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Aadarsh
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A projectile is thrown horizontallly from the top of a tower and strikes teh ground after 3 second at an angle of 45 degrees with the horizontal. Find the height of the tower and speed with which the body was projected. (Take "g" = 9.8 m/s^2)
 2 years ago
 2 years ago
Aadarsh Group Title
A projectile is thrown horizontallly from the top of a tower and strikes teh ground after 3 second at an angle of 45 degrees with the horizontal. Find the height of the tower and speed with which the body was projected. (Take "g" = 9.8 m/s^2)
 2 years ago
 2 years ago

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Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
@Mani_Jha , @Ishaan94 please help.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
@apoorvk , @srinidhijha, @AravindG please help
 2 years ago

srinidhijha Group TitleBest ResponseYou've already chosen the best response.1
what is angle of projection? is the question written as it is?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Yeah, the question is as it is as I have written here.
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
So when it strikes, basically the horizontal and vertical components of its velocity are equal (since it strikes the ground at 45 degrees) Now, let the initial velocity of projection be 'u' Now, the horizontal speed remains constant, but the vertical component increases from '0' to 'u', as it hits the ground. Now, vertical component (final) = v time of flight = sqrt(2gh) = 3 Find height, and then find 'u'.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
How time of flight = sqrt(2gh)? Can u show the complete steps and other equations also?
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
LOL sorry  it would 'final' velocity, not time of flight  my bad lol.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Still i am not able to follow how is it equal to sqrt(2gh)? Can u show the workign of other steps also?
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
yeah, so use, (vu)/g = t
 2 years ago

srinidhijha Group TitleBest ResponseYou've already chosen the best response.1
hey is the speed 97 ? u know the answers?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Answer is 30 m/s
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
for a particle under free fall with initial velocity 'u=0'dw:1338565657495:dw
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Got it. Can we not say that:\[T = 2u \cos \theta / g = \sqrt{2}u/g\]
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
yeah, v=30, and height = 45 metres, right?
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
well, that is for a groundtoground projectile @Aadarsh
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
@apoorvk bhai, ur answer is right.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
@apoorvk bhai, please show all the steps.
 2 years ago

srinidhijha Group TitleBest ResponseYou've already chosen the best response.1
look the pa
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Thanks apoorv bhai.
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
See, ye samajh mein aaya ki horizontal and vertical components at the time of hitting the ground same honge?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Yeh to samajh mein nahion aaya.....
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
samjha dijiye
 2 years ago

srinidhijha Group TitleBest ResponseYou've already chosen the best response.1
see the attachment koi horizontal equal lene ki jarurat nh ihai
 2 years ago

srinidhijha Group TitleBest ResponseYou've already chosen the best response.1
samajh aaya?
 2 years ago

srinidhijha Group TitleBest ResponseYou've already chosen the best response.1
isse pahle bhi ek attachment tha jisme U nikaala hai , dkho, Final velocity to 0 hi hoga naa jab wo gir jaaye to
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Thakns srini bhaiiiiiiiii. samajh mein aa gaya.
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Sri, great calligraphy! :P
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
srry i am late :P
 2 years ago
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