tylertriebs
Which of the following equations is of a parabola with a vertex at (0, -5)?
y = (x - 5)2
y = (x + 5)2
y = x2 - 5
y = x2 + 5
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tylertriebs
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ok
tylertriebs
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wouldnt that make it the first one then
shahzadjalbani
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sorry my equation was y=a(x-h)^2+k
shahzadjalbani
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@tylertriebs You can use -b/2a to find the x coordinate of the vertex.
tylertriebs
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ok
shahzadjalbani
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@tylertriebs Now solve by formula and tell me what is the result.
shahzadjalbani
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take each equation separately . @tylertriebs
tylertriebs
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ok just sec
tylertriebs
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ok im lost
shahzadjalbani
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why ?
tylertriebs
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i dont get how to include the equation
shahzadjalbani
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take it easy I am going to solve one equation for you.
shahzadjalbani
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|dw:1338548813555:dw|
Put these values in formula
-b/2a to get x coordiante .
shahzadjalbani
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@tylertriebs solve and it and tell me what is the value of x
tylertriebs
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-5?
shahzadjalbani
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it means it is not your answer because vertex is (0,-5)
take another equation in the same way and solve when value of x comes 0
then you will get your answer.
tylertriebs
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ok
shahzadjalbani
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Now take the third equation which x^2-5....|dw:1338549273486:dw|
Put these values in formula -b/2a
shahzadjalbani
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@tylertriebs Solve it hurry up !
And give me result.
tylertriebs
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wouldnt that still be -5
shahzadjalbani
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no
|dw:1338549527046:dw|
tylertriebs
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ok
shahzadjalbani
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@tylertriebs Now put the value of x in x^2-5 You will get your ordered pair of (0,-5)
Am I right.
tylertriebs
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yes
shahzadjalbani
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It means @tylertriebs which equation is your answer?
tylertriebs
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the second to last
shahzadjalbani
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Yes Hurrah! You Got it!
shahzadjalbani
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@tylertriebs
tylertriebs
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thank you
A.Avinash_Goutham
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congrats :) :P
shahzadjalbani
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It is certified that @tylertriebs is able to
solve the questions of quadratic equation
related to vertex and finding the value
x from an equation.
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