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shahzadjalbani

  • 3 years ago

Why is the product of the gradients of 2 straight line perpendicular to each other is always equal to -1 ?? Please prove it......?

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  1. shirleyx
    • 3 years ago
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    m1=1/m2 you can use two rules (straight line) to prove it. |dw:1338626026029:dw|

  2. shahzadjalbani
    • 3 years ago
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    Give me a hint?

  3. myko
    • 3 years ago
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    you can write equation of the lines perpedicular to each other in this form: ax+by=0 -bx+ay=0 this is a hint....:)

  4. shahzadjalbani
    • 3 years ago
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    Can you prove it through trigonometry?

  5. shahzadjalbani
    • 3 years ago
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    @myko @shirleyx Can you prove it through trigonometry?

  6. experimentX
    • 3 years ago
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    slope = \( \tan(\theta) \) another slope = \( \tan(\theta - 90) = -\cot \theta \)

  7. myko
    • 3 years ago
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    \[\cos \alpha x+\sin \alpha y =0\] \[-\sin \alpha x + \cos \alpha y =0\]

  8. myko
    • 3 years ago
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    grad f1 = (cosa -sinax,sina+cosay) grad f2 = (-sina-cosax,cosa-sinay)

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