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AcidRa1n
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5. PIE12
6. PIE36
Is that right?
Mertsj
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|dw:1338516252471:dw|
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3. 3sqrt3
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|dw:1338516418696:dw|
Mertsj
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Radius of circle = 6 since the triangles are equilateral. So circumference = 2(6)pi=12pi
Mertsj
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Area of circle = 36 pi
Mertsj
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Do you mean how many degrees in each interior angle?
AcidRa1n
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nvm
AcidRa1n
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Can you check my other answers? I'm dont with all of them here, I need to scan it again
AcidRa1n
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done*
Mertsj
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I got 8.3 for the apothem of the pentagon. Your setup seems to be right. Also you need to pay more attention to the form of the answers in both questions.
Mertsj
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\[\tan 36=\frac{6}{b}\]
\[b \tan 36=6\]
\[b=\frac{6}{\tan 36}=8.3\]
Mertsj
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Therefore the area of the pentagon = 5(1/2)(12)(8.3)=247.7
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Slant height =
\[\sqrt{(8.3)^2+(10)^2}=13.0\]
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Surface = 5(1/2)(13.0)(12)+247.7=637.7
Mertsj
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\[V=\frac{1}{3}(247.7)(10)=825.7\]
AcidRa1n
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are you sure O.o I got complete diferent answers... Smh at me
Mertsj
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The reason is that we did not agree on the apothem. Did you see what I said about the apothem?
AcidRa1n
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ohh yeah so everything would be wrong after that lol..
Mertsj
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Well check your work. I could have made a mistake. We agree on the setup.
AcidRa1n
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are you sure about the surface area? you ADD the area of the pentagon?
Mertsj
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The pyramid is composed of the base which is a pentagon and 5 sides which are 5 congruent triangles. If it said lateral surface area it would be just the 5 triangles but it says surface area so we have to assume it means all of the surfaces.
AcidRa1n
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oh yeah
AcidRa1n
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How long will you be on? Im working on the other side will you be able to help me with that?
Mertsj
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Probably about another 20-25 minutes.
AcidRa1n
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alright
AcidRa1n
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im doing it as we speak I just dont want you to go
AcidRa1n
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lol you like my -10?
Mertsj
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1/2 the difference of the arcs.
Mertsj
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30
Mertsj
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18. outside times whole = outside times whole.
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8(x+8)=7(16)
8x+64=112
x=6
AcidRa1n
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Are you sure about 17. being 30? I think it's only half for like the 120 down to 60. 60 down to B is diferent I think
Mertsj
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The measure of an angle formed by a two secants drawn from a point outside the circle is half the the difference of the intercepted arcs. (far arc - near arc)
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19. Half the sum of the arcs.
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20. 6y=8(9)
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21.
\[(x-3)^2+(y+9)^2=25\]
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22.
\[(x+4)^2+(y-11)^2=100\]
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23. 13.6
AcidRa1n
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Mert
AcidRa1n
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Do you have paypal? lol
AcidRa1n
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Id like to make a educational donation
AcidRa1n
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LOL
Mertsj
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24. 8.0
Mertsj
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25. 44 but you had better check these answers because I did not. I just whipped them off. Could easily have hit a wrong button.
Good night
AcidRa1n
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ah! night man thanks