Here's the question you clicked on:
virtus
area between y=x^2 -2x -3 and y =3x-3
i did but i don't know how to calculate it
Take the definite integral of one and subtract out the definite integral of the other.
HINT: Area under curve, Integration.
We integrate using the limits.
Nathan is your Mr Analysis, he might help you :D
LOL the i like the sarcasm fool for math
Hey vitus, long time :D
Set the equations equal to learn where they intersect and which is above the other, then take the definite integral of the lower function subtracted from the higher function, between the limits that you found.
i mean do you have have to split it some how and then integrate
Graphing is a good quick way to learn the limits of integration and which equation is larger.
fine the points of interception, those will be your bounds of integration.
http://www.wolframalpha.com/input/?i=area+between+y%3Dx%5E2+-2x+-3++and+y+%3D3x-3
thats how the graph looks like, how do i account for the are under the graph
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By looking at that graph you can see that the two functions intersect at x=0 and x=5, so those will be your limits of integration. They also show you that the linear function is above the quadratic function, so you subtract the quadratic function from the linear function, then integrate it from 0 to 5.
OHHHH is that it!!!! LOL SORRY, didn't know why i couldn't see that.