1. AcidRa1n

5. PIE12 6. PIE36 Is that right?

2. Mertsj

|dw:1338516252471:dw|

3. Mertsj

3. 3sqrt3

4. Mertsj

|dw:1338516418696:dw|

5. Mertsj

Radius of circle = 6 since the triangles are equilateral. So circumference = 2(6)pi=12pi

6. Mertsj

Area of circle = 36 pi

7. Mertsj

Do you mean how many degrees in each interior angle?

8. AcidRa1n

nvm

9. AcidRa1n

Can you check my other answers? I'm dont with all of them here, I need to scan it again

10. AcidRa1n

done*

11. Mertsj

I got 8.3 for the apothem of the pentagon. Your setup seems to be right. Also you need to pay more attention to the form of the answers in both questions.

12. Mertsj

$\tan 36=\frac{6}{b}$ $b \tan 36=6$ $b=\frac{6}{\tan 36}=8.3$

13. Mertsj

Therefore the area of the pentagon = 5(1/2)(12)(8.3)=247.7

14. Mertsj

Slant height = $\sqrt{(8.3)^2+(10)^2}=13.0$

15. Mertsj

Surface = 5(1/2)(13.0)(12)+247.7=637.7

16. Mertsj

$V=\frac{1}{3}(247.7)(10)=825.7$

17. AcidRa1n

are you sure O.o I got complete diferent answers... Smh at me

18. Mertsj

The reason is that we did not agree on the apothem. Did you see what I said about the apothem?

19. AcidRa1n

ohh yeah so everything would be wrong after that lol..

20. Mertsj

Well check your work. I could have made a mistake. We agree on the setup.

21. AcidRa1n

are you sure about the surface area? you ADD the area of the pentagon?

22. Mertsj

The pyramid is composed of the base which is a pentagon and 5 sides which are 5 congruent triangles. If it said lateral surface area it would be just the 5 triangles but it says surface area so we have to assume it means all of the surfaces.

23. AcidRa1n

oh yeah

24. AcidRa1n

How long will you be on? Im working on the other side will you be able to help me with that?

25. Mertsj

26. AcidRa1n

alright

27. AcidRa1n

@Mertsj http://i.imgur.com/bpW5d.jpg

28. AcidRa1n

im doing it as we speak I just dont want you to go

29. AcidRa1n

lol you like my -10?

30. Mertsj

1/2 the difference of the arcs.

31. Mertsj

30

32. Mertsj

18. outside times whole = outside times whole.

33. Mertsj

8(x+8)=7(16) 8x+64=112 x=6

34. AcidRa1n

Are you sure about 17. being 30? I think it's only half for like the 120 down to 60. 60 down to B is diferent I think

35. Mertsj

The measure of an angle formed by a two secants drawn from a point outside the circle is half the the difference of the intercepted arcs. (far arc - near arc)

36. Mertsj

19. Half the sum of the arcs.

37. Mertsj

20. 6y=8(9)

38. Mertsj

21. $(x-3)^2+(y+9)^2=25$

39. Mertsj

22. $(x+4)^2+(y-11)^2=100$

40. Mertsj

23. 13.6

41. AcidRa1n

Mert

42. AcidRa1n

Do you have paypal? lol

43. AcidRa1n

Id like to make a educational donation

44. AcidRa1n

LOL

45. Mertsj

24. 8.0

46. Mertsj

25. 44 but you had better check these answers because I did not. I just whipped them off. Could easily have hit a wrong button. Good night

47. AcidRa1n

ah! night man thanks