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Audrae_World Group Title

Use properties of logarithms to expand the loarithmic expressions as much as possile. log_4 7-2 1) 7log4 4 2) 4log4 7 3) -4log4 7 4) -16log 7

  • 2 years ago
  • 2 years ago

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  1. saifoo.khan Group Title
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    7-2?

    • 2 years ago
  2. Audrae_World Group Title
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    7-^2

    • 2 years ago
  3. saifoo.khan Group Title
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    \[\log_4 7^{-2} \to \log_4 (\frac{1}{49})\to \frac{\log \frac{1}{49}}{\log 4}\]

    • 2 years ago
  4. saifoo.khan Group Title
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    are the options you wrote correct? @Audrae_World

    • 2 years ago
  5. Audrae_World Group Title
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    Yes, that's what my book says

    • 2 years ago
  6. Calcmathlete Group Title
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    Isn't it \[\log_{4} 1 - \log_{4} 7^{2}\]

    • 2 years ago
  7. Eyad Group Title
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    Its expand not solve @saifoo.khan

    • 2 years ago
  8. saifoo.khan Group Title
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    Yes! im stuck. :/

    • 2 years ago
  9. Eyad Group Title
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    @Audrae_World : Is it \[\log_{4} 7^2\]

    • 2 years ago
  10. Audrae_World Group Title
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    That's the closest I've seen so far, but the one of answer choices says: 4log_4 7^2

    • 2 years ago
  11. Calcmathlete Group Title
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    Are you sure the problem is \[\log_{4} 7^{-2}\] ?

    • 2 years ago
  12. Audrae_World Group Title
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    Yes

    • 2 years ago
  13. Calcmathlete Group Title
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    Oh. I got it. Hold on.

    • 2 years ago
  14. Calcmathlete Group Title
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    \[\log_{4}7^{-2} = -2(\log_{4}7) = -2(\log_{7}7/\log_{7}4) = -2(1/\log_{7}2^{2})\] \[-2(\log_{7}2^{-2}) = -2 * -2(\log_{7}2) = 4\log_{7}2\]

    • 2 years ago
  15. Calcmathlete Group Title
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    Wait. Darn it...

    • 2 years ago
  16. Eyad Group Title
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    LOL @Calcmathlete :whats that !??

    • 2 years ago
  17. Calcmathlete Group Title
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    lol. I got so close!!! But then I realized that it isn't one of the answers...

    • 2 years ago
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