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anonymous
 3 years ago
area between y=x^2 2x 3 and y =3x3
anonymous
 3 years ago
area between y=x^2 2x 3 and y =3x3

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i did but i don't know how to calculate it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Take the definite integral of one and subtract out the definite integral of the other.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0HINT: Area under curve, Integration.

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0We integrate using the limits.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nathan is your Mr Analysis, he might help you :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0LOL the i like the sarcasm fool for math

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hey vitus, long time :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Set the equations equal to learn where they intersect and which is above the other, then take the definite integral of the lower function subtracted from the higher function, between the limits that you found.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i mean do you have have to split it some how and then integrate

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Graphing is a good quick way to learn the limits of integration and which equation is larger.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0fine the points of interception, those will be your bounds of integration.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=area+between+y%3Dx%5E2+2x+3++and+y+%3D3x3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats how the graph looks like, how do i account for the are under the graph

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1338596987767:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0By looking at that graph you can see that the two functions intersect at x=0 and x=5, so those will be your limits of integration. They also show you that the linear function is above the quadratic function, so you subtract the quadratic function from the linear function, then integrate it from 0 to 5.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0OHHHH is that it!!!! LOL SORRY, didn't know why i couldn't see that.
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