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lgbasalloteBest ResponseYou've already chosen the best response.1
are you asked to use trig theorems? or just evaluate it?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
coz idk theorems...but i can give you the value
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
\[\sin (60) = \frac{\sqrt 3}{2}\] \[\cos (60) = \frac{1}{2}\] therefore \[(\sin 60)(\cos 60) = \frac{\sqrt 3}{2} \times \frac{1}{2} = \frac{\sqrt 3}{4}\]
 one year ago
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