## anonymous 4 years ago Solve. 3x2 = 33x – 27

1. anonymous

$3x^2-33x+27=0$ the roots are: $[-(-33)\pm \sqrt{33^2-4*3*27}]/2*3$

2. anonymous

$x1=(33+\sqrt{765})/6$ $x2=(33-\sqrt{765})/6$

3. anonymous

4. anonymous

because for my answer choices i cant seem to figure which is correct

5. anonymous

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