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Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five. 38 and 40 40 and 42 42 and 44 Thank you!

Mathematics
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Hmm I see. You may check from the options.
\(\Large \color{MidnightBlue}{\Rightarrow {1 \over 2}x - {2 \over 5}(x - 1) = 5 }\)
38 nd 40

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Other answers:

Nope. Not correct.
To get a whole number 5, the smaller number must be divisible by 5, or else you get a fraction/decimal
Basically the bigger one must be divisible by 2 and the smaller one by 5.
It's not 38 and 40 parth?
Nope. 38 is not divisible by 5.
So I see. Thank you.
One of these options have the smaller number divisible by 5.
If my answer confused you, then solve the equation I gave, or check it by multiplying the bigger one by 1/2 and smaller one by 2/5 then subtracting them.
Thank you ParthKohli, for all the help.
=)
40 and 42 will be the correct answer the equation will be\[x/2-2(x-2)/5=5\]
Oh no yeah you're correct
Even numbers.
But I was correct about divisible by 5 part
Thank you both<3

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