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anonymous
 3 years ago
PLEASE HELP!!!!!
"For both of column A and B, "a" and "b" are nonzero integers:"
Column A: (a+b)^2
Column B: (a^2 + b^2)
Please explain why the answer is: "The relationship cannot be determined from the information given."
Thanks! =)
anonymous
 3 years ago
PLEASE HELP!!!!! "For both of column A and B, "a" and "b" are nonzero integers:" Column A: (a+b)^2 Column B: (a^2 + b^2) Please explain why the answer is: "The relationship cannot be determined from the information given." Thanks! =)

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zepp
 3 years ago
Best ResponseYou've already chosen the best response.0Alright, what are we suppose to find, integers a & b?

zepp
 3 years ago
Best ResponseYou've already chosen the best response.0Those are given information, but what's the actual question about those two columns?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry, I guess I should have put this: "Please explain why the answer for both columns is: "The relationship cannot be determined from the information given."

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The question just wants you to figure out the relationships between Column A and Column B.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I tried plugging numbers in for "a" and "b", and the answer seemed to be that the quantity in Column A was greater, but maybe it's only greater for some values?

AccessDenied
 3 years ago
Best ResponseYou've already chosen the best response.2If we expand out the expression for column A, we get: a^2 + 2ab + b^2 This has all the same terms as the second column, but then the extra 2ab. Now, when a and b are both greater than 0, column A is always greater than column B because 2ab is always positive, so it's always going to have an extra bit added to it. If a or b is negative and the other positive, then the "2ab" becomes a subtraction and so column A is now becoming less than column B. Then lastly, if both a and b are negative, then "2ab" is still positive and column A is once again greater than column B.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Aha! That makes tons of sense! Thank you so much! I REALLY, REALLY appreciate it! :)

AccessDenied
 3 years ago
Best ResponseYou've already chosen the best response.2You're welcome. :)
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