## anonymous 4 years ago Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five. 38 and 40 40 and 42 42 and 44 Thank you!

1. ParthKohli

Hmm I see. You may check from the options.

2. ParthKohli

$$\Large \color{MidnightBlue}{\Rightarrow {1 \over 2}x - {2 \over 5}(x - 1) = 5 }$$

3. anonymous

38 nd 40

4. ParthKohli

Nope. Not correct.

5. ParthKohli

To get a whole number 5, the smaller number must be divisible by 5, or else you get a fraction/decimal

6. ParthKohli

Basically the bigger one must be divisible by 2 and the smaller one by 5.

7. anonymous

It's not 38 and 40 parth?

8. ParthKohli

Nope. 38 is not divisible by 5.

9. anonymous

So I see. Thank you.

10. ParthKohli

One of these options have the smaller number divisible by 5.

11. ParthKohli

If my answer confused you, then solve the equation I gave, or check it by multiplying the bigger one by 1/2 and smaller one by 2/5 then subtracting them.

12. anonymous

Thank you ParthKohli, for all the help.

13. ParthKohli

=)

14. anonymous

40 and 42 will be the correct answer the equation will be$x/2-2(x-2)/5=5$

15. ParthKohli

Oh no yeah you're correct

16. ParthKohli

Even numbers.

17. ParthKohli

But I was correct about divisible by 5 part

18. anonymous

Thank you both<3