ShotGunGirl
Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.
38 and 40
40 and 42
42 and 44
Thank you!
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ParthKohli
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Hmm I see.
You may check from the options.
ParthKohli
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\(\Large \color{MidnightBlue}{\Rightarrow {1 \over 2}x - {2 \over 5}(x - 1) = 5 }\)
ParthKohli
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Nope. Not correct.
ParthKohli
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To get a whole number 5, the smaller number must be divisible by 5, or else you get a fraction/decimal
ParthKohli
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Basically the bigger one must be divisible by 2 and the smaller one by 5.
ShotGunGirl
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It's not 38 and 40 parth?
ParthKohli
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Nope. 38 is not divisible by 5.
ShotGunGirl
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So I see. Thank you.
ParthKohli
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One of these options have the smaller number divisible by 5.
ParthKohli
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If my answer confused you, then solve the equation I gave, or check it by multiplying the bigger one by 1/2 and smaller one by 2/5 then subtracting them.
ShotGunGirl
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Thank you ParthKohli, for all the help.
ParthKohli
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=)
simplicity
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40 and 42 will be the correct answer
the equation will be\[x/2-2(x-2)/5=5\]
ParthKohli
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Oh no yeah you're correct
ParthKohli
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Even numbers.
ParthKohli
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But I was correct about divisible by 5 part
ShotGunGirl
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Thank you both<3