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 2 years ago
tHE NUMBER OF WAYS 3 DIGIT NUMBER odd number CAN BE FORMED BY 0,3,4,8,9 SO THAT THE NUMBER DOES NOT REPEAT
 2 years ago
tHE NUMBER OF WAYS 3 DIGIT NUMBER odd number CAN BE FORMED BY 0,3,4,8,9 SO THAT THE NUMBER DOES NOT REPEAT

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ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0\( \color{Black}{\Rightarrow {5p1} = 5! }\)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0\( \color{Black}{\Rightarrow 5p3 = {5! \over 2!} }\)

goformit100
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1338570568852:dw

LyraElizabethAdams
 2 years ago
Best ResponseYou've already chosen the best response.0Well, because you're looking for ways in which a number does not repeat, you're going to need to use permutation. So, you'd take the total numbers that you have (5), and "permut" that by the 3 choices of number that you need. So: 5P3 Hope this helps!! ;)

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0odd no.  so the last digit can be either 9 or 3 > 2 ways. choose and arrange any 2 outta remaining 4 digits = 4P2 so no. of possible of possible nos. = 2 * 4P2

LyraElizabethAdams
 2 years ago
Best ResponseYou've already chosen the best response.0This would give you a total of 60 nonrepeating choices.

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0FOLKS! @ParthKohli and @LyraElizabethAdams  seems like you missed out that 'odd' word in the question  just like I did in the beginning.

LyraElizabethAdams
 2 years ago
Best ResponseYou've already chosen the best response.0OH, MY GOODNESS  I just realized that myself! Thanks!

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0So there is a fixed value of the last digit.

LyraElizabethAdams
 2 years ago
Best ResponseYou've already chosen the best response.0You'd need to make sure, then, that you only count the numbers for which 8 is not at the end  8 is an even number and would make the number even.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.03 * 2 * 2 = 6 * 2 = 12

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0@goformit100  that last one would be '2'  won't it?dw:1338570736125:dw

LyraElizabethAdams
 2 years ago
Best ResponseYou've already chosen the best response.0Ooops  and 0.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Because there are 3 for the first, 2 for second, 2 for third, it'll be 3 * 2 * 2

open_study1
 2 years ago
Best ResponseYou've already chosen the best response.1@apoorvk u r correct can u explain that

goformit100
 2 years ago
Best ResponseYou've already chosen the best response.0@apoorvk BUt there is only one odd number; then last must be 2 na.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah so I am correct. 3 * 2 * 2

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0I just told you  the last digit has to be odd for the whole no. to be odd. and you have two odd digits in the array  3 and 9. so choosing any one of them = 2 ways. now the remaining two digits = i can use any 2 from the 4 digits now left in the array, so 4P2, or 4x3. so, ways of selecting the no. = 2 x (4x3) = 24

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0There are two digits according to me  '3' and '9'  if we are on earth that is. _

goformit100
 2 years ago
Best ResponseYou've already chosen the best response.0oooo yes i mistaken, you were write, @apoorvk

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0But wait, there are 3 possibilites for the first because we don't have digits repeated. 2 for second. 2 for third.

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.2It should be \(2\times 3\times 3 =12\)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.03 * 2 * 2 is the answer :/

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0@FoolForMath  explain please.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Yes @FoolForMath they're not understanding what I'm trying to say..that's exactly what I said

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Apoorv scroll up and see the explanation I gave

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0That's what I was saying Foom :P

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.2Drat my typo: \(2\times 3\times 3 =18 \)

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0After a lot of days, I guess I can bet my bottom dollar on this. _ ( lol I barely have any USD left with me right now to lose :P)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Aren't there 3 for first, 2 for second, 2 for third because the digits cant repeat?

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm. okay  howzzit '3' choices for the second last digit  after I have chosen one od one, I still have 4 choices in the bank  I can pick any outta those 4. so that makes or 4 choices for the middle digit (or the first one, doesn't really matter)

FoolForMath
 2 years ago
Best ResponseYou've already chosen the best response.2@apoorvk: If you put 0 in the 100th place then it won't be a 3 digit number.

apoorvk
 2 years ago
Best ResponseYou've already chosen the best response.0Me dumbosta! Ahaaa.. Hmm. Right. I lose approximately 3 quarters and two nickels then. #NotPayingUp .
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