Sonikay
the value of (sin 60)(cos 60) is



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lgbasallote
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are you asked to use trig theorems? or just evaluate it?

lgbasallote
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coz idk theorems...but i can give you the value

Sonikay
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ok

lgbasallote
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\[\sin (60) = \frac{\sqrt 3}{2}\] \[\cos (60) = \frac{1}{2}\] therefore \[(\sin 60)(\cos 60) = \frac{\sqrt 3}{2} \times \frac{1}{2} = \frac{\sqrt 3}{4}\]

Sonikay
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Ty ^^