In a quadrilateral ABCD, the diagonals bisect each other at point T.
Based on the given information, which statement is presented first to show that side AB is equal to side BC?
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Angle ATB is congruent to Angle CTB.
Angle ADT is congruent to Angle ATB.
Side AB is equal to the diagonal DB of the quadrilateral.
Side BC is equal to the diagonal AC of the quadrilateral.
Hmm, what do you mean? lol
Seems like a square. So all the angles are 90 degrees?
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Any chance it's A?
I am thinking A as well, although I'm just reading the question again because it feels like A is the only logical answer. lol
Well, AB = BC could also be a rhombus or a kite.
mm well let me know if you change your mind :)
The first choice works, because the sides bisect each other and then we can show that the right triangles are congruent, thus the corresponding parts are congruent.
The second choice, if those two were the same angle, then there'd be an issue with point D being on top of T (like, it'd be the exact same angle)
The last two don't really help us prove anything unless we introduce more information.