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Use properties of logarithms to expand the loarithmic expressions as much as possile. log_4 7-2 1) 7log4 4 2) 4log4 7 3) -4log4 7 4) -16log 7

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\[\log_4 7^{-2} \to \log_4 (\frac{1}{49})\to \frac{\log \frac{1}{49}}{\log 4}\]

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Other answers:

are the options you wrote correct? @Audrae_World
Yes, that's what my book says
Isn't it \[\log_{4} 1 - \log_{4} 7^{2}\]
Its expand not solve @saifoo.khan
Yes! im stuck. :/
@Audrae_World : Is it \[\log_{4} 7^2\]
That's the closest I've seen so far, but the one of answer choices says: 4log_4 7^2
Are you sure the problem is \[\log_{4} 7^{-2}\] ?
Oh. I got it. Hold on.
\[\log_{4}7^{-2} = -2(\log_{4}7) = -2(\log_{7}7/\log_{7}4) = -2(1/\log_{7}2^{2})\] \[-2(\log_{7}2^{-2}) = -2 * -2(\log_{7}2) = 4\log_{7}2\]
Wait. Darn it...
LOL @Calcmathlete :whats that !??
lol. I got so close!!! But then I realized that it isn't one of the answers...

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