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anonymous
 4 years ago
Find the minimum value for the function: y = x^2 + 9x + 18
anonymous
 4 years ago
Find the minimum value for the function: y = x^2 + 9x + 18

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do u knwo how to complete the square? or do u factor it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its under my quadratic function lesson so idk

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what 2 numbers when you multiply them =18 and when u add them =9?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is there a number for that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yaaaa factoring i just taught this to my class today. hmmmm nooooo we r factoring. We r trying to figure out 2 numbers that when u mulyiply them give us 18 and when u add them gives us 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0finding the zeros is a long and complicated way to find the minimum

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0umm well we can complete the square

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i dont think she knows that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0minimum is at the vertex, and first coordinate of the vertex of \[y=ax^2+bx+c\] is always \(\frac{b}{2a}\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when doing the vertx thing... is the second number the minimum?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in your case it is \(\frac{9}{2}\) replace \(x\) by \(\frac{9}{2}\) to find the minimum

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0minimum means minimum value of \(y\) so it is the second coordinate, not the first

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so yes, what you said, the second number is the minimum.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh i like this method. We never learnt this stuff. Like the textbook always made us complete the square. oh cooll

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can i just plug it into my graphing calculator to get the anwser ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0completing the square is for suckers, unless of course you are solving a quadratic equation

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.0last i heard minimum value was in a calculus class o.O i never knew it was in algebra too

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.1You can use a calculator to solve it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hahah its in math 11 here in canada

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(\frac{9}{2})^2+9\times (\frac{9}{2})+18\] then a calculator if you need one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you turn math up to eleven in canada? mine only goes up to ten

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.1Ti84, input the equation into Y= then click 2nd Trace, and do minimum. It will say "Left bound?", go to the left side of the graph and press enter. Right bound? Obviously, right side. It will say "Guess?", which means put it to where you think the minimum y value is.

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.1So for this, you get x=4.5 and y=2.25

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sooo many numbers ... ahhhhh!!! >_< what about TI83 plus?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hahaha grade 11 math lol

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.0so taking the derivative and equating to zero is another story?

Lukecrayonz
 4 years ago
Best ResponseYou've already chosen the best response.1It'll be exactly the same basically I think.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0they give us this freshman yr. imma senior now tryna make it up.. sucks :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0using the derivative to find the minimum value of a quadratic. like using a glock to kill a wingspanroach
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