anonymous
  • anonymous
Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five. 38 and 40 40 and 42 42 and 44 Thank you!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ParthKohli
  • ParthKohli
Hmm I see. You may check from the options.
ParthKohli
  • ParthKohli
\(\Large \color{MidnightBlue}{\Rightarrow {1 \over 2}x - {2 \over 5}(x - 1) = 5 }\)
anonymous
  • anonymous
38 nd 40

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ParthKohli
  • ParthKohli
Nope. Not correct.
ParthKohli
  • ParthKohli
To get a whole number 5, the smaller number must be divisible by 5, or else you get a fraction/decimal
ParthKohli
  • ParthKohli
Basically the bigger one must be divisible by 2 and the smaller one by 5.
anonymous
  • anonymous
It's not 38 and 40 parth?
ParthKohli
  • ParthKohli
Nope. 38 is not divisible by 5.
anonymous
  • anonymous
So I see. Thank you.
ParthKohli
  • ParthKohli
One of these options have the smaller number divisible by 5.
ParthKohli
  • ParthKohli
If my answer confused you, then solve the equation I gave, or check it by multiplying the bigger one by 1/2 and smaller one by 2/5 then subtracting them.
anonymous
  • anonymous
Thank you ParthKohli, for all the help.
ParthKohli
  • ParthKohli
=)
anonymous
  • anonymous
40 and 42 will be the correct answer the equation will be\[x/2-2(x-2)/5=5\]
ParthKohli
  • ParthKohli
Oh no yeah you're correct
ParthKohli
  • ParthKohli
Even numbers.
ParthKohli
  • ParthKohli
But I was correct about divisible by 5 part
anonymous
  • anonymous
Thank you both<3

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