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comput313 Group Title

How many combinations are possible if a committee of 3 is chosen from a group of 25 people?

  • 2 years ago
  • 2 years ago

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  1. ParthKohli Group Title
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    obviously 25c3. Because we are choosing 3 from 25.

    • 2 years ago
  2. LyraElizabethAdams Group Title
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    There is a total of 2,300 combinations.

    • 2 years ago
  3. LyraElizabethAdams Group Title
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    *are

    • 2 years ago
  4. ParthKohli Group Title
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    \(\Large \color{Black}{\Rightarrow 25c3 = {25! \over (25 - 3)! \times 3!} }\)

    • 2 years ago
  5. ParthKohli Group Title
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    Looks like someone just answered it.

    • 2 years ago
  6. LyraElizabethAdams Group Title
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    Remember - this is a combination problem, so you want to do 25 C 3. When you do that, you are finding out the total number of combinations that you could possibly have. Also, remember that combinations can repeat.

    • 2 years ago
  7. comput313 Group Title
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    so 2300 is the answer?

    • 2 years ago
  8. ParthKohli Group Title
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    Yes.

    • 2 years ago
  9. LyraElizabethAdams Group Title
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    Yes, 2300 is the answer.

    • 2 years ago
  10. comput313 Group Title
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    thanks

    • 2 years ago
  11. LyraElizabethAdams Group Title
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    You're very welcome! =)

    • 2 years ago
  12. LyraElizabethAdams Group Title
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    Sorry - @ParthKohli - I'm not sure what you mean?

    • 2 years ago
  13. ParthKohli Group Title
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    Maybe the moderators will tell you about it

    • 2 years ago
  14. LyraElizabethAdams Group Title
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    Did I do something wrong?

    • 2 years ago
  15. LyraElizabethAdams Group Title
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    Did I do something wrong? What do the moderators need to tell me about - I'm confused.

    • 2 years ago
  16. Calcmathlete Group Title
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    @LyraElizabethAdams It's probably that you should show the steps or help them get the answer rather than just blurt it out.

    • 2 years ago
  17. LyraElizabethAdams Group Title
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    OH, I see! Okay - sorry! I thought that since I put the explanation beneath the answer, that was pretty much the same. I'll remember that next time. Thanks! :)

    • 2 years ago
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