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shahzadjalbani
Group Title
Is there any equation to calculate the prime numbers?
 2 years ago
 2 years ago
shahzadjalbani Group Title
Is there any equation to calculate the prime numbers?
 2 years ago
 2 years ago

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lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
do you mean a formula to verify if it is prime?
 2 years ago

shahzadjalbani Group TitleBest ResponseYou've already chosen the best response.0
Yes.....
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
There are a lot of methods for finding prime numbers, but it's not that easy, there's no function to check if any number is prime without having a list of prime numbers to use
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
Sieve of Eratosthenes is a good place to start if you want to research this area
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i can come up with a formula impromptu....o.O
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
but yeah...there isnt any im familiar of
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Easiest way: check if it's divisible by any natural number or not :P
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
Trust me the number theorists would love if there was an easy formula to verify primality :P
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
So far, there isn't. If there was the Reimann Hypothesis wouldn't be as big of a deal as it is.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I see something interesting. http://en.wikipedia.org/wiki/Lucas%E2%80%93Lehmer_primality_test
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
here is a list of *some* prime numbers if itll help: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
Yeah parth that is for Mersenne primes only, though
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
^ spam. It didnt help
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
are you good now @shahzadjalbani ?
 2 years ago

shahzadjalbani Group TitleBest ResponseYou've already chosen the best response.0
@lgbasallote You sent a list of numbers now I have to compare each number with this list it will more difficult and lengthy job . Is there any simple way to do it .
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
There is not a simple way with the primes. The primes are not simple. That's why people are still studying them :)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
my way is bloodily and manually divide a number by the simplest prime numbers (2, 3, 5, 7, 11) if i get a quotient with no remainder it is not prime....if there is a remainder...i have no way f knowing so i give up and say true lol
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i have no way of knowing because the number could be divisible by the succeeding prime numbers or it could be just prime
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
One important method when determining if a number is prime is to bound the potential divisors by the square root of the number you're investigating. Once you hit that bound, you know it's prime.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
but normally...if the number is not divisible by the basic prime numbers then it is prime...teachers are not that sadistic to have you try each one
 2 years ago

shahzadjalbani Group TitleBest ResponseYou've already chosen the best response.0
@nbouscal explain your statement.
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
Well, any integer divisors come in pairs, right? So if you're looking at the number 20, for example, you have pairs 1,20; 2, 10; 4, 5... then you have 5,4; 10,2; 20,1... but you already had those, just backwards. So if you're checking primes, and you check 1, 2, 4... you don't need to check any more numbers past that because you already would have found it in those first pairs. Once you hit the square root of the number, you know you don't have to check anymore.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
or just divide by the primes
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
So for example you want to check if 51 is prime, and you know that sqrt(51) is just a bit over 7, you only have to check if 51 is divisible by 2, 3, 5, 7. You don't need to go any further than that.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
20/2 wields a quotient with no remainder so it is automatically not prime
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
Obviously 20 isn't prime, lgba, that was not the point of the example.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i was giving an eample too...of my method
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
The point was to show why you don't need to worry about primes greater than the square root, because you would already have run into them before you got to the square root.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
makes sense...
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
The square root bound is very useful when you are using computer methods to check primality on large numbers, it saves a lot of time.
 2 years ago
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