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anonymous
 4 years ago
a block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. if a force F is applied at one end of the rope, what is the force which the rope exerts on the block?
anonymous
 4 years ago
a block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. if a force F is applied at one end of the rope, what is the force which the rope exerts on the block?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0F.. action reaction pair.. (rope is taut, assumed.. jo ho gaa hi..)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think it will be a little less than F (depending upon mass of rope). This is because the tension in the rope is not constant as the rope is having mass and is accelerated under the force F and the force that the block applies on it (Let it be F1) Acceleration of system is: F/(M+m) So net force on rope = m*(F/(M+m)) {m*a} i.e. FF1=m*(F/M+m) F1 =M*(F/M+m) And this is the required answer
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