PLEASE HELP http://i.imgur.com/GVvd6.png

- anonymous

PLEASE HELP http://i.imgur.com/GVvd6.png

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- schrodinger

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- anonymous

5. PIE12
6. PIE36
Is that right?

- Mertsj

|dw:1338516252471:dw|

- Mertsj

3. 3sqrt3

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## More answers

- Mertsj

|dw:1338516418696:dw|

- Mertsj

Radius of circle = 6 since the triangles are equilateral. So circumference = 2(6)pi=12pi

- Mertsj

Area of circle = 36 pi

- Mertsj

Do you mean how many degrees in each interior angle?

- anonymous

nvm

- anonymous

Can you check my other answers? I'm dont with all of them here, I need to scan it again

- anonymous

done*

- Mertsj

I got 8.3 for the apothem of the pentagon. Your setup seems to be right. Also you need to pay more attention to the form of the answers in both questions.

- Mertsj

\[\tan 36=\frac{6}{b}\]
\[b \tan 36=6\]
\[b=\frac{6}{\tan 36}=8.3\]

- Mertsj

Therefore the area of the pentagon = 5(1/2)(12)(8.3)=247.7

- Mertsj

Slant height =
\[\sqrt{(8.3)^2+(10)^2}=13.0\]

- Mertsj

Surface = 5(1/2)(13.0)(12)+247.7=637.7

- Mertsj

\[V=\frac{1}{3}(247.7)(10)=825.7\]

- anonymous

are you sure O.o I got complete diferent answers... Smh at me

- Mertsj

The reason is that we did not agree on the apothem. Did you see what I said about the apothem?

- anonymous

ohh yeah so everything would be wrong after that lol..

- Mertsj

Well check your work. I could have made a mistake. We agree on the setup.

- anonymous

are you sure about the surface area? you ADD the area of the pentagon?

- Mertsj

The pyramid is composed of the base which is a pentagon and 5 sides which are 5 congruent triangles. If it said lateral surface area it would be just the 5 triangles but it says surface area so we have to assume it means all of the surfaces.

- anonymous

oh yeah

- anonymous

How long will you be on? Im working on the other side will you be able to help me with that?

- Mertsj

Probably about another 20-25 minutes.

- anonymous

alright

- anonymous

@Mertsj http://i.imgur.com/bpW5d.jpg

- anonymous

im doing it as we speak I just dont want you to go

- anonymous

lol you like my -10?

- Mertsj

1/2 the difference of the arcs.

- Mertsj

30

- Mertsj

18. outside times whole = outside times whole.

- Mertsj

8(x+8)=7(16)
8x+64=112
x=6

- anonymous

Are you sure about 17. being 30? I think it's only half for like the 120 down to 60. 60 down to B is diferent I think

- Mertsj

The measure of an angle formed by a two secants drawn from a point outside the circle is half the the difference of the intercepted arcs. (far arc - near arc)

- Mertsj

19. Half the sum of the arcs.

- Mertsj

20. 6y=8(9)

- Mertsj

21.
\[(x-3)^2+(y+9)^2=25\]

- Mertsj

22.
\[(x+4)^2+(y-11)^2=100\]

- Mertsj

23. 13.6

- anonymous

Mert

- anonymous

Do you have paypal? lol

- anonymous

Id like to make a educational donation

- anonymous

LOL

- Mertsj

24. 8.0

- Mertsj

25. 44 but you had better check these answers because I did not. I just whipped them off. Could easily have hit a wrong button.
Good night

- anonymous

ah! night man thanks

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