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shahzadjalbani
 3 years ago
Describe Irrational functions and explain how to calculate asymptotes.
shahzadjalbani
 3 years ago
Describe Irrational functions and explain how to calculate asymptotes.

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lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1fianlly....now i can answer

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1you can calculate for vertical asymptote by equating y to infinity and solving for x...usually this happens in rational expressions only

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1rational expressions/functions are expressions/functions with a variable in the denominator

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1so vertical asymptotes will happen when there is an x in the denominator...im thinking horizontal asymptotes will happen when there is a y in the denominator

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1would you like an example?

shahzadjalbani
 3 years ago
Best ResponseYou've already chosen the best response.0Yes ................

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1i'll give a simple one y = 1/x you'll notice that if x = 0 then y would be undefined..you have discussed that right?

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1i mean that 1/0 is undefined..you know that right?

shahzadjalbani
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks @lgbasallote now I am going for the Lunch BRB after lunch.

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1well i have to go as well ^_^ but i assume you know the rest

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1from my example x = 0 (a.k.a. the yaxis) is the vertical asymptote

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.1horizontal asymptotes will appear in 1/y = x just do the same process
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