anonymous
  • anonymous
PLEASE HELP!!! (medal will go to best answer) Exactly 4 actors try out for the 4 parts in a play. If each actor can perform an one part and no one will perform more than one part, how many different assignments of actors are possible? Thanks! :)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
This is how i do this question: Depending on how many different parts, i make 4 underscores, _ _ _ _ and fill each number up with 4, 3, 2, 1 4 actors can tryout for the first part, 3 actors try out for the second part (because one actor get the first part so he doesnt count), 2 actors tryout for the 3rd part (because another actor gets the 2nd part) ..etc get the drift? so in the end you do 4X3X2X1= 24 assignments is that the answer barlow?
anonymous
  • anonymous
Wow! Thanks so much! Yes, I'm assuming that that's the answer - I don't have the answers in front of me, but that sounds correct.
anonymous
  • anonymous
awww mention not barlow:)

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