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ThisShouldFeelLikeFire

  • 3 years ago

How exactly do I solve this equation? x2 - 12x = -36

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  1. kevsturge
    • 3 years ago
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    \[x^2-12x+36=0\] now solve the quadratic

  2. kevsturge
    • 3 years ago
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    gives x=6 can yuo see why

  3. precal
    • 3 years ago
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    you can use the quadratic formula or you can factor it you can also, look at its graph and see where it crosses the x axis

  4. kevsturge
    • 3 years ago
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    here yuo can factor the eqn, Do you know how to do this?

  5. ThisShouldFeelLikeFire
    • 3 years ago
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    I don't understand how you got x = 6...

  6. precal
    • 3 years ago
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    |dw:1338677027789:dw|

  7. precal
    • 3 years ago
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    |dw:1338677062779:dw|

  8. ThisShouldFeelLikeFire
    • 3 years ago
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    I'm sorry... I'm so confused. /:

  9. ThisShouldFeelLikeFire
    • 3 years ago
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    Oh! Wait I think I get it!!

  10. ThisShouldFeelLikeFire
    • 3 years ago
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    Took me a little bit :P Thank you both a ton!!

  11. kevsturge
    • 3 years ago
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    if you factorise the equation you get (x-6)(x-6) so when (x-6)=0 x=6 Do you see

  12. kevsturge
    • 3 years ago
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    Here is how I practice factorising write the factorised end point i.e. (x+3)x+4) and expand the brackets to give\[x^2+4x+3x+12 \rightarrow x^2+7x+12\] now |I take \[x^2+7x+12\] and work backwards because I know it will definitely factorise

  13. precal
    • 3 years ago
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    |dw:1338678477379:dw|

  14. precal
    • 3 years ago
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    |dw:1338678551861:dw|

  15. kevsturge
    • 3 years ago
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    wow that's the hard way! but it does always work. Try to factorise it before going through all this stress

  16. precal
    • 3 years ago
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    just presenting multiple ways to solve it. Quadratic formula works 100% of the time, factoring does not

  17. kevsturge
    • 3 years ago
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    that's what I said :P

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