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AcidRa1n

  • 2 years ago

PLEASE HELP http://i.imgur.com/GVvd6.png

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  1. AcidRa1n
    • 2 years ago
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    5. PIE12 6. PIE36 Is that right?

  2. Mertsj
    • 2 years ago
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    |dw:1338516252471:dw|

  3. Mertsj
    • 2 years ago
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    3. 3sqrt3

  4. Mertsj
    • 2 years ago
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    |dw:1338516418696:dw|

  5. Mertsj
    • 2 years ago
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    Radius of circle = 6 since the triangles are equilateral. So circumference = 2(6)pi=12pi

  6. Mertsj
    • 2 years ago
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    Area of circle = 36 pi

  7. Mertsj
    • 2 years ago
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    Do you mean how many degrees in each interior angle?

  8. AcidRa1n
    • 2 years ago
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    nvm

  9. AcidRa1n
    • 2 years ago
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    Can you check my other answers? I'm dont with all of them here, I need to scan it again

  10. AcidRa1n
    • 2 years ago
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    done*

  11. Mertsj
    • 2 years ago
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    I got 8.3 for the apothem of the pentagon. Your setup seems to be right. Also you need to pay more attention to the form of the answers in both questions.

  12. Mertsj
    • 2 years ago
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    \[\tan 36=\frac{6}{b}\] \[b \tan 36=6\] \[b=\frac{6}{\tan 36}=8.3\]

  13. Mertsj
    • 2 years ago
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    Therefore the area of the pentagon = 5(1/2)(12)(8.3)=247.7

  14. Mertsj
    • 2 years ago
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    Slant height = \[\sqrt{(8.3)^2+(10)^2}=13.0\]

  15. Mertsj
    • 2 years ago
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    Surface = 5(1/2)(13.0)(12)+247.7=637.7

  16. Mertsj
    • 2 years ago
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    \[V=\frac{1}{3}(247.7)(10)=825.7\]

  17. AcidRa1n
    • 2 years ago
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    are you sure O.o I got complete diferent answers... Smh at me

  18. Mertsj
    • 2 years ago
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    The reason is that we did not agree on the apothem. Did you see what I said about the apothem?

  19. AcidRa1n
    • 2 years ago
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    ohh yeah so everything would be wrong after that lol..

  20. Mertsj
    • 2 years ago
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    Well check your work. I could have made a mistake. We agree on the setup.

  21. AcidRa1n
    • 2 years ago
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    are you sure about the surface area? you ADD the area of the pentagon?

  22. Mertsj
    • 2 years ago
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    The pyramid is composed of the base which is a pentagon and 5 sides which are 5 congruent triangles. If it said lateral surface area it would be just the 5 triangles but it says surface area so we have to assume it means all of the surfaces.

  23. AcidRa1n
    • 2 years ago
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    oh yeah

  24. AcidRa1n
    • 2 years ago
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    How long will you be on? Im working on the other side will you be able to help me with that?

  25. Mertsj
    • 2 years ago
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    Probably about another 20-25 minutes.

  26. AcidRa1n
    • 2 years ago
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    alright

  27. AcidRa1n
    • 2 years ago
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    @Mertsj http://i.imgur.com/bpW5d.jpg

  28. AcidRa1n
    • 2 years ago
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    im doing it as we speak I just dont want you to go

  29. AcidRa1n
    • 2 years ago
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    lol you like my -10?

  30. Mertsj
    • 2 years ago
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    1/2 the difference of the arcs.

  31. Mertsj
    • 2 years ago
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    30

  32. Mertsj
    • 2 years ago
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    18. outside times whole = outside times whole.

  33. Mertsj
    • 2 years ago
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    8(x+8)=7(16) 8x+64=112 x=6

  34. AcidRa1n
    • 2 years ago
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    Are you sure about 17. being 30? I think it's only half for like the 120 down to 60. 60 down to B is diferent I think

  35. Mertsj
    • 2 years ago
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    The measure of an angle formed by a two secants drawn from a point outside the circle is half the the difference of the intercepted arcs. (far arc - near arc)

  36. Mertsj
    • 2 years ago
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    19. Half the sum of the arcs.

  37. Mertsj
    • 2 years ago
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    20. 6y=8(9)

  38. Mertsj
    • 2 years ago
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    21. \[(x-3)^2+(y+9)^2=25\]

  39. Mertsj
    • 2 years ago
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    22. \[(x+4)^2+(y-11)^2=100\]

  40. Mertsj
    • 2 years ago
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    23. 13.6

  41. AcidRa1n
    • 2 years ago
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    Mert

  42. AcidRa1n
    • 2 years ago
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    Do you have paypal? lol

  43. AcidRa1n
    • 2 years ago
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    Id like to make a educational donation

  44. AcidRa1n
    • 2 years ago
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    LOL

  45. Mertsj
    • 2 years ago
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    24. 8.0

  46. Mertsj
    • 2 years ago
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    25. 44 but you had better check these answers because I did not. I just whipped them off. Could easily have hit a wrong button. Good night

  47. AcidRa1n
    • 2 years ago
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    ah! night man thanks

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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