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shahzadjalbani Group Title

Why is the product of the gradients of 2 straight line perpendicular to each other is always equal to -1 ?? Please prove it......?

  • 2 years ago
  • 2 years ago

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  1. shirleyx Group Title
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    m1=1/m2 you can use two rules (straight line) to prove it. |dw:1338626026029:dw|

    • 2 years ago
  2. shahzadjalbani Group Title
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    Give me a hint?

    • 2 years ago
  3. myko Group Title
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    you can write equation of the lines perpedicular to each other in this form: ax+by=0 -bx+ay=0 this is a hint....:)

    • 2 years ago
  4. shahzadjalbani Group Title
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    Can you prove it through trigonometry?

    • 2 years ago
  5. shahzadjalbani Group Title
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    @myko @shirleyx Can you prove it through trigonometry?

    • 2 years ago
  6. experimentX Group Title
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    slope = \( \tan(\theta) \) another slope = \( \tan(\theta - 90) = -\cot \theta \)

    • 2 years ago
  7. myko Group Title
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    \[\cos \alpha x+\sin \alpha y =0\] \[-\sin \alpha x + \cos \alpha y =0\]

    • 2 years ago
  8. myko Group Title
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    grad f1 = (cosa -sinax,sina+cosay) grad f2 = (-sina-cosax,cosa-sinay)

    • 2 years ago
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