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ShotGunGirl

  • 2 years ago

Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five. 38 and 40 40 and 42 42 and 44 Thank you!

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  1. ParthKohli
    • 2 years ago
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    Hmm I see. You may check from the options.

  2. ParthKohli
    • 2 years ago
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    \(\Large \color{MidnightBlue}{\Rightarrow {1 \over 2}x - {2 \over 5}(x - 1) = 5 }\)

  3. A.Avinash_Goutham
    • 2 years ago
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    38 nd 40

  4. ParthKohli
    • 2 years ago
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    Nope. Not correct.

  5. ParthKohli
    • 2 years ago
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    To get a whole number 5, the smaller number must be divisible by 5, or else you get a fraction/decimal

  6. ParthKohli
    • 2 years ago
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    Basically the bigger one must be divisible by 2 and the smaller one by 5.

  7. ShotGunGirl
    • 2 years ago
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    It's not 38 and 40 parth?

  8. ParthKohli
    • 2 years ago
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    Nope. 38 is not divisible by 5.

  9. ShotGunGirl
    • 2 years ago
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    So I see. Thank you.

  10. ParthKohli
    • 2 years ago
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    One of these options have the smaller number divisible by 5.

  11. ParthKohli
    • 2 years ago
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    If my answer confused you, then solve the equation I gave, or check it by multiplying the bigger one by 1/2 and smaller one by 2/5 then subtracting them.

  12. ShotGunGirl
    • 2 years ago
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    Thank you ParthKohli, for all the help.

  13. ParthKohli
    • 2 years ago
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    =)

  14. simplicity
    • 2 years ago
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    40 and 42 will be the correct answer the equation will be\[x/2-2(x-2)/5=5\]

  15. ParthKohli
    • 2 years ago
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    Oh no yeah you're correct

  16. ParthKohli
    • 2 years ago
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    Even numbers.

  17. ParthKohli
    • 2 years ago
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    But I was correct about divisible by 5 part

  18. ShotGunGirl
    • 2 years ago
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    Thank you both<3

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