anonymous
  • anonymous
PLEASE HELP http://i.imgur.com/GVvd6.png
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
5. PIE12 6. PIE36 Is that right?
Mertsj
  • Mertsj
|dw:1338516252471:dw|
Mertsj
  • Mertsj
3. 3sqrt3

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Mertsj
  • Mertsj
|dw:1338516418696:dw|
Mertsj
  • Mertsj
Radius of circle = 6 since the triangles are equilateral. So circumference = 2(6)pi=12pi
Mertsj
  • Mertsj
Area of circle = 36 pi
Mertsj
  • Mertsj
Do you mean how many degrees in each interior angle?
anonymous
  • anonymous
nvm
anonymous
  • anonymous
Can you check my other answers? I'm dont with all of them here, I need to scan it again
anonymous
  • anonymous
done*
Mertsj
  • Mertsj
I got 8.3 for the apothem of the pentagon. Your setup seems to be right. Also you need to pay more attention to the form of the answers in both questions.
Mertsj
  • Mertsj
\[\tan 36=\frac{6}{b}\] \[b \tan 36=6\] \[b=\frac{6}{\tan 36}=8.3\]
Mertsj
  • Mertsj
Therefore the area of the pentagon = 5(1/2)(12)(8.3)=247.7
Mertsj
  • Mertsj
Slant height = \[\sqrt{(8.3)^2+(10)^2}=13.0\]
Mertsj
  • Mertsj
Surface = 5(1/2)(13.0)(12)+247.7=637.7
Mertsj
  • Mertsj
\[V=\frac{1}{3}(247.7)(10)=825.7\]
anonymous
  • anonymous
are you sure O.o I got complete diferent answers... Smh at me
Mertsj
  • Mertsj
The reason is that we did not agree on the apothem. Did you see what I said about the apothem?
anonymous
  • anonymous
ohh yeah so everything would be wrong after that lol..
Mertsj
  • Mertsj
Well check your work. I could have made a mistake. We agree on the setup.
anonymous
  • anonymous
are you sure about the surface area? you ADD the area of the pentagon?
Mertsj
  • Mertsj
The pyramid is composed of the base which is a pentagon and 5 sides which are 5 congruent triangles. If it said lateral surface area it would be just the 5 triangles but it says surface area so we have to assume it means all of the surfaces.
anonymous
  • anonymous
oh yeah
anonymous
  • anonymous
How long will you be on? Im working on the other side will you be able to help me with that?
Mertsj
  • Mertsj
Probably about another 20-25 minutes.
anonymous
  • anonymous
alright
anonymous
  • anonymous
@Mertsj http://i.imgur.com/bpW5d.jpg
anonymous
  • anonymous
im doing it as we speak I just dont want you to go
anonymous
  • anonymous
lol you like my -10?
Mertsj
  • Mertsj
1/2 the difference of the arcs.
Mertsj
  • Mertsj
30
Mertsj
  • Mertsj
18. outside times whole = outside times whole.
Mertsj
  • Mertsj
8(x+8)=7(16) 8x+64=112 x=6
anonymous
  • anonymous
Are you sure about 17. being 30? I think it's only half for like the 120 down to 60. 60 down to B is diferent I think
Mertsj
  • Mertsj
The measure of an angle formed by a two secants drawn from a point outside the circle is half the the difference of the intercepted arcs. (far arc - near arc)
Mertsj
  • Mertsj
19. Half the sum of the arcs.
Mertsj
  • Mertsj
20. 6y=8(9)
Mertsj
  • Mertsj
21. \[(x-3)^2+(y+9)^2=25\]
Mertsj
  • Mertsj
22. \[(x+4)^2+(y-11)^2=100\]
Mertsj
  • Mertsj
23. 13.6
anonymous
  • anonymous
Mert
anonymous
  • anonymous
Do you have paypal? lol
anonymous
  • anonymous
Id like to make a educational donation
anonymous
  • anonymous
LOL
Mertsj
  • Mertsj
24. 8.0
Mertsj
  • Mertsj
25. 44 but you had better check these answers because I did not. I just whipped them off. Could easily have hit a wrong button. Good night
anonymous
  • anonymous
ah! night man thanks

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