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help me solve this problem by quadratic formula: y^2+7y-6=0

Mathematics
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quadratic formula is \[\large y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] do you know which is a, b and c in your problem?
a=1, b=7, c=-6
so, i plugged in the numbers and I got 7+- the square root of 53 over 2...I do not think that is right.

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Other answers:

Go back and recheck your formula. You probably forgot to attach your negative sign to b.
check your b^-4ac
okay, -7+- the square root of 73, over 2.
did I get that right this time?
yes :) good job!

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