schrodinger
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yash2651995
  • yash2651995
F.. action reaction pair.. (rope is taut, assumed.. jo ho gaa hi..)
anonymous
  • anonymous
thanks!!
anonymous
  • anonymous
I think it will be a little less than F (depending upon mass of rope). This is because the tension in the rope is not constant as the rope is having mass and is accelerated under the force F and the force that the block applies on it (Let it be F1) Acceleration of system is: F/(M+m) So net force on rope = m*(F/(M+m)) {m*a} i.e. F-F1=m*(F/M+m) F1 =M*(F/M+m) And this is the required answer

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