deedee28
help me solve this problem by quadratic formula: y^2+7y6=0



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lgbasallote
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quadratic formula is \[\large y = \frac{b \pm \sqrt{b^2  4ac}}{2a}\] do you know which is a, b and c in your problem?

deedee28
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a=1, b=7, c=6

deedee28
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so, i plugged in the numbers and I got 7+ the square root of 53 over 2...I do not think that is right.

i<3science
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Go back and recheck your formula. You probably forgot to attach your negative sign to b.

i<3science
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check your b^4ac

deedee28
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okay, 7+ the square root of 73, over 2.

deedee28
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did I get that right this time?

i<3science
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yes :) good job!