Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
tHE NUMBER OF WAYS 3 DIGIT NUMBER odd number CAN BE FORMED BY 0,3,4,8,9 SO THAT THE NUMBER DOES NOT REPEAT
 one year ago
 one year ago
tHE NUMBER OF WAYS 3 DIGIT NUMBER odd number CAN BE FORMED BY 0,3,4,8,9 SO THAT THE NUMBER DOES NOT REPEAT
 one year ago
 one year ago

This Question is Closed

ParthKohliBest ResponseYou've already chosen the best response.0
\( \color{Black}{\Rightarrow {5p1} = 5! }\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
\( \color{Black}{\Rightarrow 5p3 = {5! \over 2!} }\)
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
dw:1338570568852:dw
 one year ago

LyraElizabethAdamsBest ResponseYou've already chosen the best response.0
Well, because you're looking for ways in which a number does not repeat, you're going to need to use permutation. So, you'd take the total numbers that you have (5), and "permut" that by the 3 choices of number that you need. So: 5P3 Hope this helps!! ;)
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
odd no.  so the last digit can be either 9 or 3 > 2 ways. choose and arrange any 2 outta remaining 4 digits = 4P2 so no. of possible of possible nos. = 2 * 4P2
 one year ago

LyraElizabethAdamsBest ResponseYou've already chosen the best response.0
This would give you a total of 60 nonrepeating choices.
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
FOLKS! @ParthKohli and @LyraElizabethAdams  seems like you missed out that 'odd' word in the question  just like I did in the beginning.
 one year ago

LyraElizabethAdamsBest ResponseYou've already chosen the best response.0
OH, MY GOODNESS  I just realized that myself! Thanks!
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
So there is a fixed value of the last digit.
 one year ago

LyraElizabethAdamsBest ResponseYou've already chosen the best response.0
You'd need to make sure, then, that you only count the numbers for which 8 is not at the end  8 is an even number and would make the number even.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
3 * 2 * 2 = 6 * 2 = 12
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
@goformit100  that last one would be '2'  won't it?dw:1338570736125:dw
 one year ago

LyraElizabethAdamsBest ResponseYou've already chosen the best response.0
Ooops  and 0.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Because there are 3 for the first, 2 for second, 2 for third, it'll be 3 * 2 * 2
 one year ago

open_study1Best ResponseYou've already chosen the best response.1
@apoorvk u r correct can u explain that
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
@apoorvk BUt there is only one odd number; then last must be 2 na.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Yeah so I am correct. 3 * 2 * 2
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
I just told you  the last digit has to be odd for the whole no. to be odd. and you have two odd digits in the array  3 and 9. so choosing any one of them = 2 ways. now the remaining two digits = i can use any 2 from the 4 digits now left in the array, so 4P2, or 4x3. so, ways of selecting the no. = 2 x (4x3) = 24
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
There are two digits according to me  '3' and '9'  if we are on earth that is. _
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
oooo yes i mistaken, you were write, @apoorvk
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
But wait, there are 3 possibilites for the first because we don't have digits repeated. 2 for second. 2 for third.
 one year ago

FoolForMathBest ResponseYou've already chosen the best response.2
It should be \(2\times 3\times 3 =12\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
3 * 2 * 2 is the answer :/
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
@FoolForMath  explain please.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Yes @FoolForMath they're not understanding what I'm trying to say..that's exactly what I said
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Apoorv scroll up and see the explanation I gave
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
That's what I was saying Foom :P
 one year ago

FoolForMathBest ResponseYou've already chosen the best response.2
Drat my typo: \(2\times 3\times 3 =18 \)
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
After a lot of days, I guess I can bet my bottom dollar on this. _ ( lol I barely have any USD left with me right now to lose :P)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Aren't there 3 for first, 2 for second, 2 for third because the digits cant repeat?
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
Hmm. okay  howzzit '3' choices for the second last digit  after I have chosen one od one, I still have 4 choices in the bank  I can pick any outta those 4. so that makes or 4 choices for the middle digit (or the first one, doesn't really matter)
 one year ago

FoolForMathBest ResponseYou've already chosen the best response.2
@apoorvk: If you put 0 in the 100th place then it won't be a 3 digit number.
 one year ago

apoorvkBest ResponseYou've already chosen the best response.0
Me dumbosta! Ahaaa.. Hmm. Right. I lose approximately 3 quarters and two nickels then. #NotPayingUp .
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.