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Soni-kay

  • 2 years ago

the value of (sin 60)(cos 60) is

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  1. lgbasallote
    • 2 years ago
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    are you asked to use trig theorems? or just evaluate it?

  2. lgbasallote
    • 2 years ago
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    coz idk theorems...but i can give you the value

  3. Soni-kay
    • 2 years ago
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    ok

  4. lgbasallote
    • 2 years ago
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    \[\sin (60) = \frac{\sqrt 3}{2}\] \[\cos (60) = \frac{1}{2}\] therefore \[(\sin 60)(\cos 60) = \frac{\sqrt 3}{2} \times \frac{1}{2} = \frac{\sqrt 3}{4}\]

  5. Soni-kay
    • 2 years ago
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    Ty ^^

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